What word describes the position in the moon's elliptical orbit when it is closest to Earth?

Answers

Answer 1
Answer: That's the moon's perigee.

Related Questions

1. Can someone help me with this? :) Which object is made of frozen gas, ice, and dust that orbits in the outermost reaches of the solar system?1) planet2) moon3) Kuiper Belt object 4) meteor2. Which explanation of the solar system best fits the observations of the planets and how they orbit the sun?1) A comet hit the sun and sent off fragments that became the planets.2) The gravity of a large, massive star passing the sun ripped off blobs of material from it that formed the planets.3) The planets formed at the center of a collapsing spinning cloud of gas and dust.4) The sun and planets formed from a collapsing spinning cloud of gas and dust.
The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration
What causes light to bend when it moves from one transparent medium to another?a change in amplitude a change in color a change in frequency a change in speed
What happens as a result of an increase in the intensity of a sound wave? -the frequency of a soundwave increases. -the velocity of the sound wave decreases. -the energy of the soundwave increases. -the amplitude of the soundwave decreases
Two objects are dropped from rest from the same height. Object A falls through a distance during a time t, and object B falls through a distance during a time 2t. If air resistance is negligible, what is the relationship between A and B?

What is aphysical
property of
snowflakes?
A. They are a solid.
B. They are a gas.
C. They are plasma
D. They are a liquid,

Answers

Answer:

A. They are a solid.

Explanation:

Hope this helps. . .

uwu

Assume that you have a mass of 50.0kg and earth has a mass of 5.97x10kg.The radius of earth is 6.38x10m.What is the force of gravitational attraction between you and the earth

Answers

The formula for force of attraction between any two bodies in the universe
F  =  GMm / r^2.      (Newton's Universal law of Gravitation).

G = Universal gravitational constant, G = 6.67 * 10 ^ -11  Nm^2 / kg^2.
M = Mass of first object. = 5.97 x 10^24 kg.
m = mass of second object = 50 kg.
r = distance apart, between centers = in this case it is the radius of the earth
   = 6.38 x 10^6 m.
( Sorry I could not assume with the values you gave).
(Actually the force of attraction between an object on the Earth and the Earth is the weight of the object our answer should be around 500N which is from mg = 50 *10 = 500)

So F = ((6.67 * 10 ^ -11)*(5.97 x 10^24)*(50)) / (6.38 x 10^6)^2.
  Punch it all up in your calculator.
F = 489. 135 N.

Remember we said it would be around 500.
So that's our answer.
F = 489. 135 N.    Hurray!!


Final answer:

The force of gravitational attraction between you (of mass 50kg) and the Earth (of mass 5.97x10^24 kg) can be calculated using Newton's Universal Law of Gravitation. Substituting the respective values in the formula, the calculated force is approximately 490.5 N.

Explanation:

The force of gravitational attraction between you and the earth can be calculated using Newton's Universal Law of Gravitation. This law states that the force (F) between two masses (m1 and m2) separated by a distance (r) is given by the formula F = G*(m1*m2/r^2), where G is the gravitational constant and is approximately 6.67x10^-11 N*(m^2/kg^2).

In this case, your mass (m1) is 50 kg, Earth's mass (m2) is 5.97x10^24 kg and the radius of Earth (r) is 6.38x10^6 m. Substituting these values into the formula, we can find the force of gravitational attraction between you and the Earth.

F = (6.67x10^-11 N*(m^2/kg^2)) * ((50 kg) * (5.97x10^24 kg)) / (6.38x10^6 m)^2. After calculating the above equation, you find that F ≈ 490.5 N.

Learn more about Gravitational Force here:

brainly.com/question/18961003

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A ball of clay sinks when placed in water. The same piece of clay floats if it is made into the shape of a boat.Why does the clay float when made into the shape of a boat?
a. The clay is less dense when stretched into the shape of a boat.
b. The buoyant force is greater on the clay when it has a spherical shape.
c. The boat shape displaces a greater volume of water than the ball shape.
d. The weight of the clay boat is less than the weight of the clay ball.

Answers

The correct answer is definitely d. The weight of the clay boat is less than the weight of the clay ball.
In such situations, the point that we should take as a basis to resolve a question is weight. If the weight of clay is less than that of a clay ball, the clay will float.

Answer:

c. The boat shape displaces a greater volume of water than the ball shape.

Explanation:

If an object is not accelerating what can you determine about the sum of all the forces on the object

Answers

If object is not accelerating, the sum of all forces on the object will be equal to ZERO...

A student kicks a football vertically upwards, causing the football to reach a maximum height of 40.0m before falling back to the ground. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the football.A) With what speed was the football kicked?
B) What was the football's total flight time?

Answers

Answer:

A. 28 m/s

B. 5.72 s

Explanation:

The following data were obtained from the question:

Maximum height (h) = 40 m

Acceleration due to gravity (g) = 9.8 m/s²

A. Determination of the initial velocity.

Maximum height (h) = 40 m

Acceleration due to gravity (g) = 9.8 m/s²

Velocity at maximum height (v) = 0 m/s

Initial velocity (u) =.?

v² = u² – 2gh (Ball is going against gravity)

0² = u² – (2 × 9.8 × 40)

0 = u² – 784

Collect like terms

0 + 784 = u²

784 = u²

Take the square root of both side

u = √784

u = 28 m/s

Thus, the ball was kicked with a velocity of 28 m/s

B. Determination of the time of flight.

We'll begin by calculating the time taken to reach the maximum height. This can be obtained as follow:

Velocity at maximum height (v) = 0 m/s

Initial velocity (u) = 28 m/s

Time taken to reach the maximum height (t) =?

v = u – gt (Ball is going against gravity)

0 = 28 – 9.8t

Rearrange

0 + 9.8t = 28

9.8t = 28

Divide both side by 9.8

t = 28/9.8

t = 2.86 s

Finally, we shall determine the the time of flight as follow:

Time taken to reach the maximum height (t) = 2.86 s

Time of flight (T) =?

T = 2t

T = 2 × 2.86

T = 5.72 s

Therefore, the time of flight for the ball is 5.72 s

An object is dropped from a height of 25 meters. At what velocity will it hit the ground?

Answers

You can use Vf^2-Vi^2 = 2ax

Vf^2 - 0 = 2(9.81)(25)

Or you can use energy

mgh = 1/2mv^2

2gh =v^2

Same thing