MATHEMATICS HIGH SCHOOL

Someone help me PLZZ

Answers

Answer 1

Answer:

Answer:

5/3

Step-by-step explanation:

The slope is the coefficient next to the x. Therefore, the slope is 5/3.

Answer 2

Answer:

Answer:

m= 5/3

Step-by-step explanation:

Math wizzz

Worked it out

And online calculator verified!

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Add −3 1/6+53/4 I need help

Answers

Answer: 8 11/12

Step-by-step explanation:

3 1/6+ 5 3/4

19/6+ 23/4

38/12+69/12

107/12

8 11/12

To solve this problem, you must understand what is the Common Denominator Rule:

The Common Denominator rule is when you use the common factors of the denominators to make them the same number. This will allow you to add and subtract fractions.

First, let’s put these two mixed fractions as improper fractions. Learn more about making that conversion here: brainly.com/question/35061276

$(23)/(4)$

$(-19)/(6)$

Now that you have your fractions, look at the denominators: 6 and 4.

A common factor between 4 and 6 is the number 12. Multiply the denominators and numerators of each fraction by the number that will turn the denominator into 12:

$((23)(3))/((4)(3))$ = $(69)/(12)$

$((-19)(2))/((6)(2))$ = $(-38)/(12)$

Now that both factions have the same number in the denominator, you can add them together!

*be aware of the negative sign*

Your answer should be: $(31)/(12)$

What is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?

Answers

Perimeter = 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8

What’s is the product of 1/4 times (5.6)

Answers

Answer:

1.4

Step-by-step explanation:

1/4 x 5.6 = 1.4

14/10 = 1 4/10 = 1 2/5

Solve for x and y in the following set of equation 6x+5xy-5y=8
X+y=3

Please help this is important

Answers

STEP 1:

$6x+5xy-5y=8\n \n 6x+5y\left( x-1 \right) =8\n \n 5y\left( x-1 \right) =8-6x\n \n 5y\left( x-1 \right) =2\left( 4-3x \right) \n \n \frac { 1 }{ 5\left( x-1 \right) } \cdot 5y\left( x-1 \right) =2\left( 4-3x \right) \cdot \frac { 1 }{ 5\left( x-1 \right) } \n \n y=\frac { 2\left( 4-3x \right) }{ 5\left( x-1 \right) }$

STEP 2:

$x+y=3\n \n y=3-x$

STEP 3:

This means that...

$3-x=\frac { 2\left( 4-3x \right) }{ 5\left( x-1 \right) } \n \n \left\{ 5\left( x-1 \right) \right\} \left( 3-x \right) =2\left( 4-3x \right) \n \n \left( 5x-5 \right) \left( 3-x \right) =8-6x\n \n 15x-5{ x }^( 2 )-15+5x=8-6x\n \n 20x-5{ x }^( 2 )-15=8-6x\n \n 5{ x }^( 2 )+8-6x+15-20x=0\n \n 5{ x }^( 2 )-26x+23=0$

STEP 4:

Which means that...

$\n \frac { 1 }{ 5 } \cdot \left( 5{ x }^( 2 )-26x+23 \right) =0\cdot \frac { 1 }{ 5 } \n \n { x }^( 2 )-\frac { 26 }{ 5 } x+\frac { 23 }{ 5 } =0\n \n { x }^( 2 )-\frac { 26 }{ 5 } x=-\frac { 23 }{ 5 }$

Which means that...

$\ \n { \left( x-\frac { 13 }{ 5 } \right) }^( 2 )-{ \left( \frac { 13 }{ 5 } \right) }^( 2 )=-\frac { 23 }{ 5 } \n \n { \left( x-\frac { 13 }{ 5 } \right) }^( 2 )-\frac { 169 }{ 25 } =-\frac { 23 }{ 5 } \n \n { \left( x-\frac { 13 }{ 5 } \right) }^( 2 )=-\frac { 115 }{ 25 } +\frac { 169 }{ 25 } \n \n { \left( x-\frac { 13 }{ 5 } \right) }^( 2 )=\frac { 54 }{ 25 }$

Which means that...

$\n \n x-\frac { 13 }{ 5 } =\pm \frac { \sqrt { 54 } }{ 5 } =\pm \frac { 3\sqrt { 6 } }{ 5 } \n \n \therefore \quad x=\frac { 13 }{ 5 } \pm \frac { 3\sqrt { 6 } }{ 5 }$

STEP 5:

When:

$x=\frac { 13 }{ 5 } +\frac { 3\sqrt { 6 } }{ 5 }$

.........

$y=3-\left( \frac { 13 }{ 5 } +\frac { 3\sqrt { 6 } }{ 5 } \right) \n \n y=\frac { 15 }{ 5 } -\frac { 13 }{ 5 } -\frac { 3\sqrt { 6 } }{ 5 } \n \n y=\frac { 15-13-3\sqrt { 6 } }{ 5 } \n \n y=\frac { 2-3\sqrt { 6 } }{ 5 }$

STEP 6:

When :

$x=\frac { 13 }{ 5 } -\frac { 3\sqrt { 6 } }{ 5 }$

...........

$y=3-\left( \frac { 13 }{ 5 } -\frac { 3\sqrt { 6 } }{ 5 } \right) \n \n y=\frac { 15 }{ 5 } -\frac { 13 }{ 5 } +\frac { 3\sqrt { 6 } }{ 5 } \n \n y=\frac { 15-13+3\sqrt { 6 } }{ 5 } \n \n y=\frac { 2+3\sqrt { 6 } }{ 5 }$

Please factor this and find the domain and show work

6c-3/3c^2-12

Answers

$(6c - 3)/(3c^(2) - 12) = (3(2c) - 3(1))/(3(c^(2)) - 3(4)) = (3(2c - 1))/(3(c^(2) - 4)) = (2c - 1)/(c^(2) - 4) = (2c - 1)/(c^(2) + 2c - 2c - 4) = (2c - 1)/(c(c) + c(2) - 2(c) - 2(2)) = (2c - 1)/(c(c + 2) - 2(c + 2)) = (2c - 1)/((c - 2)(c + 2))$

Domain: ±2

The value of 3.6 - 2.4 ÷ (-0.8) is _____.
6.6
0.6
-1.5
3

Answers

I hope this helps you

Answer:

6.6

Step-by-step explanation: