In January 2010, Diana invested $4,500 in an account that paid interest compounded annually. the table showstopper balance of the account at different times. what was Diana's balance, in dollars and cents, in January 2014. the numbers on the table are, For the month Jan. 2011-$4,635.00Jan. 2012-$4,774.05
Jan. 2013-$4,917.27

Answers

Answer 1

Answer:

Final answer:

The question is related to compound interest. Diana's account balance in 2014 cannot be precisely calculated with the provided information, but based on the increasing balance trend, it would be larger than the 2013 balance of $4,917.27.

Explanation:

The subject of this question is compound interest, which is used in Mathematics. When Diana invested $4,500 in an account in 2010, the balance in the account increased each year due to the interest being compounded, or added to the principal amount. For example, by January 2011, the balance had grown to $4,635.00. The balance continued to grow each subsequent year.

To find Diana's balance in 2014, we would typically need to apply the formula for compound interest. However, in this case, the question only provides the balances for the years up to 2013. If a similar growth pattern continued, we could expect that the balance in 2014 would be larger than the $4,917.27 balance of 2013. Without a specific interest rate or an exact balance for 2014, we cannot precisely calculate the 2014 balance.

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Answer 2

Answer:

Answer:

500,000

Step-by-step explanation:

80-1

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Aiden has a rectangle that is 8 centimeters long by 4 centimeters wide. He wants to divide the rectangle into squares with 1/2 centimeter side lengths. Will Aiden’s plan result in at least 200 squares?

Answers

Answer:

128 squares

Step-by-step explanation:

If the rectangle is 8cm long by 4cm wide, the area is:

$A=8*4cm^2=32cm^2$

The squares have 1/2=0.5cm side length, hence the area of the squares is:

$A'=(0.5)cm^2=0.25cm^2$

By dividing A between A' you can obtain the number of squares:

$n=(A)/(A')=(32cm^2)/(0.25cm^2)=128$

hence, the number of sqares that Aiden is able to produce is 128

Answer:

No, Aiden's plan will be a maximum of 128 squares

Step-by-step explanation:

We have a rectangle with 8 cm long by 4 cm wide, that is to say

8*4 = 32 squares, but you want to divide the rectangle into 1/2 cm squares, therefore

$(8)/((1)/(2))*(4)/((1)/(2))=(32)/((1)/(4))=32*4=128$

So Aiden's plan will have to be limited to max 128 squares

Csc theta * cos^2 theta +sin theta= csc theta

Answers

Step-by-step explanation:

$\csc \theta \cos^(2)\theta + \sin \theta = \csc \theta(1 - \sin^(2)\theta) + \sin \theta$

$= (\csc \theta - \sin \theta) + \sin \theta$

$= \csc \theta$

A farmer notes that in a field full of horses and chickens there are 35 heads and 98 feet. How many of each animal are there?

Answers

Answer:

There are 14 horses and 21 chickens.

Step-by-step explanation:

First, you have to make expression for horse and chicken. So we can let x be the number of horses and y will be the number of chickens. Next, given that the total number of feet for both animals is 98 so you have to make simultaneous equation :

$4x + 2y = 98$

(horse has 4 feet and chicken has 2 feet)

There are a total of 35 heads so the other equation will be :

$x + y = 35$

Lastly, you have to solve it :

$4x + 2y = 98$

$2(2x + y) = 98$

$2x + y = 49 - - - (1)$

$x + y = 35 - - - (2)$

$(1) - (2)$

$2x + y - x - y = 49 - 35$

$x = 14$

$substitute \: x = 14 \: into \: (2)$

$14 + y = 35$

$y = 35 - 14$

$y = 21$

Maurice says that 1079 divided by 62= 16 with a remainder of 87. Without seeing his work how can you tell that Maurice divided incorrectly

Answers

the remainder is bigger than what you're dividing with

Solve for x. Write both solutions, separated
by a comma.
5x2 + 2x - 7 = 0

Answers

Answer:

it equals 1

Step-by-step explanation:

(5)(2)+2x−7=5

Step 1: Simplify both sides of the equation.

(5)(2)+2x−7=5

10+2x+−7=5

(2x)+(10+−7)=5(Combine Like Terms)

2x+3=5

Step 2: Subtract 3 from both sides.

2x+3−3=5−3

2x=2

Step 3: Divide both sides by 2.

x=1

On each trial of an experiment, a subject is presented with a constant soft noise, which is interrupted at some unpredictable time by a noticeably louder sound. The time it takes for the subject to react to this louder sound is recorded. The following list contains the reaction times (in milliseconds) for the trials of this experiment: 296, 311, 202, 217, 231, 171, 241, 164, 257, 269, 175, 273, 285, 226, 261 Find 25th and 80th percentiles for these reaction times.

Answers

Answer:

25th percentile = 202

80th percentile = 285

Step-by-step explanation:

Rearranging the values in increasing order

164

171

175

202

217

226

231

241

257

261

269

273

285

296

311

N = total number of variables = 15.

25th percentile = [(N + 1)/4]th variable = (15 + 1)/4 = 4th variable.

So, the 25th percentile = 4th variable = 202.

80th percentile = 0.8(N + 1) th variable = 0.8 × (15 + 1) = 12.8th variable = 13th variable = 285

Final answer:

To find the 25th and 80th percentiles for the reaction times, sort the list and determine the corresponding values.

Explanation:

To find the 25th and 80th percentiles for the reaction times in this experiment, we need to first sort the list in ascending order:

The 25th percentile is the value that separates the lowest 25% of the data. In this case, it is the 4th value in the sorted list, which is 202 milliseconds. The 80th percentile is the value that separates the lowest 80% of the data. In this case, it is the 12th value in the sorted list, which is 273 milliseconds.

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