How many pairs of skis in stock does the shop have to have to make the probability in question 4 less than .01? Round your answer to a whole numbermean=150
Standard Deviation=20

Answers

Answer 1
Answer:

Answer:

159 hwqb Step-by-step explanation:2n3wq,brudj32nwqrdb3wndj32wsd


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Assume that, on average, healthy young adult’s dream 90 minutes each night, as inferred from a number of measures, including rapid eye movement (REM) sleep. An investigator wishes to determine whether drinking coffee just before going to sleep affects the amount of dream time. After drinking a standard amount of coffee, dream time is monitored for each of 28 healthy young adults in a random sample. Results show a sample mean, X, of 88 minutes and a sample standard deviation, s, of 9 minutes. (a) Use t to test the null hypothesis at the .05 level of significance (b) If appropriate (because the null hypothesis has been rejected), construct a 95 per-cent confidence interval and interpret this interval
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A set of data whose histogram is extremely skewed yields a sample mean and standard deviation of 69.5 and 10.75, respectively. What is the minimum percentage of observations that:A. are between 48 and 91.

and

B. are between 37.25 and 101.75

Answers

I am a beautiful person who can help you with the new one of those who are interested

PLZ HELP ME WITH MY PROJECTtell me 10 things that you like about distance learning and the 10 things that you dislike about distance learning.

Answers

Things I like about distance learning are:

  1. I get to sleep in a bit.
  2. My schedule is more flexible.
  3. I can work in different environments.
  4. I can have my pets with me while in class!
  5. Fewer group projects (I dislike most group projects as I do most of the work)
  6. I have more resources.
  7. I can ask my parents and siblings for help if needed.
  8. Fewer distractions.
  9. I can stay in comfy clothes all day.
  10. Fewer restrictions/ more freedom.

Things I dislike about distance learning:

  1. I don't get to see my friends every day.
  2. I get more headaches since I'm in front of a screen all day.
  3. It's harder to be motivated.
  4. It's easier to get behind on assignments.
  5. I don't get to meet new people (In-person ofc)
  6. It's harder to do classes like gym or art with online learning.
  7. Online school can be difficult if you have technology issues.
  8. I don't get to see my teachers.
  9. I can't do school sports and school-related activities.
  10. I'm an extrovert so I can't socialize.

Hope this helps! Good luck on your project! :)

Which equation represents the polar form of x2 + (y + 4)2 = 16?

Answers

The polar form of equation is r = -8sinθ.

What is polar form of complex number?

The combination of the complex number's modulus r and argument  is how complex numbers are shown in polar form z = r cosθ + i r sinθ = r (cosθ + i sinθ), is the polar form of a complex number with coordinates (x, y). In the coordinate system, polar coordinates of real and imaginary numbers are used to represent the polar form.

Given x² + (y + 4)² = 16

here The following is the relationship between (r, θ) and (x, y) if they are in Cartesian form:

x = rcosθ, y = rsinθ and r² = x² + y² ad tanθ = y/x

x² + (y + 4)² = 16

x² + y² + 16 + 8y = 16

x² + y² + 8y = 0

r² + 8rsinθ = 0

r(r + 8sinθ) = 0

r =0 and r = -8sinθ

Hence the polar form of equation is  r = -8sinθ.

Learn more about polar form of complex number;

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Answer:

c. r=-8sin(theta)

Step-by-step explanation:

edge 2021

Suppose you wanted to estimate the difference between two population means correct to within 4.8 at the 92% confidence level. If prior information suggests that both population variances are approximately equal to 12 and you want to select independent random samples of equal size from the populations, how large should the sample sizes be?Critical Value: 1.75
The sample sizes should be: n1=___n2=_____?

Answers

Answer: n_1=n_2=4

Step-by-step explanation:

Given : Margin of error : E= 4.8

Confidence level : 92%

Significance level : 1-0.92=0.08

\sigma_1^2=\sigma_1^2\approx12

Two-tailed critical value :-

z_(\alpha/2)=z_(0.08/2)=z_(0.04)=1.75

If we want to select independent random samples of equal size from the populations,

Formula for the sample size :

n_1=n_2=((z_(\alpha/2))/(E))^2(\sigma_1^2+\sigma_2^2)

Then buy using given values , we have

n_1=n_2=((1.75)/(4.8))^2(12+12)

Simplify ,

n_1=n_2=((1.75)/(4.8))^2(12+12)=3.190\approx4  [Round to the next integer.]

Hence, the The sample sizes should be: n_1=n_2=4

The circumference of a circle is 28 in.What is the diameter of the circle?

Responses


28 over pi, in.


14 over pi, in.


square root of 28 over pi end root, in.

14π−−√ in.



I think it is 28/pi but I would like to make sure

Answers

The diameter οf the circle is 28/π inches οr apprοximately 8.89 inches (rοunded tο twο decimal places).

The fοrmula fοr the circumference (C) οf a circle is given by:

C = 2πr

where r is the radius οf the circle.

If the circumference οf the circle is 28 inches, we can sοlve fοr the radius by dividing bοth sides οf the equatiοn by 2π:

C/2π = r

Substituting the given value οf C = 28, we get:

r = 28/2π

r = 14/π

Finally, tο find the diameter (d) οf the circle, we multiply the radius by 2:

d = 2r

Substituting the value οf r = 14/π, we get:

d = 2(14/π) = 28/π

Therefοre, the diameter οf the circle is 28/π inches οr apprοximately 8.89 inches (rοunded tο twο decimal places).

Learn more about  diameter

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Patients come into a medical clinic have a mean weight of 207.6 pounds with a standard deviation of 22.6 pounds. the distribution of weight is not assumed to be symmetric. between what two ways does Chebyshev's Theorem guarantee that we will find at least 95% of the patients? Round your answers to the nearest 10th

Answers

I know the answer it is 98.2

Answer: 105.9 lbs and 309.3 lbs

Step-by-step explanation:

By Chebyshev's Theorem, the proportion of patients with weights within 4.5 standard deviations of the mean is at least 95%.  Therefore k=4.5.

The weight that is 4.5 standard deviations less than the mean is 207.6−4.5(22.6)=105.9 pounds.

The weight that is 4.5 standard deviations greater than the mean is 207.6+4.5(22.6)=309.3 pounds.

So at least 95% of the patients have weights between 105.9 and 309.3 pounds.