20 Points!!! Math Question

Answers

Answer 1

Answer:

Here is how to do the question,

The Remainder Theorem starts with an unnamed polynomial p(x), where "p(x)" just means "some polynomial p whose variable is x". ... If you get a remainder, you do the multiplication and then add the remainder back in. For instance, since 13 ÷ 5 = 2 R 3, then 13 = 5 × 2 + 3. This process works the same way with polynomials.

Hope that helps!!!!

Answer 2

Answer:

Answer:

Remainder Theorem starts with an unnamed polynomial p(x), where p(x) just means "some polynomial p whose variable is x". ... If you get a remainder, you do the multiplication and then add the remainder back in, For instance, since 13 ÷ 5 = 2 R 3, then 13 = 5 × 2 + 3. This process works the same way with polynomials

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Two bicyclists leave the center of town at the same time. One heads due north and the other heads due west. Later, the two cyclists are exactly 25 mi apart. The cyclist headed north has traveled 5 mi farther than the cyclist going west.How far has the cyclist going west traveled?

Answers

Answer:

Distance traveled by bicyclist traveling west = 15 miles

Step-by-step explanation:

These two cyclists travel at angle 90°

Relative displacement can be calculated using Pythagoras theorem.

Let d be the distance traveled by bicyclist traveling west

Distance traveled by bicyclist traveling north = d + 5

$25^2=d^2+(d+5)^2\n\nd^2+d^2+10d+25=625\n\n2d^2+5d-600=0\n\nd^2+5d-300=0\n\nd=(-5\pm √(5^2-4* 1* (-300)))/(2* 1)\n\nd=(-5\pm √(25+1200))/(2)\n\nd=(-5\pm √(1225))/(2)\n\nd=(-5\pm 35)/(2)\n\nd=15miles\texttt{ or }d=-20miles$

Negative displacement is not possible.

Hence d = 15 miles

Distance traveled by bicyclist traveling west = d = 15 miles

This situation is represented in annex.
From Pythagorean theorem you've got equation:
$x^2+(x+5)^2=25 \n \n \hbox{From formula} \ \ \ (a+b)^2 = a^2+2ab+b^2: \n \n x^2+x^2+10x+25=25 \n 2x^2+10x=0 \n \n \hbox{Factor out} \ \ 2x: \n 2x(x+5)=0 \n \n \hbox{So you've got:} \n \n x_1=0 \n x_2=-5$

There isn't any solutions where x>0, so this situation is IMPOSSIBLE.

Did you write correctly this question....?

What is the solution of the inequality 9 - x^2 < 0?(a) {x | -3 < x < 3}
(b) {x | x > 3 or x < -3}
(c) {x | x | x > 3}
(d) {x | x < -3}

please show how you got the answer. thank you!

Answers

9 - x² < 0
-9    -9 to remove 9 deduct it from both sides
- x² < -9
   ÷ -1 ÷-1 to remove the negative sign, divide both sides by -1
       x² < 9
   √x² < √9    to remove the exponent of 2, find the square root of both sides.
   x    < 3    Choice A.

To check:

9 - x² < 0
9 - 3²   < 0
9 - 9 < 0
0 < 0

$\9-x^2\ \textless \ 0\n3^2-x^2\ \textless \ 0\n(3-x)(3+x)\ \textless \ 0\n\{3-x\ \textless \ 0\ \ \wedge\ \ 3+x\ \textgreater \ 0\}\ \ \ \vee\ \ \ \{3-x\ \textgreater \ 0\ \ \wedge\ \ 3+x\ \textless \ 0\}\n\{-x\ \textless \ -3\ \ \wedge\ \ x\ \textgreater \ -3\}\ \ \ \ \ \ \vee\ \ \ \ \ \{-x\ \textgreater \ -3\ \ \wedge\ \ x\ \textless \ -3\}\n~\ \ \ \{x\ \textgreater \ 3\ \ \ \wedge\ \ \ x\ \textgreater \ -3\}\ \ \ \ \ \ \vee\ \ \ \ \ \ \{x\ \textless \ 3\ \ \ \ \wedge\ \ \ x\ \textless \ -3\}\n~\qquad \qquad \ \ x\ \textgreater \ 3\ \qquad \ \ \ \ \ \vee\ \ \ \ \ \qquad \ x\ \textless \ -3\$

The solution is (b) {x | x > 3 or x < -3}

Which of the following statements is true?10 x 7/2

The product will be less than 10.
The product will be greater than 10.
The product will be equal to 10.

Answers

the product would be greater cuz ur dividing 7 by 2 witch is 3.5 then multiplying that by 10 witch would be 35

Which statement describes the graph of the system of equations below?1.5x + 0.2y = 2.68

1.6x + 0.3y = 2.98

The lines are parallel.

The lines overlap at all points.

The lines intersect at (1.6,1.4).

The lines intersect at (3.1,0.5).

Answers

In order to see the behavior of the line formed from the equations, we write the given equation in general form which is y=mx+b

1.5x + 0.2y = 2.68 --> y= -7.5x + 13.4

1.6x + 0.3y = 2.98 --> y= -5.33x + 9.93

They definitely are not parallel lines and do not overlap at all points. Plotting the equations in a graph, an intersection is observed. This intersection most likely is the third option. The lines at (1.6, 1.4).

Answer

taskmasters

In order to see the behavior of the line formed from the equations, we write the given equation in general form which is y=mx+b

1.5x + 0.2y = 2.68 --> y= -7.5x + 13.4

1.6x + 0.3y = 2.98 --> y= -5.33x + 9.93

They definitely are not parallel lines and do not overlap at all p

The fraction 16/20 is written as 5/8 in simplest form.

True
False

Answers

4/5 if you simplify 16/20

YALL BETTER ANSWER THIS PLSSSSSSSSSSS

Answers

Answer:

= 3/16(0.1875)

Step-by-step explanation:

explanation in the image.

Answer:

Step-by-step explanation:

Take out lignes

-1/4x-3/7

= -7/12

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