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PLEASE HELP ASAP!!!!! - 1

Answers

Answer 1
Answer:

Answer:

MOSE

Explanation:


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Why is a 5 rupees coin attracted by a magnet? name the metal present in the coin​

Answers

Hey Mate

See a coin is attracted bcoz he it has a metal names iron Which is easily attracted by the magnets

Hope, you fell my answer Helpful ( ◜‿◝ )♡

The new metal in the coin is Ferritic Stainless Steel
The (old) metal in the coin is Cupro-Nickel

Different velocity-time graph lines are shown, displaying the behavior of multiple race carts along a linear track.Which description correctly identifies cart C?

A) Has a positive acceleration and is speeding up.
B) Moving with zero acceleration.
C) Moving at a constant acceleration.
D) Has a negative acceleration and is slowing down.

Answers

B) Moving with zero acceleration.

Explanation:

Acceleration is defined as the rate of change of the velocity per unit time:

a=(\Delta v)/(\Delta t)

In a velocity-time graph, this ratio corresponds to the slope of the curve. In fact:

\Delta v (change in velocity) corresponds to the increase in the y-axis

\Delta t (change in time) corresponds to the increase in the x-axis

So, acceleration corresponds to the slope of the curve in a velocity-time graph. For cart C, the slope is zero, therefore the acceleration is also zero.

Answer:

B) Moving with zero acceleration.

Explanation:

As we can see the graph for Cart C that its velocity is constant and not changing its magnitude as well as its sign

So here the magnitude and direction is constant so we can say that velocity will remain constant always.

Where we can define the acceleration as

a = (dv)/(dt)

so here if magnitude and direction both are constant so

a = 0

so we can say that acceleration of cart C is ZERO

so correct answer will be

B) Moving with zero acceleration.

Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is traveling in the same direction at 25 km/hr. Which of the following statements is true?A) The momentum before the collision is equal to the momentum after the collision.

B) The momentum before the collision is greater than the momentum after the collision.

C) The momentum before the collision is less than the momentum after the collision.

Answers

The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

It is given that velocity of car  A is given as 22 Km/hr

The car B has the velocity of 25 Km/hr.

Let the mass of two bodies are denoted as  m_(1) \ and\ m_(2)

Let the velocity of cars A and B are denoted as v_(1) \ and\ v_(2)

The momentum before collision is-

                                                  p_(i) =m_(1) v_(1) +m_(2) v_(2)

[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of  linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are v'_(1) \ and\ v'_(2)

Hence the final momentum of the system is-

                                                        p_(f) = m_(1) v'_(1) +m_(2) v'_(2)

As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e      

                              p_(i) =p_(f)

                               m_(1) v_(1) +m_(2)v_(2) =m_(1) v'_(1) +m_(2) v'_(2)

Hence the option A  is right.

A
This principle is known as the law of conservation of momentum.

What is saving energy?

Answers

Not using electricity
not using as much and being efficient with how you use it! 
hope this helps!

An emergency relief plane is dropping a care package from a plane to a group of medical personnel working for a relief agency in an African village. The package is designed to land in a small lake, inflate an attached raft upon impact, and finally resurface with the raft side down. The plane will be moving horizontally with a ground speed of 59.1 m/s. The package will be dropped a horizontal distance of 521 m from the intended target location. At what altitude above the pond must the plane be flying in order to successfully accomplish this feat?

Answers

Answer:

The altitude of the plane is 379.5 m.

Explanation:

Initial horizontal velocity, u = 59.1 m/s

Horizontal distance, d = 521 m

let the time taken by the packet to cover the distance is t.

Horizontal distance = horizontal velocity x time

521 = 59.1 x t

t = 8.8 s

let the vertical height is h .

Use second equation of motion in vertical direction.

h = u t  + 0.5 gt^2\n\nh = 0 + 4.9 * 8.8*8.8\n\nh= 379.5 m

Final answer:

The plane must be flying at an altitude of approximately 194.89 m above the pond.

Explanation:

To successfully drop the care package in the small lake, the plane must be flying at a certain altitude above the pond. We can use the horizontal distance and the ground speed of the plane to calculate the time it takes for the package to reach the target location. Then, using the time and the equation for free fall, we can find the altitude above the pond.

First, we calculate the time it takes for the package to reach the target location:

  1. Horizontal distance = 521 m
  2. Ground speed = 59.1 m/s
  3. Time = Horizontal distance / Ground speed = 521 m / 59.1 m/s = 8.81 s

Next, we use the equation for free fall to find the altitude above the pond:

  1. Acceleration due to gravity, g = 9.8 m/s^2 (assuming no air resistance)
  2. Time for free fall, t = 8.81 s
  3. Altitude above the pond = 0.5 * g * t^2 = 0.5 * 9.8 m/s^2 * (8.81 s)^2 = 194.89 m

Therefore, the plane must be flying at an altitude of approximately 194.89 m above the pond in order to successfully accomplish this feat.

Learn more about altitude above the pond here:

brainly.com/question/18722834

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What is the acceleration of a body revolving in a circle at uniform speed? The acceleration is zero. The acceleration is directed tangentially. The acceleration is directed toward the center. The acceleration is directed away from the center.

Answers

A body revolving in circle generally has tangential acceleration if the speed is changing. Since the speed is uniform here, the tangential acceleration is zero.

centripetal acceleration is directed towards the center and is given as

a = v²/r                    where a = centripetal acceleration , v = speed , r = radius

Since both speed and radius are constant here, the centripetal acceleration is constant and is always directed towards the center.

hence the correct choice is

The acceleration is directed toward the center.