2.23 round to the nearest tenth.

Answers

Answer 1

Answer: 2.2

since the third number isn’t equal to or above 5, it rounds down.

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Consider the parabola r(t)equalsleft angle at squared plus 1 comma t right angle, for minusinfinityless thantless thaninfinity, where a is a positive real number. Find all points on the parabola at which r and bold r prime are orthogonal.

The Williams are buying a house that costs $323,000 and can afford a 10% down payment. If the Williams want the lowest monthly payment, which loan option would you recommend?a. 15 year fixed, 5% down at a fixed rate of 5.5%
b. 30 year FHA, 3.5% down at a fixed rate of 6.25%
30 year fixed, 20% down at a fixed rate of 5.75%
d. 30 year fixed, 10% down at a fixed rate of 6%

Answers

Answer:

Step-by-step explanation:

30 year fixed, 10% down at a fixed rate of 6%

Answer:D

Step-by-step explanation:

Answers

The height of the water when poured into the empty wide cylinder is;

Option A; To the 7¹/₃ mark

Formula for volume of a cylinder is;

V = πr²h

where;

r is radius

h is height

We are told that water is poured into the wide cylinder up to the 4th mark. Thus, for the wide cylinder, h = 4. Thus;

V_wide = 4πR²

Similarly, we are told that water is poured into the narrow cylinder up to the 6th mark. Thus, for the narrow cylinder, h = 6. Thus;

V_narrow = 6πr²

Now, the volume of the water will be the same since it was the same quantity that was poured. Thus;

V_wide = V_narrow

4πR² = 6πr²

⇒ R²/r² = 6/4

simplifies to get; R²/r² = ³/₂

Now both cylinder were emptied and water poured rises to the 11th mark for the narrow cylinder. Thus;

πR²H = 11πr²

R²/r² = 11/H

Earlier, we saw that R²/r² = ³/₂. Thus;

11/H = ³/₂

H = 22/3

H = 7¹/₃

The complete question is;

Attached are the drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

A) To the 7¹/₃ mark

B)To the 8th mark

C) To the 7¹/₂mark

D)To the 9th mark

E) To the 11th mark

Read more at; brainly.com/question/16760517

Answer:

COMPLETE QUESTION:

To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark

e)To the 11th mark

ANSWER : Option D (To the 7 1/3 mark)

Step-by-step explanation:

First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e

Volume of cylinders

π x R² x 4 = πxr²x 6

R²/r² = 6/4

after both cylinder were emptied

π x R² x h = π x r² x 11

R²/r² = 6/4 = 11/h

h = (4 x 11) /6 = 22/3 = 7 1/3 mark

Therefore, the height of the water in the wide cylinder is 7 1/3

Suppose that the functions g and h are defined for all real numbers x as follows. gx = x − 3x
hx = 5x + 2
Write the expressions for (g - h)(x) and (g * h)(x) and evaluate (g + h)(−2).

Answers

Answer:

Step-by-step explanation:

Given the functions g(x) = x − 3x and h(x) = 5x + 2, we are to calculatae for the expression;

a) (g - h)(x) an (g * h)(x)

(g - h)(x) = g(x) - h(x)

(g - h)(x) = x − 3x -(5x+2)

(g-h)(x) = x-3x-5x-2

(g-h)(x) =-7x-2

b) (g * h)(x) = g(x) * h(x)

(g * h)(x) = (x − 3x)(5x+2)

(g * h)(x) = 5x²+2x-15x²-6x

(g * h)(x) = 5x²-15x²+2x-6x

(g * h)(x) = -10x²-4x

c) To get (g + h)(−2), we need to first calculate (g + h)(x) as shown;

(g + h)(x) an (g * h)(x)

(g + h)(x) = g(x) +h(x)

(g + h)(x) = x − 3x + (5x+2)

(g+h)(x) = x-3x+5x+2

(g+h)(x) =3x+2

Substituting x = -2 into the resulting function;

(g+h)(-2) = 3(-2)+2

(g+h)(-2) = -6+2

(g+h)(-2) = -4

Sin2x/1+cos2x=tanx
How do I prove this with the double angle law

Answers

$sin(2x) = 2 sin x cos x \n \n cos(2x) = cos^2 x - sin^2 x$
After Substituting:
$(2 sin x cos x)/(1+cos^2 x - sin^2 x)$
Use pythagorean thm:
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......................
$(2 sin x cos x)/(2cos^2 x) \n \n = (sinx )/(cos x) \n \n = tan x$

There are approximately 2.6 million deaths per year in country A. Express this quantity as deaths per minute.

Answers

In one year, there are 365 days
365x24=8760 hours
8760x60=525 600 minutes

Dividing 2.6 million to the last number (525 600), we find death per minute in this country, which gives us more than 4 deaths in a minute.

Take 2.7 million divided by the number of minutes in a year. 1 hour= 60 minutes 1 day= 24 hours So you take 24 hours × 60 minutes =1440 minutes 1 year= 365 per minute.

In the diagram below of circle 0, GO = 8 andmZGOJ= 60°.
G
8
60°
What is the area, in terms of A, of the shaded
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