27 students are learning to make balloon animals. There are 172 balloons to be shared equally among the studentsA. How many balloons are left over after sharing them equally.

B. if each student needs 7 balloons, how many more balloon are needed? Explain

Answers

Answer 1
Answer:

10 balloons are left over after sharing them equally and 17 more balloons are needed

  • Numbers of students learning to make balloon animal = 27
  • Total balloon to be shared equally among the students = 172

Further Explanation

First step:

To determine how many balloons each student gets = the total balloons to be shared equally among the students divided by the number of students learning to make balloon animal.

Therefore, we have:

= (172)/(27)

= 6.37  

= 6 balloons (each student get 6 balloons)  

Second step:

To get how many balloons will be used by the entire student, then we should multiply the number of balloon each student gets (6) and the numbers of students learning to make balloon animal (27)

Therefore, we have:

= 6 x 27  

= 162 (162 balloon will be used by the student)

To calculate the remaining balloons, then we have to subtract the total balloons to be shared equally by the students and the numbers of balloon to be used by the entire students

Therefore, we have:

= 172 – 162

= 10 balloons.

Thus, 10 balloons are left over after sharing them equally.

Part B:  

If each student needs 7 balloons, then 17 more balloons are needed.

Since we have 10 balloons left after sharing them equally, to determine how many more balloons are needed = total number of students learning to make balloon animal – the numbers of balloon left over after sharing them equally.

Therefore, we have:

= 27 – 10

= 17  balloons

Therefore, if each student needs 7 balloons, 17 more balloons are needed.

Another step:

Another way you could determine how many balloons are needed is to multiply the numbers of balloon each student needs and the total number of student learning to make balloons animals, and subtract the value you derived from the total balloon to be shared equally among the students.

Therefore, we have:

= 7 x 27

= 189 balloons

= 189 - 172

= 17 balloons.

LEARN MORE:

KEYWORDS:

  • balloon animals
  • 7 balloons
  • numbers
  • dividing
  • multiplying
  • students
Answer 2
Answer: A.) .4 of a balloon is left
To Check:
what I did was divide 172 by 27 and it is 6.37 rounded to ........6 is an equal number so I kept it and .4 will be left over after sharing equally.

B.) 17 more balloons are needs
To Check:
what I was multiply 27 by 7 because each student needs seven balloons and I got 189 after that I subtracted 172 from 189 (189-172=17)
to see how many more balloons are needed.

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Answers

Answer: 1 share of Exxon

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The word “stock” refers to a share of ownership in a particular company. Shares of Exxon are traded on an open market.

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Find the midpoint of A and B where A has coordinates (2,7)
and B has coordinates (6,3).

Answers

The midpoint of A and B where A has coordinates (2,7) and B has coordinates (6,3) is (4, 5)

If B(x, y) is the midpoint of the line segment AC with end points at A(x₁, y₁) and C(x₂, y₂), the coordinates of B is:

x = (x₁ + x₂)/2; y = (y₁ + y₂)/2

Let O(x, y) be the midpoint of A and B where A has coordinates (2,7) and B has coordinates (6,3). Hence:

x = (2 + 6)/2 = 4; y = (7 + 3)/2 = 5

Hence the midpoint of A and B is (4, 5)

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Given that the coordinates of the point A is (2,7) and the coordinates of the point B is (6,3)

We need to determine the midpoint of A and B

Midpoint of A and B:

The midpoint of A and B can be determined using the formula,

Midpoint =((x_1+x_2)/(2), (y_1+y_2)/(2))

Substituting the points (2,7) and (6,3) in the above formula, we get;

Midpoint =((2+6)/(2), (7+3)/(2))

Adding the numerator, we have;

Midpoint =((8)/(2), (10)/(2))

Dividing the terms, we get;

Midpoint =(4, 5)

Thus, the midpoint of the points A and B is (4,5)

Greatest common factor of 21, 35, 49

Answers

The greatest common factor of 21, 35, and 49 is 49, which is determined by the prime factorization.

To find the greatest common factor (GCF) of 21, 35, and 49, we can start by finding the prime factorization of each number.

Here are the prime factorizations of the given numbers:

  • 21 = 3 x 7
  • 35 = 5 x 7
  • 49 = 7 x 7

To find the GCF, we need to identify the common prime factors and multiply them together.

Here, the only common prime factor is 7, which appears twice in the prime factorization of 49.

Therefore, the GCF of 21, 35, and 49 is 7 x 7 = 49.

So, the greatest common factor of 21, 35, and 49 is 49.

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I think it is 7 because 7 x 3 = 21
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What's the whole number of 6/2

Answers

the whole number would be 3.
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Given p(x)=3x^5+2x^2-5, what is the value of the function at -5/3

Answers

Answer:

-(3080)/(81)

Step-by-step explanation:

The given function is:

p(x)=3x^(5)+2x^(2)-5

We have to find the value of the function at x = -5/3

In order to do this we need to replace every occurrence of x in the given function by -5/3. i.e.

p(-(5)/(3))=3(-(5)/(3))^(5)+2(-(5)/(3) )^(2)-5\n\n p(-(5)/(3))=3(-(3125)/(243) )+2((25)/(9) )-5\n\np(-(5)/(3))=-(3125)/(81)+(50)/(9)-5\n\n p(-(5)/(3))=-(3080)/(81)

Thus, the value of the function at x =-5/3 is -(3080)/(81)

What are the excluded values?

0 and 15

3 and -5

-3 and 5

Answers

Answer:

x=5    x = -3

Step-by-step explanation:

-7 / ( x^2 -2x -15)

Factor the denominator

-7

----

(x-5) ( x+3)

The excluded values are when the denominator is equal to zero

(x-5) (x+3) =0

x-5 =0   x+3=0

x=5    x = -3