MATHEMATICS COLLEGE

Product of 6 and 6r and the product of 8s and 4

Answers

Answer 1

Answer:

The product of the numbers are 36r and 32s.

What is product?

When we multiply two numbers the resultant is called their product.

Given that, what can be the products of 6 and 6r and 8s and 4

a) 6 and 6r =

We can write it as =

6 x 6 x r

now multiply the numeric parts,

36 x r

= 36r

Similarly,

b) 8s and 4 =

We can write it as,

8 x s x 4

= 8 x 4 x s

now multiply the numeric parts,

= 32 x s

= 32s

Hence, the products are 36r and 32s.

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Answer 2

Answer: Product tells us we’re going to multiply.

6 x 6r = 36r

8s x 4 = 32s

We don’t have a number value to substitute in for r or s, so we just leave those variables as they are.

LMK if you have questions

Related Questions

Determine which statements are true in the set of real numbers3. (Select all that apply.) (a) Two lines parallel to a third line are parallel. (b) Two lines perpendicular to a third line are parallel. (c) Two planes parallel to a third plane are parallel. (d) Two planes perpendicular to a third plane are parallel. (e) Two lines parallel to a plane are parallel. (f) Two lines perpendicular to a plane are parallel. (g) Two planes parallel to a line are parallel. (h) Two planes perpendicular to a line are parallel. (i) Two planes either intersect or are parallel. (j) Two lines either intersect or are parallel. (k) A plane and a line either intersect or are parallel. Incorrect: Your answer is incorrect.
A boat propeller spins 1044 times in 3 MINUTES. Find the rate in revolutions per SECOND.
According to a government study among adults in the 25- to 34-year age group, the mean amount spent per year on reading and entertainment is $1,999. Assume that the distribution of the amounts spent follows the normal distribution with a standard deviation of $574. (Round your z-score computation to 2 decimal places and final answers to 2 decimal places.) What percent of the adults spend more than $2,550 per year on reading and entertainment?
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The slope of the line below is -2. Use the coordinates of the labeled point tofind a point-slope equation of the line.

H=10 cm
r= 7cm
calculate the volume of the cylinder

Answers

Answer:

V = 1538.6 cm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2h where r is the radius and h is the height

V = pi (7)^2 10

V = 3.14 (49)10

V = 1538.6 cm^3

Answer:

≈ 1539.3804

Step-by-step explanation:

V= πr²h =π*7²*10

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 4 right angle0,−4 in the directions parallel to and normal to the plane that makes an angle of StartFraction pi Over 3 EndFraction π 3 with the positive x-axis. Show that the total force is the sum of the two component forces.

Answers

Answer:

$F_p = < - √(3) , -3 >\n\nF_o = < √(3) , -1 >$

Step-by-step explanation:

- A plane is oriented in a Cartesian coordinate system such that it makes an angle of ( π / 3 ) with the positive x - axis.

- A force ( F ) is directed along the y-axis as a vector < 0 , - 4 >

- We are to determine the the components of force ( F ) parallel and normal to the defined plane.

- We will denote two unit vectors: ( $u_p$ ) parallel to plane and ( $u_o$ ) orthogonal to the defined plane. We will define the two unit vectors in ( x - y ) plane as follows:

- The unit vector ( $u_p$ ) parallel to the defined plane makes an angle of ( 30° ) with the positive y-axis and an angle of ( π / 3 = 60° ) with the x-axis. We will find the projection of the vector onto the x and y axes as follows:

$u_o$ = < cos ( 60° ) , cos ( 30° ) >

$u_o = < (1)/(2) , (√(3) )/(2) >$

- Similarly, the unit vector ( $u_o$ ) orthogonal to plane makes an angle of ( π / 3 ) with the positive x - axis and angle of ( π / 6 ) with the y-axis in negative direction. We will find the projection of the vector onto the x and y axes as follows:

$u_p = < cos ( (\pi )/(6) ) , - cos ( (\pi )/(3) ) >\n\nu_p = < (√(3) )/(2) , -(1)/(2) >\n$

- To find the projection of force ( F ) along and normal to the plane we will apply the dot product formulation:

- The Force vector parallel to the plane ( $F_p$ ) would be:

$F_p = u_p(F . u_p)\n\nF_p = < (1)/(2) , (√(3) )/(2) > [ < 0 , - 4 > . < (1)/(2) , (√(3) )/(2) > ]\n\nF_p = < (1)/(2) , (√(3) )/(2) > [ -2√(3) ]\n\nF_p = < -√(3) , -3 >\n$

- Similarly, to find the projection of force ( $F_o$ ) normal to the plane we again employ the dot product formulation with normal unit vector ( $u_o$ ) as follows:

$F_o = u_o ( F . u_o )\n\nF_o = < (√(3) )/(2) , - (1)/(2) > [ < 0 , - 4 > . < (√(3) )/(2) , - (1)/(2) > ] \n\nF_o = < (√(3) )/(2) , - (1)/(2) > [ 2 ] \n\nF_o = < √(3) , - 1 >$

- To prove that the projected forces ( $F_o$ ) and ( $F_p$ ) are correct we will apply the vector summation of the two orthogonal vector which must equal to the original vector < 0 , - 4 >

$F = F_o + F_p\n\n< 0 , - 4 > = < √(3), -1 > + < -√(3), -3 > \n\n< 0 , - 4 > = < √(3) - √(3) , -1 - 3 > \n\n< 0 , - 4 > = < 0 , - 4 >$ .. proven

Mrs. Farquharson drove through a total of 36 intersections on her way home from work last week. At 4 of every 16 intersections, Mrs. Farquharson had to stop for a red light before she could drive through. At how many intersections did Mrs. Farquharson have to stop for a red light?

Answers

She had to stop at 9

A garden shop determines the demand function q = D(x) = 5x + 200 / 30x + 11 during early summer for tomato plants where q is the number of plants sold per day when the price is x dollars per plant.(a) Find the elasticity.
(b) Find the elasticity when x = 2.
(c) At $2 per plant, will a small increase in price cause the total revenue to increase or decrease?

Answers

Answer: a) $E(x)=(-5945)/((30x+11)(5x+200))$ , b) 0.7975, demand is inelastic, c) increase.

Step-by-step explanation:

Since we have given that

$D(x)=(5x+200)/(30+11)$

So, derivative w.r.t x would be

$D'(x)=(5(30x+11)-30(5x+200))/((30x+11)^2)\n\nD'(x)=(150x+55-150x-6000)/((30x+11)^2)\n\nD'(x)=(5945)/((30x+11)^2)$

As we know that

$E(x)=(-xD'(x))/(D(x))\n\n\nE(x)=((-(-)5945x)/((30x+11)^2))/((5x+200)/(30x+11))\n\n\nE(x)=(5945x)/((30x+11)(5x+200))$

(b) Find the elasticity when x = 2.

So, we put x = 2, we get that

$E(2)=(5945* 2)/((30(2)+11)((5(2)+200)))\n\nE(2)=(11890)/((60+11)(10+200))\n\nE(2)=(11890)/(71* 210)\n\nE(2)=(11890)/(14910)\n\nE(2)=0.7975$

Since, 0.7975 < 1, so the demand is inelastic.

The total revenue will also increase with increase in price.

As total revenue = $price* quantity$

Hence, a) $E(x)=(-5945)/((30x+11)(5x+200))$ , b) 0.7975, demand is inelastic, c) increase.

Final answer:

This problem involves the calculation of the elasticity of a demand function using the derivative of the function. The elasticity is then used to analyze the effect on the total revenue when the price changes. The elasticity at a specific point is calculated and used for further analysis.

Explanation:

For part (a), to find the elasticity of the demand function, we need to use the formula for the price elasticity of demand, which is E = (dQ/dX) * (X/Q). Here, dQ/dX is the derivative of the demand function concerning X. This needs to be calculated first. The value of E provides us with the measure of elasticity.

For part (b), when x = 2 we substitute this value into the formula for E to get the elasticity at x = 2.

For part (c), based on the concept of elasticity, if E > 1, the demand is said to be elastic and a price decrease will result in an increase in total revenue, and vice versa. If E < 1, the demand is said to be inelastic and a price decrease will result in a decrease in total revenue, and vice versa. So, after calculating E at x = 2, we can use it to determine the effect on total revenue.

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Hey can you please help me posted picture of question

Answers

To solve the problem shown in the figure above you must keep on mind the following information:

1. The figure shows a parabola whose vertex is (0,0).

2. The x² indicates that the red parabola shown in the figure is vertical

3. and the sign - indicates that the red parabola opens down.

Therefore, you can conclude that the red parabola has the equation f(x)=-x²

So, the answer is B.

If we observe the graph of F(x) and G(x), F(x) can be obtained by shifting the graph of G(x) 4 units down.

Shifting 4 units down means subtracting 4 from the function value.

So, G(x) = 4 - x²

Thus,

F(x) = G(x) - 4
F(x) = 4 - x² - 4 = - x²

Therefore, the correct answer is option B

The two key parts of regression equation involve the______ and the y'________ a. slope; axis
b. asymptote; axis
c. asymptote; intercept
d. slope; intercept

Answers

Answer:

d. slope; intercept

Step-by-step explanation:

A regression equation is represented in the form :

y = mx + c (linear regression)

Where y = predicted variable

m = slope of regression line

x = independent variable

c = intercept (where the regression line crosses the y axis).

For a multiple regression equation where there are more than one independent, then we have multiple slopes

y = c + m1x1 + m2x2 +...mnxn

Hence, the slope. And intercept are the two key part of a regression equation which enables us to make prediction and correlation about the dependent and independent variables.

Answer:

Step-by-step explanation:

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