Please help. Dont put a random answer plz.

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Answer 1

Answer:

Answer:

Explination:

Work:

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Hello I am needing help on this word problem please. I think it's 30 but I'm questioning myself

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Solution:

Since 5 pounds of meat will feed about 26 people.

Thus;

$\begin{gathered} (5)/(26)lb\text{ would feed 1 person} \n \n =0.1923 \end{gathered}$

If she is expecting 156 people, she should prepare;

$\begin{gathered} (0.1923*156)lb\text{ of meat} \n \n \approx30lb \end{gathered}$

ANSWER: 30lb

In AWXY, X = 700 cm, w = 710 cm and ZW=24°. Find all possible values of ZX, tothe nearest 10th of a degree.

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Answer:

{}

Step-by-step explanation:

H3lp pl34ssssssssssssssssssssssssss

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Answer:

Step-by-step explanation:

Use the given graph to determine the limit, if it exists. Find limit as x approaches three from the left of f of x. Please include an explanation in your answer, I don't really understand limits so I'll give brainliest to the best explanation.

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Answer:

$\displaystyle \lim_(x \to 3^-) f(x) = -1$

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_(x \to c^+) f(x)$
Left-Side Limit: $\displaystyle \lim_(x \to c^-) f(x)$

Graphical Limits

Step-by-step explanation:

As we approach 3 from the left according to the graph (follow the left graphed line), we see that we approach -1.

∴ $\displaystyle \lim_(x \to 3^-) f(x) = -1$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Please help I can’t find the answer for this question

Answers

Answer:

The first one

Step-by-step explanation:

Bc it the right awnswer

Evaluate the given integral by making an appropriate change of variables, where R is the region in the first quadrant bounded by the ellipse 64x2 + 81y2 = 1. $ L=\iint_{R} {\color{red}9} \sin ({\color{red}384} x^{2} + {\color{red}486} y^{2})\,dA $.

Answers

$\displaystyle\iint_R\sin(384x^2+486y^2)\,\mathrm dA$

Notice that Given that $R$ is an ellipse, consider a conversion to polar coordinates:

$\begin{cases}x(r,\theta)=\frac r8\cos\theta\ny(r,\theta)=\frac r9\sin\theta\end{cases}$

The Jacobian for this transformation is

$J=\begin{bmatrix}\frac18\cos\theta&-\frac r8\sin\theta\n\frac19\sin\theta&\frac r9\cos t\end{bmatrix}$

with determinant $\det J=\frac r{72}$

Then the integral in polar coordinates is

$\displaystyle\frac1{72}\int_0^(\pi/2)\int_0^1\sin(6r^2\cos^2t+6r^2\sin^2t)r\,\mathrm dr\,\mathrm d\theta=\int_0^(\pi/2)\int_0^1r\sin(6r^2)\,\mathrm dr\,\mathrm d\theta=\boxed{(\pi\sin^23)/(864)}$

where you can evaluate the remaining integral by substituting $s=6r^2$ and $\mathrm ds=12r\,\mathrm dr$ .

Final answer:

To evaluate the integral, we make a change of variables using the transformation x=u/8 and y=v/9 to transform the region into a unit circle. Then we convert the integral to polar coordinates and evaluate it.

Explanation:

To evaluate the given integral, we can make the appropriate change of variables by using the transformation x = u/8 and y = v/9. This will transform the region R into a unit circle. The determinant of the Jacobian of the transformation is 1/72, which we will use to change the differential area element from dA to du dv. Substituting the new variables and limits of integration, the integral becomes:

L = \iint_{R} 9 \sin (612 u^{2} + 768 v^{2}) \cdot (1/72) \,du \,dv

Next, we can convert the integral from Cartesian coordinates(u, v) to polar coordinates (r, \theta). The integral can be rewritten as:

L = \int_{0}^{2\pi} \int_{0}^{1} 9 \sin (612 r^{2} \cos^{2}(\theta) + 768 r^{2} \sin^{2}(\theta)) \cdot (1/72) \cdot r \,dr \,d\theta

We can then evaluate this integral to find the value of L.

Learn more about Evaluation of Integrals here:

brainly.com/question/32205191

#SPJ11

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Pls help im a get my but beat if i don't get my grades up. so plz help me