Mrs. Gregory, the golf course superintendent at a country club, plans to reseed the putting green of the first hole. The circular putting green has a diameter of 38 ft.What is the area of the putting green?

Use π=3.14. Round to the nearest tenth

When y = -6 and z = 5, the value of the expression y + z + 2 is 1.

To calculate the expression y + z + 2 when y = -6 and z = 5, you simply substitute these values into the expression and perform the arithmetic operations:

y + z + 2 = (-6) + (5) + 2

Now, perform the addition:

(-6) + (5) + 2 = -1 + 2 = 1

So, when y = -6 and z = 5, the value of the expression y + z + 2 is 1.

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Answer:

1

Step-by-step explanation:

y + z + 2

first you have to replace the variables with the numbers

This is your equation now.

-6 + 5 + 2

Now you just have to solve it.

-6 + 5 = -1+ 2 = 1

or

7 - 6 = 1

The quadratic value function is y = -x² - 4x + 16

Given data ,

Let the quadratic equation be represented as A

Now , the value of A is

Let the function passes through the given points. (-1,-11) (2,-26) (-3,-31)

And , using the point (-1,-11) , we get

-11 = a(-1)² + b(-1) + c

-11 = a - b + c

Using the point (2,-26) , we get

-26 = a(2)² + b(2) + c

-26 = 4a + 2b + c

Using the point (-3,-31) , we get

-31 = a(-3)² + b(-3) + c

-31 = 9a - 3b + c

And , the three set of equations are

-11 = a - b + c

-26 = 4a + 2b + c

-31 = 9a - 3b + c

From the first equation, we can solve for c:

c = 11 - a + b

Substituting this expression for c into the other two equations, we get:

-26 = 4a + 2b + 11 - a + b

-31 = 9a - 3b + 11 - a + b

Simplifying these equations, we get:

-15 = 3a + 3b

-21 = 8a - 2b

Solving the first equation for b in terms of a, we get:

b = -5 - a

Substituting this expression for b into the second equation, we get:

-21 = 8a - 2(-5 - a)

Simplifying and solving for a, we get:

a = -1

Substituting this value of a into the equation for b that we found earlier, we get:

b = -5 - (-1) = -4

Finally, substituting these values of a and b into the equation for c that we found earlier, we get:

c = 11 - (-1) - (-4) = 16

Hence , the quadratic function that passes through the given points is given by y = -x² - 4x + 16

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Answer:

1 . EF is a secant of OX

2. DF is a chord of OX.

3. AABC is made of tangents to OX

4. ∠DEF is an inscribed angle of OX.

Step-by-step explanation:

Secant is line which intersects a circle from two distant points. Locus is a set of points which is same distance from the center of a circle. Chord is a straight line whose end points lie on circular arc of a circle. Tangent is a line which touches the circle at one point only.