What is bigger 11/14 or 3/4?

Answers

Answer 1
Answer: Step 1: Reduce (simplify) entered fractions to lowest terms, if the case:
Fraction: 3 / 4 it's already reduced to lowest terms
Fraction: 11 / 14 it's already reduced to lowest terms

Step 2: Calculate LCM (lowest common multiple) of the reduced fractions' denominators, it will be the common denominator of the compared fractions:
Denominator 4, factored = 22
Denominator 14, factored = 2 * 7
LCM (4, 14) = 22 * 7 = 28

Step 3: Calculate each fraction's expanding number (LCM divided by each fraction's denominator):
For fraction: 3 / 4 is 28 : 4 = (22 * 7) : 4 = 7
For fraction: 11 / 14 is 28 : 14 = (22 * 7) : 14 = 2

Step 4: Expand fractions to bring them to the common denominator (LCM):
3 / 4 = (7 * 3) / (7 * 4) = 21 / 28
11 / 14 = (2 * 11) / (2 * 14) = 22 / 28

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Andrew’s rotation maps point M(9, –1) to M’(–9, 1). Which describes the rotation?
Can you help me solve this question please?
An accurate answer would be appreciated. please and thank you
Which one is greater 2.857 or 2.87

One survey showed that among 785 randomly selected subjects who completed four years of college, 18.3% smoke and a 98% confidence interval for the true percentage of smokers among all people who completed four years of college is 15.1% to 21.6%. Based on the result, the smoking rate for those with four years of college appears to be substantially different than the 27% rate for the general population.a. Trueb. False

Answers

Answer

a. True

Step-by-step explanation:

Based on this survey we estimate that about 18.3\% of the college students smokes. And a 98\% confidence interval is [15.1\% ; 21.6\%].  So we know that our estimative for the smoking rate is in the confidence interval with 98\% certainty. We also know the estimative for the smoking rate in the general population is 27\%. So we can write the two possible hypothesis:

H_0 = Smoking rate is equal to 27\%.

H_1 = Smoking rate is not equal to 27\%.

We will reject the null hypothesis (H_0) if the estimate doesn't fall into the confidence interval for the college students smoking rate.

Since this condition holds we reject the null hypothesis. So with 98\% certainty we say that the smoking rate for the general population is different than the smoking rate for the college students.

A car rental agency initially offers a car that can go 304 miles on 19/2 gallons of gasoline. There are other vehicles available at the agency, shown below. Which of the other cars have a greater unit rate of miles per gallon than the recommended car?A) 187 miles on 17/2 gallons
B) 357 miles on 21/2 gallons
C) 216 miles on 27/2 gallons
D) 209 miles on 11/2 gallons
E) 115 miles on 5/2 gallons

Answers

Given:
304 miles on 19/2 gallons of gasoline.

304 miles ÷ 19/2 gallons = 304 miles * 2/19 gallon = 608 /19 = 32 miles per gallon.

Compute unit rate of each choices.
a) 187 miles ÷ 17/2 gallons = 187 * 2/17 = 374/17 = 22 miles per gallon
b) 357 miles ÷ 21/2 gallons = 357 * 2/21 = 714/21 = 34 miles per gallon
c) 216 miles ÷ 27/2 gallons = 216 * 2/27 = 432/27 = 16 miles per gallon
d) 209 miles ÷ 11/2 gallons = 209 * 2/11 = 418/11 = 38 miles per gallon
e) 115 miles ÷ 5/2 gallons = 115 * 2/5 = 230/5 = 46 miles per gallon

The car with the greater unit rate of miles per gallon than the recommended car is CHOICE E. 46 MILES PER GALLON

2 more questions thanks

Answers

These are two questions and two answers.

1) Problem 17.

(i) Determine whether T is continuous at 6061.

For that  you have to compute the value of T at 6061 and the lateral limits of T when x approaches 6061.

a) T(x) = 0.10x if 0 < x ≤ 6061

T (6061) = 0.10(6061) = 606.1

b) limit of Tx when x → 6061.

By the left the limit is the same value of T(x) calculated above.

By the right the limit is calculated using the definition of the function for the next stage: T(x) = 606.10 + 0.18 (x - 6061)

⇒ Limit of T(x) when x → 6061 from the right = 606.10 + 0.18 (6061 - 6061) = 606.10

Since both limits and the value of the function are the same, T is continuous at 6061.

(ii) Determine whether T is continuous at 32,473.

Same procedure.

a) Value at 32,473

T(32,473) = 606.10 + 0.18 (32,473 - 6061) = 5,360.26

b) Limit of T(x) when x → 32,473 from the right

Limit = 5360.26 + 0.26(x - 32,473) = 5360.26

Again, since the two limits and the value of the function have the same value the function is continuos at the x = 32,473.

(iii) If  T had discontinuities, a tax payer that earns an amount very close to the discontinuity can easily approach its incomes to take andvantage of the part that results in lower tax.

2) Problem 18.

a) Statement Sk

You just need to replace n for k:

Sk = 1 + 4 + 7 + ... (3k - 2) = k(3k - 1) / 2

b) Statement S (k+1)

Replace

S(k+1) = 1 + 4 + 7 + ... (3k - 2) + [ 3 (k + 1) - 2 ] = (k+1) [ 3(k+1) - 1] / 2

Simplification:

1 + 4 + 7 + ... + 3k - 2+ 3k + 3 - 2] = (k + 1) (3k + 3 - 1)/2

                 k(3k - 1)/ 2 + (3k + 1) = (k + 1)(3k+2) / 2

Do the operations on the left side and  you will find it can be simplified to k ( 3k +1) (3 k + 2) / 2.

With that you find that the left side equals the right side which is a proof of the validity of the statement by induction.

Hello,
Please, see the detailed solution in the attached files.
Thanks.

What is 2(x + 2) + (x + 5)

Answers

Answer:

3x+9

Step-by-step explanation:

What is the sum of -45 and 17?

-28
-62
28
-32

Answers

Sum means to add, so just add -45 + 17. 

-45 + 17 = -28

The answer is: -28.

the drama club held tryouts for 6 roles in a one-act play. five people auditioned for lead female, 3 for lead male, 8 for the best friend, 4 for the mother, 2 for the father, and 3 of the humorous aunt. how many different casts can be created from those who auditioned?

Answers

There are 2,880 different casts that can be created from those who auditioned.

To calculate the number of different casts that can be created, we need to multiply the number of options for each role.

For the lead female role, there are 5 options.

For the lead male role, there are 3 options.

For the best friend role, there are 8 options.

For the mother role, there are 4 options.

For the father role, there are 2 options.

For the humorous aunt role, there are 3 options.

To find the total number of possiblecasts, we multiply the number of options for each role:

5 x 3 x 8 x 4 x 2 x 3 = 2,880

Therefore, there are 2,880 different casts that can be created from those who auditioned.

To learn more on Combinations click:

brainly.com/question/19692242

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