MATHEMATICS COLLEGE

Ashley has an action figure collection of 500 action figures. She keeps 430 of the action figures on her wall. What percentage of Ashley's action figure collection does she keep on her wall?

Answers

Answer 1

Answer:

Answer: 86%

Step-by-step explanation:

430/500=0.86

0.86x100= 86

86%

Answer 2

Answer:

86%

Step-by-step explanation:

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An investor buys Rs.1200 worth of share in company first 5 monnths he bought the share at price of Rs.10,12,15,20 and 24 per share. After 5 months what is the average price paid for the share by him.

Answers

Answer:

14.6

Step-by-step explanation:

The computation of average price paid for the share is shown below:-

$Average = (Total\ investment)/(Total\ share)$

= $(6,000)/(410)$

= 14.6

For more clarification please find the attachment as attached using excel spreadsheet.

By dividing the total investment by the total number of shares we can get the average price paid for the share and the same is to be considered

Moreover, the total investment and the total shares are shown in the attachment. Kindly find it below:

Write an algebraic expression to represent the phrase below.a number n decreased by 5
please help

Answers

Answer

5-n

Step-by-step explanation:

consider the quadratic form q(x,y,z)=11x^2-16xy-y^2+8xz-4yz-4z^2. Find an orthogonal change of variable that eliminates the cross product in q(x,y,z) and express q in the new variables.

Answers

Answer:

$q(x,y,z)=16x^(2)-5y^(2)-5z^(2)$

Step-by-step explanation:

The given quadratic form is of the form

$q(x,y,z)=ax^2+by^2+dxy+exz+fyz$ .

Where $a=11,b=-1,c=-4,d=-16,e=8,f=-4$ .Every quadratic form of this kind can be written as

$q(x,y,z)={\bf x}^(T)A{\bf x}=ax^2+by^2+cz^2+dxy+exz+fyz=\left(\begin{array}{ccc}x&y&z\end{array}\right) \left(\begin{array}{ccc}a&(1)/(2) d&(1)/(2) e\n(1)/(2) d&b&(1)/(2) f\n(1)/(2) e&(1)/(2) f&c\end{array}\right) \left(\begin{array}{c}x&y&z\end{array}\right)$

Observe that $A$ is a symmetric matrix. So $A$ is orthogonally diagonalizable, that is to say, $D=Q^(T)AQ$ where $Q$ is an orthogonal matrix and $D$ is a diagonal matrix.

In our case we have:

$A=\left(\begin{array}{ccc}11&((1)/(2))(-16) &((1)/(2)) (8)\n((1)/(2)) (-16)&(-1)&((1)/(2)) (-4)\n((1)/(2)) (8)&((1)/(2)) (-4)&(-4)\end{array}\right)=\left(\begin{array}{ccc}11&-8 &4\n-8&-1&-2\n4&-2&-4\end{array}\right)$

The eigenvalues of $A$ are $\lambda_(1)=16,\lambda_(2)=-5,\lambda_(3)=-5$ .

Every symmetric matriz is orthogonally diagonalizable. Applying the process of diagonalization by an orthogonal matrix we have that:

$Q=\left(\begin{array}{ccc}(4)/(√(21))&-(1)/(√(17))&(8)/(√(357))\n(-2)/(√(21))&0&\sqrt{(17)/(21)}\n(1)/(√(21))&(4)/(√(17))&(2)/(√(357))\end{array}\right)$

$D=\left(\begin{array}{ccc}16&0&0\n0&-5&0\n0&0&-5\end{array}\right)$

Now, we have to do the change of variables ${\bf x}=Q{\bf y}$ to obtain

$q({\bf x})={\bf x}^(T)A{\bf x}=(Q{\bf y})^(T)AQ{\bf y}={\bf y}^(T)Q^(T)AQ{\bf y}={\bf y}^(T)D{\bf y}=\lambda_(1)y_(1)^(2)+\lambda_(2)y_(2)^(2)+\lambda_(3)y_(3)^(2)=16y_(1)^(2)-5y_(2)^(2)-5y_(3)^2$

Which can be written as:

$q(x,y,z)=16x^(2)-5y^(2)-5z^(2)$

PLEASE ANSWER THIS I WILL MARK BRAINLIEST WHOEVER ANSWERS IT CORRECT! Amanda made a jewelry box out of wood. The jewelry box is 7.5 inches long, 5 inches wide, and 3 inches high. Amanda decorates the jewelry box with 1-inch-square gem stickers. What is the minimum number of gem stickers needed to completely cover the jewelry box? To answer the question you must find the... A. length B. Surface Area C. Volume... The minimum number of gem stickers is... A. 31 B. 75 C. 112.5 D. 150

Answers

Answer:

surface area

150

Step-by-step explanation:

surface area

150

Answer:

Answer for 1st question: B. Surface Area, Answer for the 2nd question: D. 150

Step-by-step explanation:

Explanation for the 1st question: The length, we already know. The volume, we do not need to know because we are not trying to fill it up. We are trying to cover it up. That leaves only surface area.

Explanation for the 2nd question: The box is made up of 6 rectangles, but there are only 3 different rectangles. So after we find the area of each square, we need to multiply it by 2. So 3*5=15. 15*2=30. 7.5*3= 22.5. 22.5*2=45. 7.5*5=37.5. 37.5*2=70. So our answer is

45+75+30= 150.

249794641 ×7383838184

Answers

1844443208374371840 is the answer :)

A sphere fits snugly inside a cube with 2.4 m. edges. What is the approximate volume of the space between the sphere and cube to the nearest tenth?

Answers

Area of cube = s*s*s = 2.4 * 2.4 * 2.4 = 13.824 m³

Since the sphere is snugly fit in the cube, so the diameter of the sphere is equal to the length of the cube.

d = 2.4m, radius, r = d/2 = 2.4/2 = 1.2 m

Volume of sphere = (4/3)πr³

   = (4/3)*π*1.2*1.2*1.2 = 2.304π

   ≈ 2.304*3.1416 ≈ 7.2382 m³

Volume of space between sphere and cube = Volume of cube - Volume of sphere

   = 13.824 m³ - 7.2382 m³ = 6.5858 m³

Volume ≈ 6.6 m³      to the nearest tenth

Hope this helps.

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