Given that (-1,3) is on the graph of f(x), find thecorresponding point for the function
f(x - 1).

Answers

Answer 1
Answer:

I tried helping but I cant figure it out let me see..

Answer 2
Answer:

Answer: 0,3

Step-by-step explanation:


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A rectangular blankets perimeter is 210 inches. If the long sides of the blanket measure 60 inches what is the length of the shorter side of the blanket

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I believe the answer is 45

4x-7>17 what's the problem and answe of solution please

Answers

4x-7>17\n\n4x-7+7>17+7\n\n4x>24\ \ /:4\n\nx>6\ \ \ \Rightarrow\ \ \ x\ \in\ (6;\ +\infty)
4x-7>17\ \ \ \ | add\ 7\n\n4x>24\ \ \ \ | divide\ by\ 4\n\nx>6\n\nSolution\ is\ x\in(6,+\infty)

The interior angles in a regular polygon are 140 degrees. How many sides has the polygon? it could be something to do with s=(n-2) x 180

Answers

Yes, it certainly could !  When you first noticed that formula in a book, or when it was given to you in class, did you also notice or learn what it means ?

It means
"The sum of all the interior angles in a polygon" = (number of sides - 2) x 180.

Triangle ........ 3 sides ... (3 - 2) = 1 x 180 = 180° degrees ... 60° each if regular
Quadrilateral . 4 sides ... (4 - 2) = 2 x 180 = 360° degrees ... 90° each if regular
Pentagon ...... 5 sides ... (5 - 2) = 3 x 180 = 540° degrees ... 108° each if regular
Hexagon ....... 6 sides ... (6 - 2) = 4 x 180 = 720° degrees ... 120° each if regular
Sevenagon ... 7 sides ... (7 - 2) = 5 x 180 = 900° degrees ... 128 and 4/7 each if regular
Octagon ........ 8 sides ... (8 - 2) = 6 x 180 = 1080° degrees ... 135° each if regular
Nonagon ....... 9 sides ... (9 - 2) = 7 x 180 = 1260° degrees ... 140° each if regular
180^o-140^o=40^o\n\n360^o:40^o=9\n\nAnswer:This\ a\ regular\ polygon\ has\ 9\ sides.

Show how to apply the order of operation rules as you simplify the following expression.|-5| – 45 ÷ 3

Answers

|-5| - (45)/(3) 

5- (45)/(3)    Simplify \ (45)/(3) \ to \ 15

5-15 

\boxed{\boxed{=-10}}   Solution
There arnt really any steps
|-5|-45/3=-10

7a – b = 15a, for a does anyone have a clue what this is

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welp its kinda easy you are trying to get b so 7a-7a 15a-7a equals 8a
Im new here, Could anyone help me

How to combine fraction

Answers

\Large \frac { x }{ y } \begin{matrix} \rightarrow numerator \n \rightarrow denominator \end{matrix}


If two (or more) fractions have the same number as their denominator, you can just go ahead and add their numerators, without changing the denominator. For example:

\frac { 1 }{ 2 } and \frac { 4 }{ 2 } has the same number (2) as their denominator. So we will add their numerators, without changing the denominator.

\frac { 1 }{ 2 } +\frac { 4 }{ 2 } \quad =\quad \frac { 1+4 }{ 2 } \quad =\quad \frac { 5 }{ 2 }

So we added the numerators (1 + 4 = 5) and kept the denominator same (2) and we got ((5)/(2)

This was the case where the fractions' denominator was same. What if it's not ?

If their denominator isn't equal, we're gonna have to equalize them ourself. How to do that ?

Let's show it with an example :

\frac { 1 }{ 2 } and \frac { 3 }{ 4 } do no have the same number as their denominator. To be able to add them, we have to equalize their denominators.

\frac { 1 }{ 2 } 's denominator is 2 and \frac { 3 }{ 4 } 's is 

What can we do to equalize them ? Well, 4 is two times 2 ( 4 = 2\cdot 2 ) So we cane multiply the denominator of \frac { 1 }{ 2 } (which is 2) with 2 , to equal it to \frac { 3 }{ 4 } 's denominator (which is 4).

But, there is a catch here. When multiplying a fraction's denominator before adding it to another, you should make sure that you're preserving its ratio. What does that mean ? 

Let's take the number \frac { 4 }{ 6 } 

(1) if we multiply only its numerator with a number (let it be 3)

\frac { 3\cdot 4 }{ 6 } \quad =\quad \frac { 12 }{ 6 } \quad =\quad 2

You got a new fraction with a different ratio than (4)/(6). And it is also equal to 2, but (4)/(6) isn't equal to 2.

(2) if we multiply only its denominator with a number (let it be 3 again)

\frac { 4 }{ 3\cdot 6 } \quad =\quad \frac { 4 }{ 18 }

You got a new fraction again, with a different ration than (4)/(6)

How can we know that ? Well, if you simplify these two numbers to the simplest number, you'll get a different fraction or integer. Let's do so.

\frac { 4 }{ 6 } \quad =\quad \frac { 2\cdot 2 }{ 2\cdot 3 } \quad =\quad \frac { 2 }{ 2 } \cdot \frac { 2 }{ 3 } \quad =\quad 1\cdot \frac { 2 }{ 3 } \quad =\quad \frac { 2 }{ 3 }

So the simplified form of (4)/(6) in the fraction form is (2)/(3)

\frac { 4 }{ 18 } \quad =\quad \frac { 2\cdot 2 }{ 2\cdot 9 } \quad =\quad \frac { 2 }{ 2 } \cdot \frac { 2 }{ 9 } \quad =\quad 1\cdot \frac { 2 }{ 9 } \quad =\quad \frac { 2 }{ 9 }

And the simplest form of (4)/(18) as a fraction is (2)/(9) , which is not equal to (2)/(3)

\frac { 2 }{ 3 } \quad \neq \quad \frac { 2 }{ 9 }

So what to do, to preserve the ratio ? Simle. We'll multiply also the numerator with the same number we're going to multiply the denominator with.

Let's get back to our example.

Adding \frac { 1 }{ 2 } and \frac { 3 }{ 4 }

We were going to multiply (1)/(2) 's denominator with 2. Now that we know, the ratio must not change, we'll also multiply the numerator with 2.

\frac { 2\cdot 1 }{ 2\cdot 2 } \quad =\quad \frac { 2 }{ 4 }

Now we've got a number which has the same denominator as \frac { 3 }{ 4 }

We can add them now,

\frac { 2 }{ 4 } \quad +\quad \frac { 3 }{ 4 } \quad =\quad \frac { 2+3 }{ 4 } \quad =\quad \frac { 5 }{ 4 }

\boxed { \frac { 1 }{ 2 } \quad +\quad \frac { 3 }{ 4 } \quad =\quad \frac { 5 }{ 4 }  }

I hope this was clear, if not please ask and I'll try to explain.