In an equation or inequality, you want to get the variable.
Answers
To solve for [variable] in the equation [equation], apply inverse operations to isolate [variable]. For inequalities, follow the same steps, but note the direction of the inequality sign to find valid values.
To solve for a variable in an equation, one must follow a systematic process. First, identify the equation's form, whether linear, quadratic, or another type. Then, apply appropriate operations to isolate the variable. For example, in linear equations, perform addition, subtraction, multiplication, or division to isolate the variable on one side of the equation. For quadratic equations, use factoring, completing the square, or the quadratic formula.
When dealing with inequalities, the same principles apply, but one must also consider the direction of the inequality sign (>, <, ≥, ≤). When multiplying or dividing by a negative number, the inequality sign must be reversed.
In both cases, it's crucial to perform the same operation on both sides of the equation or inequality to maintain balance and equivalence. Lastly, check the solution by substituting it back into the original equation or inequality to ensure its validity.
This systematic approach ensures that we can accurately solve for variables in equations and find the values that satisfy inequalities while maintaining mathematical integrity.
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Please help im desperate if f(x) = 5 + 3x find the value of the dependent variable if the if he independent variable is -4 and if you know hoew to do this pls answer my other question
Which best describes this quadrilateral? A. Opposite sides are parallel. B. Only one pair of sides is parallel. C. All angles have the same measure. D. All sides are a different length.
Answers
y=ax+b
Putting those points to equation:
(2,14)
14=a*2+b
(1,7)
7=a+b
From substituting method:
a=7-b
14=(7-b)*2+b
14=14-2b+b
b=0
a=7
y=7x - result
Answer
If I'm stoked, then I got a good
grade on my math test.
If I'm not stoked, then I didn't
O get a good grade on my math
test.
If I don't get a good grade on
my next math test, then I won't
be stoked.
If I get a good grade on my
next math test, then I won't be
stoked.
Answers
Answer:
"If I don't get a good grade on my next math test, then I won't be stoked."
Step-by-step explanation:
The original statement is about a good grade leading to being happy. The converse statement is about a bad grade leading to not being happy. It's the opposite situation but still follows a similar pattern: "If A, then B" becomes "If not A, then not B."
Let me know if you have any questions!
Answers
A) To convert 7.000 cubic centimeters to kiloliters:
7.000 cm^3 * (1 kL / 1,000,000 cm^3) = 0.000007 kL
B) To convert 80. cm^2 to square inches:
80. cm^2 * (1 in^2 / 6.4516 cm^2) ≈ 12.44 in^2
Answers
-4x<11
-3-4x<8 /: (-4)
x>-2
add and simplify 9/16=1/2=?
Answers
I hope I helped :D
The mean is less than the median.
The median is less than the mean.
The mean is equal to the median.
The median and mean cannot be compared from a histogram.
Answers
The correct answer is:
The median is less than the mean.
Explanation:
This histogram is skewed right; the data "peaks" further to the left than the center.
If a histogram is skewed right, the mean is greater than the median.
This is because skewed-right data have a few large values that increase the mean but do not affect where the exact middle of the data is.
Answer:
Option B) The median is less than the mean.
Step-by-step explanation:
We are given the following in the question:
A histogram showing the duration, in minutes, of movies in theaters.
- If we observe the shape of the histogram, more values of the histogram lies on the right side, the tail of the distribution is longer on the right hand side than on the left hand side
- Hence, the histogram is skewed right.
- The histogram is not normal and shows skewness.
- It is a right skewed histogram or positively skewed.
- Now, for a positively skewed data the mean is greater than the median since more values lies on right side and have a greater value thus the mean increases.
- The relationship shown by the histogram between mean and median is that median is less than the mean