Answer:
with exponents, you take a number and multiply it by itself.
Step-by-step explanation:
the root of a number is the number that can be multiplied a certain amount of times to get us that number.
therefore roots get you to the root of a number.
Hope it helps!
(even if its two weeks late.....)
Answer:20
Step-by-step explanation:
b) (b, -c)
c) (-b, c)
d) (-b, -c)
The coordinate of the point C will be (b, c). Then the correct option is A.
The polygon which is having five sides and each side are congruent. And each internal angle of the Pentagon will be of 108 degrees.
The pentagon ABCDE with the coordinate of A, B, C, D, and E are given below.
If a line intersect the shape and the shape look identical on both sides of line, then the line is known as axis of symmetry.
In a regular pentagon, there are five line of symmetry.
In the figure, the y-axis is the axis of symmetry and the axis of symmetry is passing through the point D.
The point C is in the first coordinate, then the abscissa and ordinate will be positive.
Then the coordinate of the C will be (b, c).
Then the correct option is A.
More about the regular pentagon link is given below.
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Answer: a
Step-by-step explanation: C is in quadrant 1 and quadrant 1 is (+,+)
The particle passes through the origin at t = 0 and t = ±√20. The particle is instantaneously motionless at t = 0 and t = ±√10.
(a) To determine the times at which the particle passes through the origin, we need to find when the position function equals zero. So, we set s(t) = 0 and solve for t.
t4 - 20t2 = 0
Factoring out a t2, we get:
t2(t2 - 20) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial position), and t = ±√20 (approximately t = ±4.47).
(b) To determine when the particle is instantaneously motionless, we need to find when the velocity of the particle is equal to zero. The velocity function of the particle is the derivative of the position function. So, we differentiate s(t) with respect to t to find the velocity function.
v(t) = s'(t) = 4t³ -40t
Setting v(t) = 0, we have:
4t³ -40t = 0
Factoring out a 4t, we get:
4t(t² - 10) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial velocity), and t = ±√10 (approximately t = ±3.16).
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The particle passes through the origin at t = 0 and t = √20 seconds. The particle is instantaneously motionless at t = 0 and t = ±√10 seconds.
The position of the particle at time t is given by the equation s(t) = t4 - 20t2. To determine the times when the particle passes through the origin, we set s(t) equal to zero and solve for t. This gives us the quadratic equation t4 - 20t2 = 0, which can be factored as t2(t2 - 20) = 0. The solutions to this equation are t = 0 and t = ±√20. Since t cannot be negative in this scenario, the particle passes through the origin at t = 0 and t = √20 seconds.
To determine the times when the particle is instantaneously motionless, we need to find the times when the velocity of the particle is equal to zero. The velocity of the particle can be found by taking the derivative of the position function with respect to time, v(t) = 4t3 - 40t. Setting this equation equal to zero and solving for t gives us the cubic equation 4t3 - 40t = 0. This equation can be factored as 4t(t2 - 10) = 0. The solutions to this equation are t = 0 and t = ±√10. Therefore, the particle is instantaneously motionless at t = 0 and t = ±√10 seconds.
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Answer:
To get to the ice cream store, Molly went 1 unit right and 7 units down. This means that she moved 1 unit to the right from her original position and 7 units down from her original position.
So, to find Molly's starting position, we need to move 1 unit to the left from the ice cream store and 7 units up from the ice cream store.
Therefore, Molly started from a location that is 1 unit to the left and 7 units up from the Ice Cream Store.
Step-by-step explanation: