MATHEMATICS COLLEGE

Kristl has saved 30%of her tuition for
dance class. She
needs to have $600
save. How much has
she saved so far?

Answers

Answer 1
Answer:

Answer:

$180

Step-by-step explanation:

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Help with this math question please thanks

Answers

For this case, what we should do is use the given equation.
 A = P (1 + r) ^ t
 Substituting values we have:
 3900 = 1100 * (1 + 0.04) ^ t
 Clearing t we have:
 (1.04) ^ t = (3900) / (1100)
 log1.04 ((1.04) ^ t) = log1.04 ((3900) / (1100))
 t = log1.04 ((3900) / (1100))
 t = 32.3 years
 Answer:
 the time will be:
 t = 32.3 years

There are 15 pieces of fruit in the fruit in a bowl and 6 of them are apples. What percentage of the pieces of the fruit in the bowl are apples0.06%

0.4

6%

40%

Answers

The answer is 0.4 because 6/15 is 2/5 which is 0.4 as a decimal

Pls help me with these equations 2x-7/3 = 5
4 (x - 5) = 3 (x - 7) + x + 1
5x + 2x - 9 = 7x + 11
6x - 12 + 4 (x - 7) = 5 (2x - 4) - 1
5x - 1/3 = 8

Answers

The answers to the questions
Last one is 3/4 hope this helps

At a large department store, the average number of years of employment for a cashier is 5.7 with a standard deviation of 1.8 years, and the distribution is approximately normal. If an employee is picked at random, what is the probability that the employee has worked at the store for over 10 years? 99.2% 0.8% 49.2% 1.7%

Answers

Answer:

option 0.8%

Step-by-step explanation:

Data provided in the question:

Mean = 5.7 years

Standard deviation, s = 1.8 years

Now,

P(the employee has worked at the store for over 10 years)

= P(X > 10 years)

= P (Z > (X-Mean)/(\sigma))

or

= P (Z > (10-5.7)/(1.8))

= P (Z > 2.389 )

or

= 0.008447     [from standard  z table]

or

= 0.008447 × 100% = 0.84% ≈ 0.8%

Hence,

the correct answer is option 0.8%

A consumer advocate wants to collect a sample of jelly jars and measure the actual weight of the product in the container. He needs to collect enough data to construct a confidence interval with a margin of error of no more than 3 grams with 95​% confidence. The standard deviation of these jars is usually 3 grams. Estimate the minimum sample size required.

Answers

Answer:

n=3.8416≅4

So Minimum Sample Size is 4

Step-by-step explanation:

In order to find the minimum sample size, the formula we use will be:

n= (Z^2*S^2)/(E^2)

Where:

n is sample size  

Z is the distribution

S is the standard deviation

E is the  Margin of error

S=3 ,E=3

For Z:

Alpha=1-0.95=0.05

Alpha/2=0.025=2.5%

From Cumulative Standard Distribution Table:

Z at Alpha/2 = 1.960

n= (1.960^2*3^2)/(3^2)

n=3.8416≅4

So Minimum Sample Size is 4

Can someone help me with this problem please

Answers

Answer:

Circumference=2πr or πd

So:

3.14 × 6cm

=18.84cm
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