A jar contains only nickels and dimes. The jar contains a total of 21 coins. The value of all the coins is 1.65$. How many nickels and dimes are in the jar?

Answer:

option 2=11/20  is the answer.

Step-by-step explanation:

given that there are 20 cards numbers 1,2... 20.

A card is randomly drawn.

We have to find the probability of drawing either 1 or even card.

P(drawing even card) = no of even cards/total cards = 10/20= 0.5

P(drawing one) = no of 1's/total cards = 1/20 = 0.05

P(drawing both one and even card) = 0 (since impossible)

Hence P(drawing even or one) =0.5+0.05-0

=0.55

= 11/20

Hence option 2 is the answer.

Answer : 11/20

There are 20 cards labeled from 1 to 20 in a bag. A card is randomly selected from the bag.

Total number of outcomes = 20

outcomes of an even number ={2,4,6,8,10,12,14,16,18,20}

So number of outcomes of even number = 10

outcomes of a 1 ={1}

So number of outcomes of a 1 = 1

Number of outcomes of even number and a 1 = 10+1 = 11

Probability ( any event) =number of favorable outcomes divide by total  number of outcomes

Probability (getting an even number or a 1) =

Answer:

1. 3 2/3

2. 4 9/10

3. 1 27/56

4. 58 2/15

5. 11 1/24

Step-by-step explanation:

1. To find the answer, add 3 1/6 and 5 9/10. First change them into improper fractions. 5 9/10 is 59/10 and 3 1/6 is 19/6. Now, you have to make the denominator (bottom number) the same number for both fractions. To do this you must find a LCM for both the number (10, 6) a LCM for these numbers is 30. Now to change the denominator to this you must times the numerator and denominator by the number needed to get the LCM for the denominator.

So 6 x 5 = 30 and 3 x 10 = 30.

19/6 x 5 = 95/30 and 59/10 x 3 = 177/30

Now add the fractions:

This equals 272/30

Simplify:

Now take 12 5/6 and turn it into a improper fraction: 77/6

Now again, you have to make the denominator to 30

77/6 x 5 = 385/30

Now subtract 385/30 - 272/30

This equals 113/30

Now turn this back into a mixed fraction:

3 23/30

The answer is 3 23/30

This process is basically the same for all the other questions.