Book club A charges $20 for membership and $2 per book rental. Book club B charges $10 for membership and $3 per book rental. For how many movie rentals will the cost be the same at both book clubs? What does that cost?

Answers

Answer 1
Answer:

Given:

Book club A charges $20 for membership and $2 per book rental.

Book club B charges $10 for membership and $3 per book rental.

To find:

The number of books for which the cost be the same at both book clubs.

Solution:

Let x be the number of books.

Book club A charges $20 for membership and $2 per book rental. So, the total cost is

C_1=20+2x             ...(i)

Book club B charges $10 for membership and $3 per book rental. So, the total cost is

C_2=10+3x            ...(ii)

Equating (i) and (ii), we get

10+3x=20+2x

3x-2x=20-10

x=10

The total cost is

C_1=20+2(10)

C_1=20+20

C_1=40

Therefore, the total cost at both book clubs are same for 10 rental books and that cost is $40.


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Which of the following is not a property of mathematical proofs?

Explain why (–4x)^0 = 1, but –4x^0 = –4.

Answers

Any number raised to power zero = 1. 

Note that 0 raised to power 0 is not 1, it is undefined.

Therefore:

(-4x)⁰ = 1

For the second part  -4x⁰ = :

x⁰ = 1,    -4x⁰ = -4*(1) = -4

 This is true on the assumption that x is not equal to zero.

I hope this explains it.

A couple decided to have 4 children. What is the probability that they will have at least two boys?

Answers

See below the theee of possibilities:

BBBB
BBBG
BBGB
BBGG
BGBB
BGBG
BGGB
BGGG
GBBB
GBBG
GBGB
GBGG
GGBB
GGBG
GGGB
GGGG

There are 16 differents possibilities.
In 11 of them have at least 2 boys

So probability is 11/16

How do u check your answer for 4x+12-2x=26

Answers

Answer:

7

Step-by-step explanation:

4x+12-2x=26

Or, 2x=26-12

Or, 2x=14

Or, x=7

Can anyone help?? Please

Answers

3O=12/3   Divide both sides by 3.
/3

O=4

♢+2=5(4)
♢+2=20
    -2  -2      Subtract 2

 ♢=18

 2(4)+18=2∆
8+18=2∆
26=2∆
/2     /2      Divide by 2

∆=13
The circle is worth 4 because it's being multiplied by 3. Then the diamond is 18 and the triangle is -5.

Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4.

A) 5
B) 7
C) 19
D) 23

Answers

We have given t_(1)=3 and t_(n) =  t_(n-1) + 4. Fifth term is t_(5)= t_(4)+4. It means we need to find t_(4) and in order to find the latter, we have to find t_(4)= t_(3)+4, t_(3)= t_(2)+4 and t_(2)= t_(1)+4 . Since we know the value of  t_(1), beginning from the last equation we can find the value of  t_(5). We can write that t_(2)= t_(1)+4=3+4=7, t_(3)= t_(2)+4=7+4=11 and t_(4)= t_(3)+4=11+4=15. Since t_(5)= t_(4)+4, then t_(5)= 15+4=19

Factories fully the flowing
x^(2) +3x \n2x^(2) -8x \n6x+9x^(2) \n12x^(3) -4x^(2)

Answers

Answer:

Given below:)

Step-by-step explanation:

1) (x)(x+3)

2) (2x)(x-4)

3) (3x)(2+3x)

4) (4x^2)(3x+1)

I have factorised all of them by taking the common factor out of each