Find the difference using fraction bars or a paper and pencil. Write your answer in simplest form. 7/10 - 1/2

Answer:

16

Step-by-step explanation:

x^2-8x+k is a quadratic expression of the form ax^2 + bx + c.  Here a = 1, b = -8 and c = k.  Focus on x^2-8x and complete the square as follows:  Take half of the coefficient of x (that is, take half of -8) and square the result:

(-4)^2 = 16; if we now write x^2-8x+ 16, we'll have the square of (x - 4):  (x -4)^2.

Thus, k = 16 turns x^2-8x+k into a perfect square.

Answer:

(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

Step-by-step explanation:

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

What is inequality?

Inequality is a statement shows greater the, greater then equal to, less then,less then equal to between two algebraic expressions.

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

Hence the inequality for the number of items, x, produced by the labor, is 250 ≤ x ≤ 600 and the inequality for the cost, C is $1,000 ≤ C ≤ $3,000

To know more about Inequality follow

brainly.com/question/24372553

Answer:

The correct option is the last one.

Step-by-step explanation:

To transform the graph of into the following steps are fulfilled:

1) Move the graph 2 units to the right:

Let then Notice that the cut point has been moved to x = 2.

2) Reflect on the x axis:

To reflect a graph on the x-axis we do Then

3) Stretch according to factor 2.

For this we do

Then we have

4) Move up the graph in two units:

We do

Then

These steps coincide with those listed in the last option. Therefore the correct option is the last one.

"Translate 2 units on the right, reflect on the x-axis, stretch according to the factor 2 and translate 2 units"

Final answer:

To transform the graph from y • x^2 to y = -2(x - 2)^2 + 2, you need to translate 2 units to the right, reflect across the x-axis, stretch by the factor 2, and translate up 2 units.

Explanation:

The correct steps to transform the graph of y•x^2 to y = -2(x - 2)^2 + 2 are:

1. Translate 2 units to the right
2. Reflect across the x-axis
3. Stretch by the factor 2
4. Translate up 2 units

Learn more about Transforming Graphs here:

brainly.com/question/19040905

#SPJ3