What are the zeros of the polynomial function: f(x) = x3 + x2 – 6x ? ...?

Answers

Answer 1
Answer: The solution to the problem is as follows:

  
x³ + x² − 6x = 0 
x (x² + x − 6) = 0 
x (x − 2) (x + 3) = 0 
x = 0, 2, −3 


f(x) = 2x³ + 5x² + 6x − 4 
f(−x) = −2x³ + 5x² − 6x − 4 

Let's look at signs only and how many sign changes there are: 
f(x) = + + + − 
1 sign change ----> 1 positive root 
f(−x) = − + − − 
2 sign changes ----> 2 or 0 negative roots 

Min. number of real roots = 1 ----> max. number of complex roots = 2 
Max. number of real roots = 3 ----> min. number of complex roots = 0

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(-1,2) and (-4,8)Find the slope of the line that contains the point
1. 2
2. 6/5
3. -2
4. -6/5

Answers

Answer:

-2

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

   = ( 8 -2)/(-4- -1)

   = (8-2)/(-4+1)

   = 6/-3

   = -2

The answer is -2 you simplify 6/-3 and get -2

If abx - 5 = 0, what is x in terms of a and b?

Answers

Here we want to have x on one side of equation so,
we put number 5 on right side of equation:
abx=5
then we divide both sides by ab to obtain x on left side:
Result:
x=(5)/(ab)
abx - 5 = 0

abx - 5 +5= 0+5

abx=5

(abx)/(ab) = (5)/(ab)

x= (5)/(ab)

Find the second derivative for y=(x+2)/(x-3)

Answers

Let's find the first derivative.

Using quotient rule

f(x)=(g(x))/(h(x))

f'(x)=(g'(x)*h(x)-g(x)*h'(x))/(h^2(x))

then:

y=(x+2)/(x-3)
f(x)=y

g(x)=x+2

g'(x)=1

h(x)=x-3

h'(x)=1

Let's replace

f'(x)=(g'(x)*h(x)-g(x)*h'(x))/(h^2(x))

y'=(1*(x-3)-(x+2)*1)/((x-3)^2)

y'=(x-3-x-2)/((x-3)^2)

\boxed{y'=(-5)/((x-3)^2)}

the second derivative is the derivative of our first derivative.

y'=(-5)/((x-3)^2)

We can write this function as

y'=-5*(x-3)^(-2)

now we have to use the Chain rule's

f(u)=-5u^(-2)

and

g(x)=x-3

f[g(x)]=-5*(x-3)^(-2)

then

f'[g(x)]=f'(u)*g'(x)

f'(u)=-5*(-2)*u^(-3)=10*u^(-3)

g'(x)=1

f'[g(x)]=f'(u)*g'(x)

Let's replace

f'[g(x)]=10*u^(-3)*1

Let's change u by (x-3)

f'[g(x)]=10*u^(-3)

f'[g(x)]=10*(x-3)^(-3)

\boxed{\boxed{y''=(10)/((x-3)^(3))}}

Trig please helpLaw of Sines and the Ambiguous Case.

In ∆ ABC, a =10, c = 16, and m < A = 44*
How many distinct triangles can be drawn given these measurements?

Answers

Answer:

None (zero)

Step-by-step explanation:

10/sin(44) = 16/sinC

sinC = 1.111453392

Not possible

Answer:

Answer:

None (zero)

Step-by-step explanation:

10/sin(44) = 16/sinC

sinC = 1.111453392

Oxfam America, Doctors Without Borders, and the Red Cross are examples of __________.a. IRBDs
b. IDAs
c. NGOs
d. IMFs

Which of the following countries is the largest shareholder in the World Bank?
a. Japan
b. France
c. the United States
d. the United Kingdom

Answers

Answer:

The correct answers are the option C to question number 1 and the option C to question number 2.

Step-by-step explanation:

Non-Governmental Organization, or NGO, is the name given to the organizations that are not under the control and direction of any government, therefore they are independent. Moreover, it is very common that they tend to be non-profit organization that focus on humanitarians and social aspects.

Oxfam America is an international confederation of 19 NGOs members whose main purpose is to fight against poverty and suffering in 90 countries.

Doctors Without Borders is an international humanitarian medical NGO whose main work has covered conflict zones and regions affected by endemic diseases helping those in need.

Red Cross is also an international humanitarian movement whose main focus is on protecting life and human health.

The World Bank is an international financial institution whose main purpose is to provides loans to poorer countries that need it for long run capital proyects which involves development and reconstruction most of the time. It is financed by the most powerful countries and its major shareholder is the United States, followed by Japan, China and other 17 members on the list.  

number 1 is C.NGOs
number 2 is C. United States

Use the function f(x)=x 2 −6x+8 to answer the following questions: a. What is the y-intercept? b. What are the x-intercepts? c. What is the vertex? d. What is the axis of symmetry?

Answers

Answer:

see explanation

Step-by-step explanation:

given the function

f(x) = x² - 6x + 8

(a)

to find the y- intercept , let x = 0 in f(x)

f(0) = 0² - 6(0) + 8 = 0 - 0 + 8 = 8 ← y- intercept

(b)

to find the x- intercepts , let f(x) = 0 , that is

x² - 6x + 8 = 0 ← in standard form

(x - 2)(x - 4) = 0 ← in factored form

equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x - 4 = 0 ⇒ x = 4

the x- intercepts are x = 2 and x = 4 or (0, 2 ), (0, 4 ) in coordinate form

(c)

given a quadratic in standard form

f(x) = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the vertex is

x_(vertex) = - (b)/(2a)

f(x) = x² - 6x + 8 ← is in standard form

with a = 1 and b = - 6 , then

x_(vertex) = - (-6)/(2) = - (- 3) = 3

evaluate f(3) for corresponding y- coordinate

f(3) = 3² - 6(3) + 8 = 9 - 18 + 8 = - 9 + 8 = - 1

vertex = (3, - 1 )

(d)

the axis of symmetry is a vertical line , passing through the vertex with equation

x = c ( c is the value of the x- coordinate of the vertex )

equation of axis of symmetry is then x = 3