if the perimeter of a circular sector is fixed at 100 ft, what values of r and s give the sector the greatest area? ...?

Answers

Answer 1
Answer: The sector arc length is just a fraction of the circumference: 
Laʀc = (2πR) • (θ ⁄ 2π) = R • θ ... where θ = central angle (of sector) 

 Ps = R + R + (R • θ) ... perimeter of sector = Ps 

 Ps = R • (2 + θ) ... Ps = 100 ft 

  100 = R • (2 + θ) 

      θ = (100 ⁄ R) – 2 

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~... 

Similarly, the sector area is just a fraction of the circle area: 

 As = (πR²) • (θ ⁄ 2π) ... area of sector = As 

 As = R² • θ ⁄ 2 ... substitute for θ 

 As = R² • [(100 ⁄ R) – 2 ] ⁄ 2 

 As = 50R – R² ... differentiate 

            As' = 50 – 2R ... set to zero 

           0 = 50 – 2R 

         R = 25 ft ... optimum radius 

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~... 

 As = 50R – R² ... evaluate at: R = 25 ft 

 As = 50(25) – (25)² 

 As = 625 ft² ... maximum area 

Note ... at any other R_value, the sector area is less. 


  " θ " can be determined using:  θ = (100 ⁄ R) – 2

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Answer 2
Answer:

Final answer:

For a circular sector with a fixed perimeter of 100 ft, the values of radius (r) and arc length (s) that will maximize the sector's area are r=25 and s=50.

Explanation:

The perimeter of a circular sector is composed by the length of the arc (s) plus twice the radius (r). If this sum is fixed at 100 ft, then the length of the arc s is equal to 100 - 2r. The area A of a circular sector can be defined as A = 0.5 * r * s.

Substituting the expression for s into the area formula obtains A = 0.5 * r * (100-2r). Simplifying results in A = 50r - r^2 which is a downward opening parabola.

The maximum value of a parabola occurs at the vertex. For a parabola in the form y=ax^2 + bx + c, the x-coordinate of the vertex is -b/(2a). In this case, a=-1 and b=50, hence r=-50/2*(-1) = 25. Substituting r=25 back into the formula for s obtains s = 100-2*25 = 50. Therefore, the values for r and s that will give the circular sector the greatest area are r=25 and s=50.

Learn more about Perimeters and Areas here:

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Guy and Jim work at a furniture store. Guy is paid $185 per week plus 3% of his total sales indollars, x, which can be represented by g(x) = 185 + 0.03x. Jim is paid $275 per week plus 2.5%
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Answers

Guy's weekly pay is:
185 dollars + 3/100 * x (3 percent of X -> his total weekly sales in dollars).
Jim's weekly pay is:
275 dollars + 25/1000 * x (2.5 percent of X -> his total weekly sales in dollars, i.e. 2.5/100 = 0.025).
We need to have these weekly pays the same, so we equalize these expressions and solve the obtained equation by x:
185 + 0.03*x = 275 + 0.025*x
we switch free numbers to the right side and unknowns to the left side of equation:
3/100 * x - 25/1000 * x = 275 - 185
3/100 * x - 25/1000 * x = 90 /*1000 (multiply whole equation by a 1000, to loose fractions)
we get:
30*x - 25*x = 90000
5*x = 90000, divide whole equation by 5 (which means both sides of equation):
x = 90000/5
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Value of x is 18 000 for which their weekly pay is the same.

Can someone help me with this please

Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

............................................................60 and 78

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Answers

2/5-1/4

8/20 - 5/20

(8-5)/20

= 3/20


I hope that's help ! if you have question please ask

2/5-1/4

2/5=8/20

1/4=5/20

8/20-5/20=3/20
The answer to the problem is3/20