Older auto-focus cameras sent out a pulse of sound and measured the time interval required for the pulse to reach an object, reflect off of it, and return to be detected. Can air temperature affect the camera's focus? New cameras use a more reliable infrared system.

Answers

Answer 1

Answer: Temperature is also a condition that affects the speed ofsound. Heat, like sound, is a form of kinetic energy. Molecules at higher temperatures have more energy, thus they can vibrate faster. Since the molecules vibrate faster, sound waves can travel more quickly. so the higher the air temperature the faster it will focus.

Answer 2

Answer:

Answer:

ITS C!!

Explanation:I PROMISE!!

I GOT IT CORRECT!!!

JUST DO IT!!

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Why is the water vapor fresh water when it rises from the ocean?

Answers

Because when the water is heated by the sun, the salt sinks to the bottom.

leaves the salt behind

While sitting in your car by the side of a country road, you see your friend, who happens to have an identical car with an identical horn, approaching you. You blow your horn, which has a frequency of 260 Hz; your friend begins to blow his horn as well, and you hear a beat frequency of 6.0Hz .How fast is your friend approaching you?

Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

$v_s =7.74\ m/s$

Explanation:

given,

Speed of sound = 343 m/s

frequency of horn = 260 Hz

the friend is approaching, the frequency is increased by the Doppler Effect. The frequency is 266 Hz

using formula

$f' = (v)/(v-v_s)f_0$

$266= (343)/(343 - v_s)(260)$

$1.023= (343)/(343 - v_s)$

$343 - v_s = 335.26$

$v_s =7.74\ m/s$

the speed of friends approaching is equal to $v_s =7.74\ m/s$

A rocket travels vertically at a speed of 1300 km/hr.1300 km/hr. The rocket is tracked through a telescope by an observer located 13 km13 km from the launching pad. Find the rate at which the angle between the telescope and the ground is increasing 3 min3 min after the lift-off.

Answers

Final answer:

This calculus problem can be solved by defining the appropriate variables, constructing a relationship using trigonometry, taking the derivative of both sides with respect to time, and solving for the rate of change of the angle with respect to time. The initial distances, rocket's speed, and angle are used to determine the rocket's position after 3 minutes and thus the rate at which the angle is changing.

Explanation:

This problem involves the concept of related rates in calculus and the understanding of trigonometric relationships. Let's denote the rocket's altitude as y and the angle between the ground and the telescope as θ. We know Δy/Δt = 1300 km/hr, we're given the initial distance (13 km), and we want to find Δθ/Δt at 3 min after lift-off.

From trigonometry, we know that tan(θ) = y/x, where x is the horizontal distance (which remains constant at 13 km) and y is the vertical distance (which is changing). Differentiating both sides with respect to t gives sec²(θ) * Δθ/Δt = Δy/Δt / x. Assuming that the speed of the rocket remains constant, we find that y = (1300 km/hr * 3min)*(1hr/60min) = 65 km at 3 min after launch. Plugging x = 13 km and y = 65 km into the equation tan(θ) = y/x, we get θ = atan(65/13) = 78.69°. Now we can solve for Δθ/Δt using the differentiated equation: Δθ/Δt = ( Δy/Δt / x ) / sec²(θ) = (1300 km/hr / 13 km) / sec²(78.69°). Solving this gives the rate of change of θ with respect to time.

Learn more about Related Rates here:

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Andrew drives to his friend's house, which is 60 miles to the east. After visiting, he travels 25 miles to the west to visit his grandparents. What is Andrew's displacement?

Answers

Andrew's displacement while visiting his grandparents is 35 miles to the east.

What is displacement?

The displacement is the shortest distance travelled by the particle. It is the vector quantity which represents both the magnitude and direction.

Given Andrew drives to his friend's house, which is 60 miles to the east. After visiting, he travels 25 miles to the west to visit his grandparents.

The displacement will be

60 miles to the east - 25 miles to the west = 35 miles to the east

Thus, the Andrew's displacement is 35 miles to the east.

Learn more about displacement.

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A few miles like 23 I’m thinking

If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, what's the average velocity of the body? A. 28 m/s
B. 17 m/s
C. 21.5 m/s
D. 19.5 m/s

Answers

Since the acceleration is constant, the average velocity is simply the average of the initial and final velocities of the body:

$v_(avg) = (v_f+v_i)/(2)=(30 m/s+13 m/s)/(2)=21.5 m/s$

We can proof that the distance covered by the body moving at constant average velocity $v_(avg)$ is equal to the distance covered by the body moving at constant acceleration a:

- body moving at constant velocity $v_(avg)$ : distance is given by

$S=v_(avg)t = (v_f+v_i)/(2)t$

- body moving at constant acceleration $a=(v_f-v_i)/(t)$ : distance is given by

$S=v_i t+ (1)/(2)at^2 = v_i t + (1)/(2)(v_f-v_i)/(t)t^2=(v_i+(1)/(2)(v_f-v_i))t=(v_f+v_i)/(2)t$

The answer is 21.5 m/s

The charge on a gamma ray is ____.

Answers

A gamma ray is the same physical thing as a radio wave or
a light wave. All of them are traveling electric and magnetic
fields, not charged particles. The waves and rays have no charge.

the charge on a gramma ray is zero

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