An Earth satellite in orbit emits a radio signal of constant frequency. Compared to the emitted frequency, the frequency of the signal received by a stationary observer will appear to be:a) higher as the satellite approaches
b) higher as the satellite moves away
c) lower as the satellite approaches
d) unaffected by the satellite's motion

Answers

Answer 1
Answer: The best and most correct answer among the choices provided by your question is the first choice or letter A.

Compared to the emitted frequency, the frequency of the signal received by a stationary observer will appear to be: higher as the satellite approaches

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What receives radio waves from space objects such as quasars?a. GPS equipment
b. Landsat satellites
c. VLBI equipment
d. navigation satellites

Answers

A VLBI system detects radio waves from space objects such as quasars.

"VLBI" stands for "Very Long Baseline Interferometry".  The idea
is that the signal is picked up by two receivers, separated by some
distance.  The tiny difference in the time the signal shows up at the
two places is used for a very precise calculation of the direction it's
coming from.

Why does diamond sparkles stars twinkles?​

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Answer:

Because they want attention

A fulcrum is? A. A support for an inclined plain. B. The place where a lever is supported. C. Measured in Newton-meters. D. Measured in joules.

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a fulcrum is the point which a lever rests or is supported on which it pivots, so B. hope this helps!!

What is the process by which water dissolves certain minerals in the soil and carries them away?

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The correct answer would be LEACHING. When at first thought, it would seem that it is erosion. Erosion not only eliminates the soil minerals, it also washes everything else and that includes the soil. In a different manner, Leaching can happen when certain minute particles of the minerals are melted and mixes with water. All that is left in the soil will be the bigger particles that are not soluble by water. In this manner, only a soil that cannot properly nourish remains as it is stripped off of minerals.

Gaseous helium is in thermal equilibrium with liquid helium at 6.4 K. The mass of a helium atom is 6.65 × 10−27 kg and Boltzmann’s constant is 1.38066 × 10−23 J/K. Determine the most probable speed of a helium atom. Answer in units of m/s.

Answers

Answer:

162.78 m/s is the most probable speed of a helium atom.

Explanation:

The most probable speed:

v_(mp)=\sqrt{(2K_bT)/(m)}

K_b= Boltzmann’s constant =1.38066* 10^(-23) J/K

T = temperature of the gas

m = mass of the gas particle.

Given, m = 6.65* 10^(-27) kg

T = 6.4 K

Substituting all the given values :

v_(mp)=\sqrt{(2* 1.38066* 10^(-23) J/K* 6.4 K)/(6.65* 10^(-27) kg)}

v_(mp)=162.78 m/s

162.78 m/s is the most probable speed of a helium atom.

A dog looking for its bone in the yard, first heads 160.0° for 14.0 m and then turns and heads west for 8.50 m.a. What is the magnitude of the dog's displacement?
b. What is the direction of the dog's displacement?

Answers