A proof should always begin with stating the given information.
True
False

Answers

Answer 1

Answer: A proof should always begin with stating the given information.
True

Answer 2

Answer: True,,, usually mostly

Related Questions

Factor x2 + 11x + 24A. (x + 6)(x + 4) B. (x + 2)(x + 12) C. (x + 3)(x + 8) D. (x + 1)(x + 11) Factor 2m2 + 27m + 70 A. (2m + 7)(m + 10) B. (m + 10)(2m + 7) C. (2m + 3)(m + 20) D. (2m + 7)(m – 10) Factor g2 – 64 A. (g – 1)(g + 64) B. (g + 8)(g – 8) C. (g – 8)(g – 8) D. (g + 8)(g + 8) Factor 49t2 – 9 A. (7t + 3)(7t + 3) B. (7t + 3)(–7t – 3) C. (7t + 3)(7t – 3) D. 7t – 3 The area of a rectangular field is given by the trinomial t2 – 4t – 45. The length of the rectangle is t + 5. What is the expression for the width of the field? A. t – 9 B. t – 5
Select the proper inverse operation to check the answer to 25-13=12
What is equal to 5 radical 3
Explain how to find 40x50 using mental math
Find the mode for the data set. 8.3, 8.7, 4.5, 6.9, 3, 4.2, 11.7, 4 4 6.9 8.3 no mode

A label is placed around a soup can during manufacturing. If the label is represented by the rectangle in the figure, how many square inches is the label? Answer in terms of π.image of a net drawing of a cylinder is shown as two circles each with a radius labeled 4 inches and a rectangle with a height labeled 7.8 inches

94.4π square inches
32π square inches
30.1π square inches
62.4π square inches

Answers

The label on the soup can has area of 62.4π square inches. The Option D is correct.

What is the area of the label on the soup can?

The label is represented by the rectangle in the figure.

The height of rectangle is given as 7.8 inches. The length is equal to the circumference of the circular base of the cylinder.

The circumference of a circle is: 2πr

In this case, the radius of each circle is 4 inches. So, the circumference of each circle is:

= 2π(4)

= 8π

As length of rectangle represents circumference, its length is equal to 8π inches. The height of rectangle is given as 7.8 inches.

We will calculate the area of the rectangle:

Area = Length × Height

Area = (8π) × 7.8

Area = 62.4π.

Answers

$a=0 \n b=1 \n 2(0) + (1) + (c)/(3) =12 \n (c)/(3) =12-1 \n c=11*3 \n max (c) = 33$

A baseball team plays in a stadium that holds 50000 spectators. When the ticket price is $10, the average attendance is 27000. When the price is lowered to $6, the average attendance rose to 39000. Find a demand function, D(q), where q is the quantity or number of spectators and D(q) is linear.

Answers

Answer:

the answer is below

Step-by-step explanation:

Demand seems to be based on price.

Therefore we must consider two things:

that "x" is equal to the price and that "y" is equal to the average attendance.

Thus:

the two points would be:

(x1, y1) = (10,27000)

(x2, y2) = (6.39000)

The slope of a straight line is given by:

m = (y2-y1) / (x2-x1)

we replace:

m = (39000 - 27000) / (6 - 10) = 12000 / -4 = -3000

The equation of a straight line can be expressed like this

y = m * x + b.

where

m is the slope and b is the y-intercept.

we replace

y = -3000 * x + b.

To solve for b, replace x and y with the value of one of the points on the line.

We choose (6.39000). and we replace:

39000 = -3000 * 6 + b

39000 = -18000 + b

39000 + 18000 = b

b = 57000.

if we replace we have:

the equation becomes y = -3000 * x + 57000

since it is the demand and * x is the price.

t = d (x), therefore the equation becomes

d (x) = -3000 * x + 57000.

d (x) = 57000 - 3000 * x.

when x = 0, the price is 0 and the demand will be 57000, which will be more than the stadium can contain because the stadium can only contain 50,000.

So:

when x = 6, the price is 6 and the demand is 57000 - 18000 = 39000.

when x = 10, the price is 10 and the demand is 57000 - 30000 = 27000.

Final Answer:

The demand function D(q) we are looking for is given by D(q) = -3q + 351,000.

Explanation:

We're looking for a linear demand function D(q) of the form D(q) = aq + b, where q is the quantity or number of spectators.

We have two pieces of information here:

1) When the ticket price is $10, the average attendance is 27000, which gives us the equation: 10 * 27000 = a * 27000 + b, i.e 270,000 = 27,000a + b.

2) When ticket price is lowered to $6, the average attendance rose to 39000, which gives us the equation: 6 * 39000 = a * 39000 + b, i.e 234,000 = 39,000a + b.

Let's solve this system of equations to find the values of a and b.

To isolate a, we can subtract the second equation from the first: 270,000 - 234,000 = 27,000a - 39,000a, this simplifies the equation to 36,000 = 12,000a.

So, we divide both sides by 12,000 to solve for a:

a = (270,000 - 234,000) / (27,000 - 39,000) = -3.

So, the coefficient of q in our demand function is -3.

Now, let's find b by plugging in the value of a into the first equation.

Thus, b is equal to 270,000 - (27,000 * -3), which gives

b = 270,000 + 81,000 = 351,000.

At this point, we have the values for our coefficients a and b as -3 and 351,000, respectively.

Therefore, the demand function D(q) we are looking for is given by D(q) = -3q + 351,000.

To know more about demand function:

brainly.com/question/38859172?

#SPJ12

A recent survey by the cancer society has shown that the probability that someone is a smoker is P(S)=0.19. They have also determined that the probability that someone has lung cancer, given that they are a smoker is P(LC|S)=0.158. What is the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S∩LC) ?0.35

0.03

0.02

0.83

Answers

Answer:

P (S∩LC) = 0.03

Step-by-step explanation:

We are given that the probability that someone is a smoker is P(S)=0.19 and the probability that someone has lung cancer, given that they are a smoker is P(LC|S)=0.158.

Given the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).

P (LC|S) = P (S∩LC) / P (S)

Substituting the given values to get:

0.158 = P(S∩LC) / 0.19

P (S∩LC) = 0.158 × 0.19 = 0.03

Find the gcf
14abc and 28a^2b^2c^3

Answers

gcf mean great common factor
so between 14abc and 28a^2b^2c^3 the great common factor will be

between 14 and 28 is 14
btw. a and a^2 is a
btw. b and b^2 is b
btw. c and c^3 is c
---------------------------------
so the gcf will be 14abc

hope helped

Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at y=+- 5/4x.

Answers

Answer:

Step-by-step explanation:

Given that vertex of the hyperbola is

(0,10) and(0,-10)

Hence the hyperbola will have equation of the form

$(y^2)/(a^2) -(x^2)/(b^2) =1$

Since vertex has y coordinate as 10, we have a =10

So equation would be $(y^2)/(10^2) -(x^2)/(b^2) =1$

Since asymptotes are y =±5x/4

we have equation of both asymptotes is

$y^2-(25x^2)/(16) =0\ny^2/25-x^2/16 =0\ny^2/100-x^2/64 =0$

Since hyperbola will have equations same as asymptotes except with difference of constant terms as 1 instead of 0, we have

equation as

$(y^2)/(100) -(x^2)/(64) =1$

The equation of this hyperbola in standard form:
y² / a² + x² / b² = 1.
y = +/- a/b x
a / b = 5 / 4
a = 10
10 / b = 5 / 4
b = (10 · 4) : 5
b = 8
Answer:
The equation of the hyperbola is:
y² / 100 - x²/ 64 = 1

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