Laura wants to show 70 in tens.How many tens will she draw?How do you know?

Answers

Answer 1
Answer: She will draw 7 tens. We know this because 70 divided by 10 is 7. To check, 7 times 10 is 70. 7 tens are in 70.

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The density of a certain material is such that it weighs 7 pounds for every 5.5 cups of volume. Express this density in kilograms per pint. Round your answer to the nearest hundredth.

Answers

Answer:

Density = 1.1546\ kg/pint

Step-by-step explanation:

Given

Mass = 7\ lb

Cups = 5.5

Required

Determine the density in Kg/Pint

Density is calculated as thus:

Density = (Mass)/(Volume)

Density = (7\ lb)/(5.5\ cups)

Convert pound to kg

Density = (7/ 2.205\ kg)/(5.5\ cups)

Density = (3.17515\ kg)/(5.5\ cups)

Convert cups to pint

Density = (3.17515\ kg)/(5.5/2\ pint)

Density = (3.17515\ kg)/(2.75\ pint)

Density = 1.1546\ kg/pint

Final answer:

The density of the given material can be converted from 7 pounds per 5.5 cups to 1.22 kg per pint by adjusting the weight from pounds to kilograms and the volume from cups to pints.

Explanation:

To solve this problem, we need to start by understanding the unit conversions. We know that 1 pound is approximately 0.453592 kilograms and 1 pint is equivalent to 2.11338 cups. Therefore, we need to convert the units of the given density from pounds per cups to kilograms per pint.

First, convert the weight from pounds to kilograms: 7 pounds * 0.453592 kg/pound = 3.17514 kg

Next, convert the volume from cups to pints: 5.5 cups / 2.11338 cups/pint = 2.6 pints

Finally, calculate the new density by dividing the weight by the volume: 3.17514 kg / 2.6 pints = 1.22 kg/pint to the nearest hundredth.

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There are 39 donuts in 3 boxes. Calculate the unit rate of donuts per box. *

Answers

Answer:

13

Step-by-step explanation:

All you do is divide 39 by 3 and that gets 13

A dog weighs two pounds less than three times the weight of a cat. The dog also weighs twenty-two pounds more than a cat. Write and solve an equation to find the weights of the dog and the cat.

Answers

Let's use algebra to represent the weights of the dog and the cat.

Let D represent the weight of the dog in pounds.

Let C represent the weight of the cat in pounds.

According to the information given:

1. The dog weighs two pounds less than three times the weight of a cat, so we can write this as an equation: D = 3C - 2.

2. The dog also weighs twenty-two pounds more than a cat, so we can write this as another equation: D = C + 22.

Now, we have a system of two equations:

1. D = 3C - 2

2. D = C + 22

To solve for the weights of the dog and the cat, we can set these two equations equal to each other since they both equal D:

3C - 2 = C + 22

Now, let's solve for C (the weight of the cat):

3C - C = 22 + 2

This simplifies to:

2C = 24

Now, divide both sides by 2 to find the value of C (the weight of the cat):

C = 24 / 2

C = 12

So, the weight of the cat is 12 pounds.

Now, we can find the weight of the dog using either of the two original equations. Let's use the second equation:

D = C + 22

D = 12 + 22

D = 34

So, the weight of the dog is 34 pounds.

Therefore, the dog weighs 34 pounds, and the cat weighs 12 pounds.

If 4 gallons of milk cost $16.76, how much would 7 gallon of milk cost

Answers

7 gallons of milk will cost $29.33.

What is function?

A function is a relation between a dependent and independent variable.

Mathematically, we can write → y = f(x) = ax + b.

Given is that 4 gallons of milk cost $16.76.

Now, we can write that -

4 gallons of milk cost $16.76

1 gallon of milk will cost $(16.76/4)

7 gallons of milk will cost $(16.76/4 x 7) = $29.33

Therefore, 7 gallons of milk will cost $29.33.

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The answer is $29.33

Which of the following shows why the commutative property doesn't work under subtraction

Answers

Answer with explanation:

Commutative property under subtraction:

If a and b are any two real numbers such that,⇒ a-b =b-a, then we say that ,a and b Satisfy Commutative property under Subtraction.

Take any two real numbers

a=5.6

And,b=7

a-b

=5.6-7

= -1.4

b-a

=7-5.6

=1.4

So,a-b≠b-a

Therefore  , we can say that, real numbers doesn't satisfy commutative property under subtraction.

Option D:5-1≠1-5

This statement shows that, commutative property doesn't work under subtraction.

Hello!  To answer your question, you first need to know what the commutative property is and does.  Down to the basics, it lets you switch around numbers and it would allow me to say that 2+5=7 and 5+2=7.  This property also works in multiplication, because if I take 4*2=8, and 2*4 still equals 8.  Now that I've either refreshed or hopefully helped you to understand the property better, why wouldn't it work under subtraction?  If you switch numbers around in subtraction, will your answer still be the same?  Once you answer that, take a peak at the worksheet!  I hope this has helped in some way, and if you have any further questions send me a question or another message.  Good luck :)

SOMEONE ANSWER THIS QUESTION BEFORE I GO CRAZY!!! The heights, in cm, of some plants in a greenhouse are shown below:

13.5, 12.2, 12.8, 12.8, 12.3, 12, 13.9, 14, 14.2, 12.6

Jack made the following box plot to represent the heights:

box plot shows minimum at 12, first quartile at 12.5, median at 12.8, third quartile at approximately 13.9 and maximum at 14.2

Which of the following did Jack show incorrectly on his box plot?
Median
Minimum
First quartile
Third quartile

Answers

Answer:

The First Quartile is incorrect.

Step-by-step explanation:

Step 1: Order the Numbers

They should looks like this: 12  12.2  12.3  12.6  12.8  12.8  13.5  13.9  14  14.2

Step 2: Find the Median

Since there is an even amount of numbers (10), the median is the sum of the two middle numbers divided by two: 12.8 + 12.8 = 25.6, 25.6 ÷ 2 = 12.8. So, 12.8 is our Median. Since our next steps will involve us figuring out more Medians, we will call this the "original Median." (I would suggest you replace the two numbers with one 12.8 and circle it so you know that this is the Median.)

Step 3: Find the Median for the Quartiles

Now you need to find the Median for the numbers leading up to the "original" Median and the numbers following the "original" Median. Since there is again, an even amount of numbers (4), you will add the two middle numbers of those four and divide the sum. Leading up to the Median: 12.2 + 12.3 = 24.5, 24.5 ÷ 2 = 12.25 (First Quartile). Following the Median: 13.9 + 14 = 27.9, 27.9 ÷ 2 = 13.95 (Second Quartile). (Again, I would suggest you replace each two numbers with the one median and circle it so that you will know that these will be the end of your first and third quartiles.)

Step 4: Find the Quartiles

Referring to Jack's Box Plot, the end of his line should start at 12 (that is the lowest number) and should end at 14.2 (that is the highest number). The "original Median" is 12.8, which will be the line inside of his box. Since we figured out what the median is leading up to the "original Median", his box should start at 12.25, and since we figured out the Median following the "original Median" we know that his box should end at 13.95.

Step 5: Make sure they match up

Let's organize this a bit better; numbers 12 - 12.25 (first quartile), 12.25 - 12.8 (second quartile), 12.8 - 13.95 (third quartile), 13.95 - 14.2 (fourth quartile). All of these match correctly except for our first quartile. It starts correctly at 12 but does not end at 12.25 and instead ends around 12.5.

Incorrect: First Quartile

After working out the problem and figuring out what Jack did wrong, we now know that Jack incorrectly worked the First Quartile.

Hope this helped and that it wasn't too confusing. Also, if it was too confusing, try reading it and working out the problem yourself as you read the steps. :)

First put them in order: 12, 12.2, 12.3, 12.6, 12.8, 12.8, 13.5, 13.9, 14, 14.2. The minimum (the lowest) is 12. The median (the middle number) is 12.8. The third quartlile is approximately 13.9. The first quartile is 12.25. He lied about the first quartile :)