In the rhombus ABCD diagonal DB is congruent to side AD what is the measure of angle A

Answers

Answer 1
Answer: All sides of a rhombus are equal ⇒ AD = AB

AD = AB and AD = DB ⇒ AD = AB = DB ⇒ ΔABD is equilateral  ⇒∠A = 60°

Related Questions

Find solution to logarithm.
Angle M has a measure between 0 and 360 and is coterminal with a –620° angle. What is the measure of angle M?100° 110° 120° 130°
Factor the expression 28x + 49
Can someone help with this plz
The rectangular vegetable garden in 6 feet longer than 2 times its width. If the perimeter is 48 feet, what is the garden's width? Remember, the perimeter of a rectangle is the sum of all its sides.

Use the drop-down menus to locate integers on the number line.A number line going from negative 5 to 7. A is at negative 4, B is at negative 1, C is at 2, D is at 6.

A -4. -1 , 6, 2
B -4, -1, 6 , 2
C -4, -1, 6, 2
D -4, -1, 6, 2

Answers

A is -4

B is -1

C is +2

D is +6

( example: +3 is positive 3

                 -3 is negative 3 )

Hope this helped!

Make x the subject of y=3x-2

Answers

To make x the subject of the equation
y
=
3
x

2
y=3x−2, you can isolate
x
x:

Start with the equation:
y
=
3
x

2
y=3x−2.
First, add 2 to both sides of the equation to isolate the term with
3
x
3x:
y
+
2
=
3
x
y+2=3x.
Finally, divide both sides by 3 to solve for
x
x:
x
=
y
+
2
3
x=
3
y+2

.
So,
x
x is the subject of the equation
y
=
3
x

2
y=3x−2, and it can be expressed as
x
=
y
+
2
3
x=
3
y+2

.

Step-by-step explanation:

y = 3x-2      add '2' to both sides of the equation to get :

y+2 = 3x     Now divide both sides by 3 to get :

(y+2)/3 = x     Done.

Show your work !

Thanks

Answers

For 1st. 
you can solve it by general law or , 
since the coefficient of r^2 = 1 
so u should think of 2 number which if u multiple them gives you 27 and sum of them is 12 and those numbers are 9 , 3 
so the answer (x+9)*(x+3) 
2nd problem :
g^2 - 9 = (g-3)*(g+3) 
3rd problem:
2p^3 + 6p^2 + 3p +9 
1st divide it into two parts 
(2p^3 +6p^2)+    (3p+9)
from the 1st part 
take 2p^2 as a common factor and from part 2 take 3 as a common factor and the equation be like 
2p^2(p+3)  + 3(p+3)
then take (p+3) as a common factor
so (p+3)* ( 2p^2 +3 )                                                         
1: (r+3)(r+9). 2: (g+3)(g-2). 3: (2p^2+3)(p+3). FOIL multiply the first, inside, outside, and last terms. add the inside and outside terms together. :)

Tickets to a baseball game cost $18.95, $12.95, or $9.95. A hot dog and soda combo costs $5.50. The Madison family is having a reunion. They buy 10 tickets in each price category and plan to buy 30 combos. What is the total cost for the tickets and mealsI GOT 583.5 JUST WANT A SECOND CHECK

Answers

Hmmm Interesting: 189.5+129.5+99.5+53
I got 471.5 Dollars....

Because Look If they buy 10 tickets each category it be 18.95 times 10= 189.5
then 12.95 times= 129.5 , Then 9.95 times= 99.5.... Also if they plan to get 30 combos it be also 5.50 times 30,,, You add the answers and it will give you 471.5 dollars. You can try doing it in a caculator (:
You want to times each ticket price by 10 then add them together, then $5.50 by 30.

$18.95*10 = $189.50
$12.95*10 = $129.50
$9.95*10 =  $99.50
$189.50+$129.50+$99.50 = $418.5

Then do $5.50*30 = $165

Then add them both together.
418.5 + 165 = 583.5

You were correct.

Assume that 70% of the cars on a particular freeway are traveling faster than 70 miles per hour. A random sample of 8 cars was observed under normal driving conditions with no police car in sight. What is the probability that 7 or more of them were going faster than 70 miles per hour? A. 0.55 B. 0.30 C. 0.20 D. 0.26 E. 0.49

Answers

E. 0.49

A random sample of 8 cars were observed, under normal driving conditions with no police car in sight. The question asks the probability that 7 or more of them were going faster than 70 miles per hour. Let's try to solve this problem step-by-step.Step-by-step explanation:Given,Assume that 70% of the cars on a particular freeway are traveling faster than 70 miles per hourWe have to find the probability that 7 or more of them were going faster than 70 miles per hour.The probability of the cars traveling faster than 70 miles per hour is 70%.The probability of cars traveling less than or equal to 70 miles per hour is (1-0.7) = 0.3 (from the complement rule of probability).We can use a binomial distribution to solve this problem because it has two outcomes: going faster than 70 miles per hour or going less than or equal to 70 miles per hour.P(X = 7) + P(X = 8) = (8C7)(0.7)^7(0.3)^1 + (8C8)(0.7)^8(0.3)^0= 0.4907 ≈ 0.49Therefore, the probability that 7 or more cars were traveling faster than 70 miles per hour is 0.49. Therefore, the answer is E. 0.49.

Learn more about probability)

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Selena bought a shirt on sale that was 20% less than the original price. The original price was $25. What was the sale price?

Answers

Answer:20 dollars

Step-by-step explanation:

Answer:

20 dollars:)

Step-by-step explanation: