MATHEMATICS HIGH SCHOOL

70 oz of dried cranberries costs $5.60 what is the cost per ounce

Answers

Answer 1

Answer:

The cost per ounce is 12.5.

Given that,

70 oz of dried cranberries cost $5.60

We have to determine,

What is the cost per ounce?

According to the question,

To determine the cost per ounce calculation must be done in a single unit, following all the steps given below.

The cost per ounce is,

70 oz of dried cranberries cost $5.60,

$= (70)/(5.60)\n\n=12.5$

Hence, The cost per ounce is 12.5.

To know more about Fractions click the link given below.

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Answer 2

Answer: Divide 5.60 by 70 and that's the price per ounce

Related Questions

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Jeff found 3 times as many seashells as his sister. Jeff found 39 seashells. How many seashells did his sister find? Write an equation to represent the situation. Then solve the equation to answer the problem.
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Which inequality best represents that ice cream at −5°C is cooler than ice cream at 4°C?−4°C > 5°C −4°C < 5°C 4°C < −5°C 4°C > −5°C
Solve this inequality j/4 -8<4

Word problem: A High School had a musical in which students ($5 tickets) and adults ($7 tickets) attended. If a total of 47 tickets were sold and they made a total of $269. How many student tickets were sold and how many adult tickets were sold?

Answers

Answer:

30 of them were students

17 were adults

Step-by-step explanation:

bunny and rabbit problems

if they were all adults

7 x 47 = 329

329 - 269 = 60

60/ (7-5) = 30

30 of them were students

17 were adults

Solve by substitution
y=x+3
y=2x+5

Answers

y = x+3
y = 2x+5
x+3 = 2x+5
x+8 = 2x
x = 8

I think I did that right, anyway.

y=x+3
y=2x+5

1. Solve for the variable that is easiest to find.
In this case I will solve for x.
y=x+3
-3 -3
y-3=x

2. Now plug in (y-3) for x in the other equation.
y=2(y-3)+5 ~use distributive property
y=2y-6+5 ~combine like terms
y=2y-1
-2y=-2y
-y=-1 ~multiply both sides by -1
y=1

3. Since you have a value for y you can plug it in to solve for x.
y=x+3
1=x+3
-3 -3
-2=x

Answers:
y=1
x=-2

Solve for
a. 7a-2b = 5a b

Answers

For this case we have the following expression:

From here, we must clear the value of a.

We then have the following steps:

Place the terms that depend on a on the same side of the equation:

Do common factor "a":

Clear the value of "a" by dividing the factor within the parenthesis:

Answer:

The clear expression for "a" is given by:

Answer: The required value of a is $(2b)/(7-5b).$

Step-by-step explanation: We are given to solve the following equation for the value of a:

$7a-2b=5ab~~~~~~~~~~~~~~~~~~~~~(i)$

Since there are two unknowns and only one equation , so the value of a will definitely contain the value of b.

The solution of equation (i) for a is as follows:

$7a-2b=5ab\n\n\Rightarrow 7a-5ab=2b\n\n\Rightarrow a(7-5b)=2b\n\n\Rightarrow a=(2b)/(7-5b).$

Thus, the required value of a is $(2b)/(7-5b).$

2x-3y=-143x-2y=-6
if (x,y) is a solution to the system of equations above, what is the value of x-y?
A)-20
B)-8
C)-4
D)8
can you show your work please

Answers

Answer:

Step-by-step explanation:

The given system of equations :

$2x-3y=-14.............................(1)\n3x-2y=-6.........................(2)$

Multiply equation (1) with 3 and equation (2) with 2 , we get

$6x-9y=-42.............................(3)\n6x-4y=-12.........................(4)$

Now subtract equation (4) from equation (3), we get

$5y=30\n\n\Rightarrow\ y=6$

Substitute the value of y in equation (1), we get

$2x-3(6)=-14\n\n\Rightarrow\ 2x=-14+18\n\n\Rightarrwo\ 2x=4\n\n\Rightarrow\ x=2$

Hence, the solution of the system : (x,y)=(2,6)

Now, consider $x-y$ and substitute the value of x and y , we get

$2-6=-4$

The solution to the equation is x - y = -4

Given data ,

To solve the system of equations, we can use the method of substitution or elimination. Let's use the method of elimination:

Multiply the first equation by 3 and the second equation by 2 to make the coefficients of x in both equations equal:

(3)(2x-3y) = (3)(-14)

(2)(3x-2y) = (2)(-6)

Simplifying these equations gives:

6x-9y = -42

6x-4y = -12

Now, subtract the second equation from the first equation:

(6x-9y) - (6x-4y) = (-42) - (-12)

-5y = -30

Divide both sides by -5:

y = 6

Substitute this value of y back into one of the original equations, let's use the first equation:

2x - 3(6) = -14

2x - 18 = -14

2x = 4

x = 2

Now , the value of x - y is given by

A = x - y

A = 2 - 6

A = -4

Hence , the equation is solved

To learn more about equations click :

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You are planning to take to a trip to Montreal, Canada during the month of April and you want to bring clothing that is appropriate for the weather. The daily high temperature X in degrees Celsius in Montreal during April has expected value E(X) = 10.3oC with a standard deviation SD(X) = 3.5oC. You want to convert these Celsius temperatures to oF (degrees Fahrenheit). The conversion of X into degrees Fahrenheit Y is Y = (9/5)X + 32.1. What is E(Y), the expected daily high in Montreal during April in degrees Fahrenheit?
2. What is SD(Y), the standard deviation of the daily high temperature in Montreal during April in degrees Fahrenheit?

Answers

Answer:

1. E(Y) = 50.54°F

2. SD(Y) = 11.34°F

Step-by-step explanation:

We are given that The daily high temperature X in degrees Celsius in Montreal during April has expected value E(X) = 10.3°C with a standard deviation SD(X) = 3.5°C.

The conversion of X into degrees Fahrenheit Y is Y = (9/5)X + 32.

(1) Y = (9/5)X + 32

E(Y) = E((9/5)X + 32) = E((9/5)X) + E(32)

= (9/5) * E(X) + 32 { $\because$ expectation of constant is constant}

= (9/5) * 10.3 + 32 = 50.54

Therefore, E(Y), the expected daily high in Montreal during April in degrees Fahrenheit is 50.54°F .

(2) Y = (9/5)X + 32

SD(Y) = SD((9/5)X + 32) = SD((9/5)X) + SD(32)

= $(9/5)^(2)$ * SD(X) + 0 { $\because$ standard deviation of constant is zero}

= $\beacuse$ $(9/5)^(2)$ * 3.5 = 11.34°F

Therefore, SD(Y), the standard deviation of the daily high temperature in Montreal during April in degrees Fahrenheit is 11.34°F .

There are two types of trees: elm and pine. There should be at least 16 total trees but no more than 30. The ratio of elm trees to pine trees will be 3:2. Give an example of how many trees of each type the designer could plan for the park. Show or explain how you found your answer.

Answers

Answer: 18 pine trees / 12 elm trees

Step-by-step explanation:

To meet the requirement of at least 16 but no more than 30 trees with a 3:2 ratio of elm to pine trees, we can choose:

Elm Trees: 3x

Pine Trees: 2x

Where x is a positive integer. To stay within the given constraints:

3x + 2x ≥ 16 (at least 16 trees)

5x ≥ 16

x ≥ 16/5

x ≥ 3.2

We need to find the largest integer value for x while staying below 30 (no more than 30 trees). Since x must be an integer, the largest valid value for x is 6 (as 7 would exceed 30).

So, for the example:

Elm Trees = 3x = 3 * 6 = 18

Pine Trees = 2x = 2 * 6 = 12

In this case, there would be 18 elm trees and 12 pine trees, totaling 30 trees, which falls within the range of at least 16 but no more than 30 trees and maintains the 3:2 ratio of elm to pine trees.

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