MATHEMATICS COLLEGE

There are twenty classes at each of two middle schools. The number of students in each class at each school is shown in the dot plots below.Number of Students in Each Class at Poplar Middle School
A dot plot. A number line going from 20 to 29 labeled Number of Students. There are 3 dots above 20, 5 above 21, 7 above 22, 4 above 23, 1 above 24, and 0 above 25, 26, 27, 28, and 29.

Number of Students in Each Class at Oak Middle School
A dot plot. A number line going from 20 to 29 labeled Number of Students. There is 1 dot above 20, 2 above 21, 2 above 22, 4 above 23, 3 above 24, 2 above 25, 2 above 26, 2 above 27, 1 above 28, and 1 above 29.

Which statement correctly compares the mean number of students for the data in the plots?
There are about 2 more students in each class at Poplar Middle School than at Oak Middle School.
There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.
There are about 5 more students in each class at Poplar Middle School than at Oak Middle School.
There are about 5 more students in each class at Oak Middle School than at Poplar Middle School.

Answers

Answer 1

Answer:

The dot plot is missing, so i have attached it.

Answer:

B: there are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

Step-by-step explanation:

From the dot plot attached, we can find the average number of students per class for each school.

For Poplar Middle School;

Total number of students = (20 × 3) + (21 × 5) + (22 × 7) + (23 × 4) + (24 × 1) = 435 students.

There are 20 classes.

Thus;

average number of students per class = 435/20 = 21.75

For Oak Middle School;

Total number of students = (20 × 1) + (21 × 2) + (22 × 2) + (23 × 4) + (24 × 3) + (25 × 2) + (26 × 2) + (27 × 2) + (28 × 1) + (29 × 1) = 483

Average number of students per class ; 483/20 = 24.15

Difference in average = 24.15 - 21.75 = 2.40

This implies that there are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

Answer 2

Answer:

Answer:

da answer is B lesss goooo

Step-by-step explanation:

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WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FASTEST!

Answers

Answer:

speed i answerd first U.U

Step-by-step explanation:

Ms. Terry's class is hosting a fundraisingchallenge. The students in her class are
divided into 4 teams. Each team has an
equal number of students. Do you have
enough information to find how many
students are on each team? Explain.

Answers

In being able to find out whether it is possible to know the number of students on each team, there simply isn't enough information to do so.

In order to find out the number of students on each team, the following formula is necessary:

= Number of students in general / Number of teams

The number of teams is 4 so the denominator is present.

We however, do not have the number of students in general so we are unable to find out the number of students in each team.

In conclusion, we do not have enough information to find out the number of students in each team.

Find out more at brainly.com/question/15459630.

You do not have enough information because you need to know how many students are in the class to be able to divide them into 4 equal groups we do know that it has to be a positive integer that can be evenly divided by 4

Prove the trigonometric identity
(tan x + cot x)/(csc x * cos x) = sec^2 x

Answers

Answer:

$(\tan x + \cot x)/(\csc x \cos x)=\sec^2 x$

$\boxed{((\sin x)/(\cos x) + (\cos x)/(\sin x))/((1)/(\sin x) \cdot \cos x)}=\sec^2 x$

$\boxed{((\sin^2 x)/(\sin x\cos x) + (\cos^2 x)/(\sin x \cos x))/((\cos x)/(\sin x))}=\sec^2 x$

$\boxed{((\sin^2 x+\cos^2 x)/(\sin x\cos x))/((\cos x)/(\sin x))}=\sec^2 x$

$\boxed{((1)/(\sin x\cos x))/((\cos x)/(\sin x))}=\sec^2 x$

$\boxed{(1)/(\sin x\cos x) \cdot (\sin x)/(\cos x)}=\sec^2 x$

$(1)/(\cos^2x)=\sec^2x$

$\sec^2x=\sec^2x$

Step-by-step explanation:

Given trigonometric identity:

$(\tan x + \cot x)/(\csc x \cos x)=\sec^2 x$

$\textsf{Use the identities\;\;$\tan x = (\sin x)/(\cos x)$\;,\;$\cot x=(\cos x)/(\sin x)$\;\;and\;\;$\csc x=(1)/(\sin x)$}:$

$\boxed{((\sin x)/(\cos x) + (\cos x)/(\sin x))/((1)/(\sin x) \cdot \cos x)}=\sec^2 x$

Simplify the denominator and make the fractions in the numerator like fractions:

$\boxed{((\sin^2 x)/(\sin x\cos x) + (\cos^2 x)/(\sin x \cos x))/((\cos x)/(\sin x))}=\sec^2 x$

$\textsf{Apply\;the\;fraction\;rule\;\;$(a)/(b)+(c)/(b)=(a+c)/(b)$\;to\;the\;numerator}:$

$\boxed{((\sin^2 x+\cos^2 x)/(\sin x\cos x))/((\cos x)/(\sin x))}=\sec^2 x$

$\textsf{Use\;the\;identity\;\;$\sin^2x+\cos^2x=1$}:$

$\boxed{((1)/(\sin x\cos x))/((\cos x)/(\sin x))}=\sec^2 x$

$\textsf{Apply\;the\;fraction\;rule\;\;$(a)/((b)/(c))=a \cdot (c)/(b)$}:$

$\boxed{(1)/(\sin x\cos x) \cdot (\sin x)/(\cos x)}=\sec^2 x$

Cancel the common factor sin x, and apply the exponent rule aa = a² to the denominator:

$(1)/(\cos^2x)=\sec^2x$

$\textsf{Use the identity\;\;$(1)/(\cos x)=\sec x$}:$

$\sec^2x=\sec^2x$

Answer:

The proof of the trigonometric identity:

We can start by expanding the numerator and denominator. In the numerator, we can use the trigonometric identities tan x = sin x / cos x and cot x = cos x / sin x.

In the denominator, we can use the trigonometric identity csc x = 1 / sin x. This gives us:

$((tan x + cot x))/((csc x * cos x) ) = (((sin x )/( cos x)) + ((cos x )/(sin x)))/(((1)/( sin x)) * cos x)$

`We can then cancel the sin x terms in the numerator and denominator. This gives us:

$((tan x + cot x))/((csc x * cos x) ) = (1 + 1)/(((1 )/(sin x)) * cos x)$

We can then multiply the numerator and denominator by sin x. This gives us:

$((tan x + cot x))/((csc x * cos x) ) = (sin x + sin x)/((1 )/(cos x))$

We can then simplify the expression. This gives us:

$((tan x + cot x))/((csc x * cos x) ) = (2sin x)/((1 )/(cos x)) = (2sin x)/(cos x) = 2tan x$

Finally, we can use the trigonometric identity tan^2 x = sec^2 x - 1 to get:

$2tan x =( 2tan^2 x )/( (sec^2 x - 1))$

This gives us the following identity:

$((tan x + cot x))/((csc x * cos x) ) = sec^2 x$

This completes the proof of the trigonometric identity.

Help due in a bit!subject: Pythagorean Theorem

Do the following lengths form a right triangle?

Answers

Answer:

alright this is an easy question to do u have to use the Pythagorean theorem which is a²+b²=c²

so put the number of the triangle in this form for #1

Step-by-step explanation:

1.6²+9²=8²

=117=64

2.5²+13²=12²

=194=144

1.) Find the first six terms of the sequence.a1 = -6, an = 4 • an-1

A.)0, 4, -24, -20, -16, -12
B.)-24, -96, -384, -1536, -6144, -24,576
C.)-6, -24, -20, -16, -12, -8
D.)-6, -24, -96, -384, -1536, -6144

2. Find an equation for the nth term of the arithmetic sequence.
-15, -6, 3, 12, ...

A.)an = -15 + 9(n + 1)
B.)an = -15 x 9(n - 1)
C.)an = -15 + 9(n + 2)
D.)an = -15 + 9(n - 1)

3. Find an equation for the nth term of the arithmetic sequence.
a14 = -33, a15 = 9

A.)an = -579 + 42(n + 1)
B.)an = -579 + 42(n - 1)
C.)an = -579 - 42(n + 1)
D.)an = -579 - 42(n - 1)

4. Determine whether the sequence converges or diverges. If it converges, give the limit.
48, 8, four divided by three , two divided by nine , ...

A.)Converges; two hundred and eighty eight divided by five
B.)Converges; 0
C.)Diverges
D.)Converges; -12432

5. Find an equation for the nth term of the sequence.
-3, -12, -48, -192, ...

A.)an = 4 • -3n + 1
B.)an = -3 • 4n - 1
C.)an = -3 • 4n
D.)an = 4 • -3n

8. Write the sum using summation notation, assuming the suggested pattern continues.
-9 - 3 + 3 + 9 + ... + 81

A.)summation of the quantity negative nine plus six n from n equals zero to fifteen
B.)summation of negative fifty four times n from n equals zero to fifteen
C.)summation of negative fifty four times n from n equals zero to infinity
D.)summation of the quantity negative nine plus six n from n equals zero to infinity

Answers

try a,b,d,a,then b
sorry if its wrong

A brownie recipe calls for 1 1/2 cups of flour and 1/2 cup of sugar. If you use 1 cup of sugar, how many cups of flour will you use

Answers

Answer:

1 and 2/4

or 2

Step-by-step explanation:

I would say that it is 3 cups of flower. B/c you doubled your sugar so you would double the flower. 1 1/2 + 1 1/2 = 3 cups of flower. Good luck

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