At 400 K, a volume of gas has a pressure of 0.40 atmospheres. What is the pressure of this gas at 273 K?
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The pressure of the sample of gas at 273 K is equal to 0.273 atm assuming the volume is constant.
What is Gay Lussac's law?
Gay-Lussac's law can be described as that when the volume of the gas remains constant then the pressure (P) of the gas and the absolute temperature (T) in a direct relationship.
Gay Lussca's law can be described as mentioned below:
P/T = k
The pressure of gas is directly proportional to absolute temperature of the gas.
P ∝ T ( Volume of gas is constant)
or, P₁/T₁ = P₂/T₂ .................(1)
Given, the initial temperature of the gas, T₁ = 400 K
The final temperature of the gas, T₂ = 273 K
The initial pressure of the gas, P₁ = 0.40 atm
The final pressure of the given gas can be calculated from Gay Lussac's law as:
P₂ = (0.40/400) ×273
P₂ = 0.273 atm
Therefore, the pressure of this gas at 273 K is 0.273 atm.
Learn more about Gay Lussac's law, here:
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a lithosphere
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the answer is bioshere
Answer:
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Explanation:
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Is that a lot ? Not much ?
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