CHEMISTRY COLLEGE

What does dry ashing mean​

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Answer 1
Answer: Dry ashing refers to the use of a muffle furnace capable of maintaining temperatures of 500–600°C. Water and volatiles are vaporized, and organic substances are burned in the presence of oxygen in air to CO 2 and oxides of N 2. Most minerals are converted to oxides, sulfates, phosphates, chlorides, and silicates. Hope this helped!

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A solution of HNO3HNO3 is standardized by reaction with pure sodium carbonate. 2H++Na2CO3⟶2Na++H2O+CO2 2H++Na2CO3⟶2Na++H2O+CO2 A volume of 27.71±0.05 mL27.71±0.05 mL of HNO3HNO3 solution was required for complete reaction with 0.9585±0.0007 g0.9585±0.0007 g of Na2CO3Na2CO3 , (FM 105.988±0.001 g/mol105.988±0.001 g/mol ). Find the molarity of the HNO3HNO3 solution and its absolute uncertainty.
The equation represents the decomposition of a generic diatomic element in its standard state. 12X2(g)⟶X(g) Assume that the standard molar Gibbs energy of formation of X(g) is 4.25 kJ·mol−1 at 2000. K and −63.12 kJ·mol−1 at 3000. K. Determine the value of K (the thermodynamic equilibrium constant) at each temperature.
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Which TWO properties are characteristic of iconic compounds?brittleness
ductility
high melting point
low boiling point
malleability

Answers

Answer : The correct options are, brittleness and high melting point

Explanation :

Ionic compound : Ionic compounds are the compounds which are formed when a metal cation bonded with non-metal anion. The metal cation and non-metal anion bonded with an electrostatic force of attraction.

The properties of ionic compounds are :

Ionic compounds are brittle and hard. They breaks easily into small pieces.

They have high melting point and boiling point.

They conduct electricity in liquid state not in solid state.

Hence, the brittleness and high melting point properties are the characteristic of ionic compounds.

Some characteristics of Ionic compounds by Mimiwhatsup: brittle, high melting point, conducts electricity when molten or dissolved in water.

Match the vocabulary word with the defination.___1.Hypothesis
___2.Variables
___3.Conclusion
___4.Scientific Method
___5.Procedure

a.The steps you take to complete the experiment
b.Factors that changes in an experiment
c.A possible solution to a problem
d.The result of the experiment
e.The process scientist follow to complete an investigation

Answers

Hypothesis - A possible solution to a problem

Variables - Factors that changes in an experiment

Conclusion - The result of the experiment

Scientific Method - The process scientists follow to complete an investigation

Procedure - The steps you take to complete the experiment

Answer:

1. d

2. b

3. d

4. e

5. a

explanation:

there's nothing else to explain

How much heat is required to change the temperature of two cups of water (500 g) from room temperature (25◦C) to boiling? Specific heat of water is c=4.184 J/(g oC) a 78.5 kJ b 15.7 kJ c 157 kJ d 1.57 kJ

Answers

The heat that is required to change the temperature of two cups of water (500 g) from room temperature (25◦C) to boiling

C) 157 kJ

Heat

Heat required= Mass of water x specific heat capacity of water x change in temperature of water required

Q=m* c* delta T

M = 500g

C = 4.184 g°C

Delta T = 100 - 25(room temp) = 75°C

Heat = 500 x 4.184 x 75

Heat = 156900 J

Heat = 156.9 KJ

Heat ~ 157.0 KJ (3.D.P)

Thus, the correct answer is C.

Learn more about "Heat":

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Answer:

C

Explanation:

Heat required= Mass of water x specific heat capacity of water x change in temperature of water required

q \: = m * c * delta \: t

M = 500g

C = 4.184 g°C

Delta T = 100 - 25(room temp) = 75°C

Heat needed= 500 x 4.184 x 75

= 156900 J

= 156.9 KJ

~ 157.0 KJ (3.D.P)

Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you the substance is a pure substance or a mixture, if you can. • Sample A is a solid yellow cube with a total mass of 50.0 g. The cube is put into a beaker filled with 250. mL of water. The cube collapses into a small pile of orange powder at the bottom of the beaker. When this powder is filtered out, dried and weighed, it has a total mass of 29.9 g. If the experiment is repeated with 500. mL of water, the powder that's left over has a mass of 10.0 g. Sample B is 100. g of a coarse grey powder with a faint unpleasant smell. 15. mg of the powder are put into a very thin tube and heated. The powder begins melting at 66.2 °C.The temperature stays constant as the powder slowly melts. After the last of the powder melts, the temperature starts to rise again, eventually reaching 76.0 °C. O pure substance Is sample A made from a pure substance or a mixture? x ? mixture If the description of the substance and the outcome of the experiment isn't enough to decide, choose "can't decide. (can't decide) O pure substance Is sample B made from a pure substance or a mixture? If the description of the substance and the outcome of bstance and the outcome of the experiment isn't enough to decide, choose "can't decide." mixture (can't decide)

Answers

Answer and Explanation: Sample A is a mixture. Solubility is characteristics of each substance, which means a substance can be distinguished from other substances and can be useful to separate mixtures.

In Sample A, when is added different volumes of water, the resulting powder has different mass. This means there are more than one substance forming the yellow cube. Therefore, sample A is a mixture.

Sample B is a puresubstance. Each substance has its own melting point. Whe na pure substance reaches its melting point, temperature is constant until all of that substance is melted. In sample B, temperature is stable at 66.2°C and then, after all the powder is melted, it rises again. Therefore, sample B is a pure substance.

Final answer:

Sample A is a mixture based on the experiment result, while the nature of Sample B is inconclusive.

Explanation:

The result of the experiment with sample A indicates that it is a mixture. When the solid yellow cube is put into water, it collapses into a small pile of orange powder. The mass of the powder that is left over depends on the amount of water used. This suggests that the cube is composed of different substances that can be separated by filtration.

On the other hand, the result of the experiment with sample B is inconclusive, so we can't decide whether it is a pure substance or a mixture. Heating the coarse grey powder causes it to melt at a constant temperature, but there is a temperature increase after the last of the powder melts. This could indicate that the powder is a pure substance with a melting point range, or it could suggest the presence of impurities.

Learn more about Substances and experiments here:

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Most wine is prepared by the fermentation of the glucose in grape juice by yeast: C6H12O6(aq) --> 2C2H5OH(aq) + 2CO2(g) How many grams of glucose should there be in grape juice to produce 725 mLs of wine that is 11.0% ethyl alcohol, C2H5OH (d=0.789 g/cm3), by volume?

Answers

Answer:

123.41 g

Explanation:

Given that the ethyl alcohol produced is 11.0 % by volume.

It means that 1000 mL contains 110 mL of ethyl alcohol

Given that the volume is:- 725 mL

So,

Volume of ethyl alcohol = (110)/(1000)* 725\ mL = 79.75 mL

Given that:- Density = 0.789 g/cm³ = 0.789 g/mL

So, Mass = Density*Volume = 0.789* 79.75\ g = 62.92 g

Calculation of the moles of ethyl alcohol as:-

Molar mass of ethyl alcohol = 46.07 g/mol

The formula for the calculation of moles is shown below:

moles = (Mass\ taken)/(Molar\ mass)

Thus,

Moles= (62.92\ g)/(46.07\ g/mol)

Moles=1.37\ mol

According to the reaction:-

C_6H_(12)O_6_((aq))\rightarrow 2C_2H_5OH_((aq)) +2CO_2_((g))

2 moles of ethyl alcohol is produced when 1 mole of glucose reacts

Also,

1.37 moles of ethyl alcohol is produced when (1)/(2)* 1.37 mole of glucose reacts

Moles of glucose = 0.685 Moles

Molar mass of glucose = 180.156 g/mol

Mass = Moles*Molar mass = 0.685* 180.156\ g = 123.41 g

Help me assiment will close after an hour ​

Answers

Answer :

(a) The molecular equation will be,

CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)

(b) The complete ionic equation in separated aqueous solution will be,

Ca^(2+)(aq)+CO_3^(2-)(aq)+2H^(+)(aq)+2Cl^(-)(aq)\rightarrow Ca^(2+)(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)

(c) The net ionic equation will be,

CO_3^(2-)(aq)+2H^(+)(aq)\rightarrow H_2O(l)+CO_2(g)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The molecular equation will be,

CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)

(b) The complete ionic equation in separated aqueous solution will be,

Ca^(2+)(aq)+CO_3^(2-)(aq)+2H^(+)(aq)+2Cl^(-)(aq)\rightarrow Ca^(2+)(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)

In this equation, Ca^(2+)\text{ and }Cl^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

(c) The net ionic equation will be,

CO_3^(2-)(aq)+2H^(+)(aq)\rightarrow H_2O(l)+CO_2(g)
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