What do you think most likely cause the differences seen in the two graphs for cold spring and normal wearher

Answers

Answer 1

Answer:

Temperature variations in a graph occur as a result of changing environmental conditions and changing temperature.

what is temperature ?

Temperature is a physical quantity which measures hotness and coldness of a body. Temperature measures the degree of vibration of molecule in a body. Temperature is measured in centigrade (°C), Fahrenheit (°F) and Kelvin (K) in which Kelvin (K) is a SI unit of temperature. Absolute scale of temperature means Kelvin scale of temperature. relation between Kelvin(K) and centigrade (°C), °C= K - 273.15 from equation, 273.15 K means 0 °C, which is freezing point of water (ice). when we give temperature to the body, its molecule or atom absorbs thermal energy and vibrate about their mean position. Amplitude of vibration get increases as we go on increasing temperature and for higher temperature force of attraction between molecules gets weaker. Hence for higher temperature, due to weaken the force of attraction between molecule, solid goes into liquid state. and further increase in temperature liquid goes into gaseous state.

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Answer 2

Answer:

Answer:

The tempature changes, and the envronment chnages because of this, therefore making tempature changes in a graph.

Explanation:

sorry if this isnt good

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A 0.700-kg particle has a speed of 1.90 m/s at point circled A and kinetic energy of 7.20 J at point circled B. (a) What is its kinetic energy at circled A? 1.2635 Correct: Your answer is correct. J (b) What is its speed at circled B? 4.54 Correct: Your answer is correct. m/s (c) What is the net work done on the particle by external forces as it moves from circled A to circled B?

Answers

Answer:

a). $E_(kA)=1.2635 J$

b). $V_(B)=4.535(m)/(s)$

c). Δ $E_(t)=8.4635 J$

Explanation:

ΔE=kinetic energy

a).

$E_(kA)=(1)/(2)*m*v_(A) ^(2) \n v_(A)=1.9 (m)/(s)\n m=0.70kg\nE_(kA)=(1)/(2)*0.70kg*(1.9 (m)/(s))^(2) \nE_(kA)=1.2635 J$

b).

$E_(kB)=(1)/(2)*m*v_(B) ^(2)$

$V_(B)^(2)=(E_(kB)*2)/(m) \nV_(B)=\sqrt{(E_(kB)*2)/(m)} \nV_(B)=\sqrt{(7.2J*2)/(0.70kg)} \nV_(B)=4.53 (m)/(s)$

c).

net work= EkA+EkB

$E_(t)=E_(kA)+ E_(kB)\nE_(t)=1.2635J+7.2J\nE_(t)=8.4635J$

The most interpersonal constructive passion response to relational conflict is..

Answers

Answer:

loyalty

Explanation:

On a 30degrees day, there is an explosion. The sound is heard 3.4s after seeing the flash. How far away was the explosion

Answers

Answer:

Distance = 1.2 km (Approx)

Explanation:

Given:

Temperature (T) = 30°C

Total Time taken (t) = 3.4 Sec

We know that sound increases in the air sound increase nearly 0.60 m/s for every sound with temperature.

Speed of sound = 331 m/s

So,

V = (331 + 0.60T) m/s

V = 331+(0.60×300C) m/s

V = 349 m/s

Distance = speed × time

Distance = 349 × 3.4

Distance = 1,186.6 m

Distance = 1.2 km (Approx)

1 microgram equals how many milligrams?

Answers

Answer: 1 microgram is equal to 0.001 miligrams

Explanation: The factor micro is equal 10^-3 while the factor mili is equal to 10^-3 so to converte the micro to mile we have to multiply by 0.001.

Exposure to what type of radiant energy is sensed by human skin as warmth? x-rays ultraviolet infrared gamma rays

Answers

infrared radiant energy is sensed by human skin as warmth. Hence option C is correct.

What is radiation ?

Radiation in physics is the emission or transmission of energy as waves, particles, or both, via space or a material medium.[1][2] This comprises:

electromagnetic radiation, which includes gamma radiation, x-rays, microwaves, infrared, visible light, and ultraviolet radiation

Particle radiation includes beta radiation, proton radiation, neutron radiation, and other particles with non-zero rest energies.

ultrasonography, sound, and seismic waves (reliant on a physical transmission medium) are examples of acoustic radiation.

gravity radiation, which manifests as gravitational waves or ripples in spacetime's curvature

Depending on the energy of the emitted particles, radiation is frequently divided into ionising and non-ionizing categories. More than 10 eV is carried by ionising radiation, which is sufficient to ionise atoms, molecules.

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i think it is infared

M = 30.3kg
M = 40.17kg 9
R = 0.5m
G = 6. 67x10^11
F ?