Please help with 1 , and 2 I really don’t understand this!
Answers
2. A
hope this helped
Answer:
1.B
2.A
Hope it helped all of you....
Related Questions
Find the equation of the perpendicular bisector of a line segment whose end points are (-3,9) and (-1,5)
3x+5+19x+11 help please
1. What is the equation of the line that goes through the point and is parallel to the line represented by the equation below?y=-5/6x+3A. y=-5/6x+4B. y=-5/6x-6C. y=-5/6x-4D. y=-5/6x+6Which equation produces a line that is perpendicular to the line represented by the function below?y=2/5x+9A. 5x+2y=4B. 2x-5y=8C. 5x+2y=-3D.2x+5y=-7What is the slope of the line that is parallel to the line represented by the equation below?4x-5y+-1A 4/5B -4/5C 5/4D -5/4
What is the solution of the equation w - 2 = -3
Answers
hypotenuse=6√2
let us suppose leg =a
using Pythagorean theorem
a^2+a^2=(6√2)^2
2a^2=36*2
diving by 2 on both sides
a^2=36
taking square root on both sides
√a^2 =√36
a=6
therefore
the leg of each isosceles right triangle is 6
Answers
dimes is 0,1 o dolar -d
quarters is 0,25 of dolar -q
dimes =2nickels
d=2n
quarters=2dimes
q=2d=4n
12,5=n(0,05)+2n(0,1)+4n(0,25)
12,5=0,05n+0,2n+n
12,5=1,25n
n=10
q=4n=40
There are 40 quarters
Answers
Answer:
Step-by-step explanation:
0.2
Total number of students: 90
Total number of students who were cast: 1/3 x x 90 = 30
Number of students who got a major role: 6
Fraction of students who got a major role: 6/30
Fraction of students who got a major role: 1/5
1/5 as a decimal is 0.2
So in conclusion, the fraction of students who were cast and got major roles is 1/5 and the answer as a decimal is 0.2!
Answers
Model D :
x = 2, y = 1.959
y = 0.0000872 · 2³ - 0.00989 · 2² + 0.403 · 2 + 1.192 = 1.968
.... ...
x = 82, y = 15.817
y = 0.000873 · 82³ - 0.00989 · 82² + 0.403 · 82 + 1.192 = 15.818
Answer:
D ) y = 0.0000872 x²- 0.00989 x² + 0.403 x + 1.192
Answers
If you want to go further, you can figure out that
y= 7-x
but that's about it.
x - 7 = 7 - 7 - y
x - 7 = -y
x + 7 = y
y = x + 7
Answers
Answer :
All values of \( c \), specifically \( c = 49, 100, 144, \) and \( 169 \), can make a polynomial a perfect square trinomial depending on the other terms of the polynomial.
Step-by-step explanation :
1. Understanding Perfect Square Trinomials :
A perfect square trinomial is one that can be written in the form:
\[ (ax + b)^2 = a^2x^2 + 2abx + b^2 \]
From this formula, the value \( c \) would be equivalent to \( b^2 \), and the coefficient of the linear term (the term with \( x \)) would be \( 2ab \).
2. Analyzing Given Options :
- Option 1 : c = 49
For \( c = 49 \), \( b^2 = 49 \) which implies \( b = \pm 7 \). The middle term would then be \( 2a(7) = 14a \).
- Option 2 : c = 100
For \( c = 100 \), \( b^2 = 100 \) which means \( b = \pm 10 \). The middle term would then be \( 2a(10) = 20a \).
- Option 3 : c = 144
For \( c = 144 \), \( b^2 = 144 \) which translates to \( b = \pm 12 \). This makes the middle term \( 2a(12) = 24a \).
- Option 4 : c = 169
For \( c = 169 \), \( b^2 = 169 \) which gives \( b = \pm 13 \). Consequently, the middle term would be \( 2a(13) = 26a \).
3. Conclusion :
Without specific details on the polynomial or its middle term, we can deduce that any of the provided options for \( c \) can result in a perfect square trinomial if the linear term of the polynomial matches the \( 2ab \) value corresponding to that \( c \).