MATHEMATICS HIGH SCHOOL

A pole is 65 feet tall. A support wire isattached to the top of the pole and secured
to the ground 33 feet from the base of the
pole. Find the approximate length of the
wire.
A 32 feet
© 56 feet
0 60 feet
B 73 feet

Answers

Answer 1

Answer:

Answer:

A) 35 feet

Step-by-step explanation:

If the pole is 65 feet tall

and the wire is attached to the top of it and secured 35 feet from the bottom of it. Then the wire is 65-33=32

Related Questions

What is the word form of 1.604
All four sided polygons are quadrilaterals
What is 5.63×10−6in decimal form?a. 0.00000563 b. 0.000000563 c.5,630,000d. 56,300,000
The perimeter of an equilateral triangle is 12\/3 cm. Find the radius, apothem and area of the equilateral triangle.
There are 70 students in a school band. 40%are sixth graders,20% are seventh graders and the rest are eighth graders.How many sixth graders are there.

Domain is the set of all input values, while range is the set of all:

Answers

all output values. This is because the domain of a function is the set of all possible x-values that you will put into the equation while the range is the set of all possible y-values, the solution.

Need help with all!!! Please help

Answers

For number nine the answer is 20

Carl drew a rectangle with a width of 8 in. And a length of 32 in. Which rectangles are not similar to Carl’s rectangle? Select ALL that apply.

Answers

Answer:

1) A rectangle with width of 10 cm and length of 44 cm.

4) A rectangle with width of 9 mm and length of 45 cm.

Step-by-step explanation:

Given:

Length of the rectangle = 32 in.

Width of the rectangle = 8 in.

Now we will find the ratio of length by width.

$(length)/(width)= (32)/(8) = (4)/(1) \ \ \ \ equation \ 1$

Now we need to find from the given Option which rectangles are not similar to Carl's Rectangle.

So we will check for each.

1) A rectangle with width of 10 cm and length of 44 cm.

Now we will find the ratio of length by width.

$(length)/(width)= (44)/(10) = (11)/(5) \ \ \ \ equation \ 2$

Now we know that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $\neq$ equation 2

Hence This rectangle is not similar to Carl's rectangle.

2) A rectangle with width of 2.5 inch and length of 10 inch.

Now we will find the ratio of length by width.

$(length)/(width)= (10)/(2.5) = (4)/(1) \ \ \ \ equation \ 2$

Now we know that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $=$ equation 2

Hence This rectangle is similar to Carl's rectangle.

3) A rectangle with width of 23 cm and length of 92 cm.

Now we will find the ratio of length by width.

$(length)/(width)= (92)/(23) = (4)/(1) \ \ \ \ equation \ 2$

Now we know that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $=$ equation 2

Hence This rectangle is similar to Carl's rectangle.

4) A rectangle with width of 9 mm and length of 45 cm.

Now we will find the ratio of length by width.

$(length)/(width)= (45)/(9) = (5)/(1) \ \ \ \ equation \ 2$

Now we know that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 $\neq$ equation 2

Hence This rectangle is not similar to Carl's rectangle.

To convert from square miles to square feet,what operation will you use

Answers

The correct one is multiplication.

-- Take the number of square miles.

-- Multiply it by the fraction (5,280 feet / 1 mile)² .

-- After canceling things where possible, simplifying, and
cleaning up the product, what you have is the same area
expressed in square feet.

Multiplication because to convert from a larger unit, miles, to a smaller unit, feet, you multiply the number of miles by the number of feet in a mile to get the total number of feet.

Solve the following equation. Remember to check for extraneous solutions 7/(b+3) + 5/(b-3) = (10b-2)/(b²-9).