1. The Hamiltons are installing a new pool in their backyard. The scale drawing below represents the new pool, where 1 centimeter represents 5 feet. 4 cm 6 cm If the area of the Hamiltons' backyard is 900 square feet, how many square feet of their backyard will NOT be taken up by the pool? Round your answer to the nearest whole number.​

Answers

Answer 1
Answer:

The number of square feet of their backyard will NOT be taken up by the pool should be 100 square feet.

Calculation of the number of square feet;

Since 1  centimeter represents 5 feet. 4 cm 6 cm And, the area of the Hamiltons' backyard is 900 square feet.

So here it can be like

4cm (5) = 20ft

6cm (5) = 40ft

Now

20ft : 40ft pool

20(40) = 800 square ft

So,

= 900sq ft - 800sq ft

= 100 square feet

Learn more about area here: brainly.com/question/17758676

Answer 2
Answer:

Answer:

175

Step-by-step explanation:

Because why would i lie?


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Costco sells chicken for $2.25 per pound. What would be the cost of 2 4 5 lb of chicken?

2. Jack’s parents were planning a big birthday party for him. Answer the questions below. Show your work for all parts.a. His parents spent $4.49 on each of 6 goodie bags. How much did they spend on goodie bags?

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Answers

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

24 minutes

Step-by-step explanation:

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Answer:

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I really don't know how to calculate this question.

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Answers

Answer:

9\,\sin(60^\circ), which is equal to \displaystyle (9√(3))/(2).

Step-by-step explanation:

An angle of 45^\circ corresponds to an isosceles right triangle: the length of the two legs (adjacent and opposite) would be equal. Accordingly:

\displaystyle \tan(45^\circ) = \frac{\text{Opposite Leg}}{\text{Adjacent Leg}} = 1.

Let A denote the measure of an angle. Double-angle identity for sine:

2\, \sin(A) \cdot \cos(A) = \sin(2\, A).

By this identity:

\begin{aligned}& (2\, \cos(30^\circ)) \cdot (3\, \sin(30^\circ)) \n &= 3\, (2\, \cos(30^\circ) \cdot \sin(30^\circ)) \n &= 3\, \sin(2 * 30^\circ) \n &= 3\, \sin(60^\circ)\end{aligned}.

(A = 30^\circ in this instance.)

Hence:

\begin{aligned}&(3\, \tan(45^\circ)) \cdot (4\, \sin(60^\circ)) - (2\, \cos(30^\circ)) \cdot (3\, \sin(30^\circ)) \n &= 12\, \sin(60^\circ) - 3\, \sin(60^\circ) \n &= 9\, \sin(60^\circ)\end{aligned}.

\displaystyle \sin(60^\circ) = (√(3))/(2). Therefore, \displaystyle 9\, \sin(60^\circ) = (9 √(3))/(2).