If log 6=a, then log 600= ?

Answers

Answer 1

Answer: $\log 600 = \log (100 \cdot 6)= \log 100 + \log 6 = \log 10^2 + \log 6 = \n 2 \log 10 +\log 6 =2+\log 6 = \boxed{a+2} \n \hbox{From formulas:} \n \log a + \log b = \log (ab) \n \log a^b = b\log a$

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mario went on a hike with his friends. they hiked 2,24 miles an hour for 8 hour. how many miles did they hike in all
Find the coordinates of the midpoint of the segment given the endpoints p( -3,-7) and q (3, -5)

C. Read and analyze the problem, then solve.1. Mother bought 20 meters of curtain material. She used 8 metres for the living room, 73
meters for the dining room, and the rest for the kitchen. How many meters did she use for the
curtain in the kitchen?

Answers

Given parameters:

Total length of curtains bought = 20m

She used 8m for the living room

She used 7m for the dining room

unknown:

Quantity used for the kitchen = ?

Solution:

Quantity used for the kitchen = Total length - (living room + dining room)

Input the parameters given solve;

Quantity used for the kitchen = 20 - (8 + 7) = 5m

The length of curtain used for the kitchen is 5m

Suppose you deal three cards from a regular deck of 52 cards, What is the probability that they will all be jacks?

Answers

Answer:

$0.00018$

Step-by-step explanation:

The number of ways you can draw 3 cards from the deck of 52 cards is,

$\dbinom{52}{3}=(52!)/(3!\ 49!)=(52* 51* 50)/(6)=22100$

Out of 52, 4 cards are jacks. So the number of ways you can draw 3 jacks out of 4 is,

$\dbinom{4}{3}=(4!)/(3!\ 1!)=(24)/(6)=4$

So, the probability three cards from a regular deck of 52 cards will be,

$(4)/(22100)=0.00018$

Final answer:

The likelihood of pulling three Jacks from a 52-card deck is calculated by multiplying together the probabilities of pulling a Jack on each of the three cards drawn. This comes to approximately 0.000181, or 0.0181%

Explanation:

The question you're asking is about the probability of drawing three Jacks from a 52-card deck. A standard deck has 52 cards, and there are 4 Jacks in the deck. So, when you're dealing the first card, the probability that it's a Jack is 4 out of 52, or 1 out of 13. After one Jack has been dealt, there are now only 3 Jacks left and 51 cards total, so the probability that the second card is a Jack is 3 out of 51. For the third card, because there are only 2 jacks left out of 50 cards, the probability is 2 out of 50. Because you want all these events to happen, you would multiply these probabilities together. Therefore, the probability of getting three Jacks is (4/52) * (3/51) * (2/50), which simplifies to approximately 0.000181.

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If the sum of the measures of ∠1 and ∠2 is 180°, what is the sum of the measures of ∠3 and ∠4?A) 360°
B) 120°
C) 90°
D) 180°

Answers

in any 4-sided shape, the angles add to 360. if angles 1 & 2 are 180, 3 & 4 are also 180. the answer is D

Final answer:

The sum of the measures of ∠3 and ∠4 is 180°.

Explanation:

To find the sum of the measures of ∠3 and ∠4, we need to know the relationship between these angles and ∠1 and ∠2. If the sum of the measures of ∠1 and ∠2 is 180°, this means that these two angles are supplementary. In other words, they add up to 180°. Since angles ∠3 and ∠4 are corresponding angles with ∠1 and ∠2, they will also be supplementary to each other. Therefore, the sum of the measures of ∠3 and ∠4 is 180° as well.

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The parent function f(x)=log^3x has been transformed by reflecting it over the X axis, stretching it vertically by a factor of two and shifting it up three units. Which function is representative of this transformation

Answers

Answer:

Step-by-step explanation:

a teacher needs 70 lengths of string cut to 40 cm each. If balls of string are 10 m long how many balls will be needed

Answers

The balls need for the given question is 28.

Given-

Total required string is 70.

The length of the required string is 40 cm.

The length of the ball of string is 10 m.

Convert the length of ball in centimetre from meter. We know that one meter has hundredcentimetres. Thus ten meters is,

$=10* 100$

$=1000$

Hence the length of the ball of string is 1000 cm.

Now the string is cut thus we need two lengths of string. Therefore,

$=40* 2$

$=80$

Two length of string is 80 cm.

Now this is the half times the lengths of the seventy. Thus,

$=(70)/(2) *{80}$

$=2800$

For this 2800 cm string we need 1000 cm string balls $n$ are,

$n=(2800)/(1000)$

$n=28$

Hence, the balls need for the given question is 28.

For more about the units follow the link below-

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A meter is 100 cm. A ball of string has 10m of string, and you multiply 10m by 100cm, you get 1,000cm. Then you multiply 40cm by 2, and you get 80cm, or two lengths of string. Then you multiply 35, which is half of 70, by 80, and that is 2,800 cm.
2,800÷40cm=70
And 100cm=1m.
The teacher will therefore need 28 balls of string.

How many times does 6 go into 312

Answers

It can go in 52 times. Just divide 312 from 6.

$Hope - this -helped :)$

52 times is the answer : )

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For the school play , adult tickets cost $4 and children cost $2. Natalie is working at the ticket counter and just sold $20 worth of tickets. What are all of the possible ticket combinations for $20 worth tickets?

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Variable y varies directly with variable x, and y = 6 when x = 4. Enter the constant of variation in lowest terms. y =__x