Point M is the midpoint of segment QR. If QM = 16 + x and MR = 2(x + 2), find the length of QM.
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QM+MR=QR
16+x+2(x+2)=QR
16+x+2x+4=QR
20+3x=QR
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A telephone pole 13 1/3 feet tall casts a shadow of 16 feet when a person casts a shadow of 6 feet. How tall is the person?
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P(x) x^3+x^2-x-1Find all zeros of p (x)
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Answer:
Step-by-step explanation:
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If you pull the information into a mathematical context, you'll notice it is asking for the highest common factor of the 2 numbers
Let's put both of them in prime factorization:
96 = 2^5 x 3
72 = 2^3 x 3^2
Now pick out what is common in these
2^3 x 3 = 24
Thus it would be 24 feet
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It is a binomial with a degree of 3.
It is a trinomial with a degree of 2.
It is a trinomial with a degree of 3.
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Answer: B. it is a binomial with a degree of 3
Step-by-step explanation:
3xy² + 5x²y
There are two terms so it is a BINOMIAL
xy² has a degree of 1 + 2 = 3
x²y has a degree of 2 + 1 = 3
The largest sum of exponents in a term is three so DEGREE is 3
The true statement about the polynomial is (a) It is a binomial with a degree of 2.
What are polynomials?
Polynomials are algebraic expressions that are represented by terms and factors
The polynomial is given as:
The above polynomial has two terms; so it is a binomial
The highest power of the polynomial is 2; so it has a degree of 2
Hence, the true statement about the polynomial is (a) It is a binomial with a degree of 2.
Read more about polynomials at:
b. {2,2,4}
c. (1,2, sqrt of 3 wouldn't it be B because it has all even numbers?
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The only set of numbers that could be the sides of a right triangle is **(b) {2, 2, 4}**.
The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Therefore, in order for a set of numbers to be the sides of a right triangle, the following equation must hold:
hypotenuse^2 = leg1^2 + leg2^2
Let's check each of the given sets:
(a) {2, 3, √13}
hypotenuse^2 = √13^2 = 13
leg1^2 = 2^2 = 4
leg2^2 = 3^2 = 9
13 ≠ 4 + 9
Therefore, {2, 3, √13} cannot be the sides of a right triangle.
(b) {2, 2, 4}
hypotenuse^2 = 4^2 = 16
leg1^2 = 2^2 = 4
leg2^2 = 2^2 = 4
16 = 4 + 4
Therefore, {2, 2, 4} can be the sides of a right triangle.
(c) {1, 2, √3}
hypotenuse^2 = √3^2 = 3
leg1^2 = 1^2 = 1
leg2^2 = 2^2 = 4
3 ≠ 1 + 4
Therefore, {1, 2, √3} cannot be the sides of a right triangle.
Therefore, the only set of numbers that could be the sides of a right triangle is **(b) {2, 2, 4}**.
Learn more about sides of a right triangle here:
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Final answer:
The set of numbers that could be the sides of a right triangle is {2,3, sqrt of 13}.
Explanation:
To determine whether a set of numbers could be the sides of a right triangle, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
Let's check each set of numbers:
a. {2,3,√13}
b. {2,2,4}
c. (1,2,√3)
For set a, the sum of the squares of 2 and 3 is 13, which is equal to the square of √13. Therefore, set a could be the sides of a right triangle.
For set b, the sum of the squares of 2 and 2 is 8, which is not equal to the square of 4. Therefore, set b could not be the sides of a right triangle.
For set c, the sum of the squares of 1 and 2 is 5, which is not equal to the square of √3. Therefore, set c could not be the sides of a right triangle.
Therefore, the set of numbers that could be the sides of a right triangle is a. {2,3,√13}.
Learn more about right triangle here:
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