What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is 3.611 × 10-15 joules? (Planck's constant is 6.626 × 10-34 joule seconds) 5.50 × 10-11 Hz 2.39 × 10-50 Hz 5.45 × 1018 Hz 1.633 × 1027 Hz

Answers

Answer 1

Answer: If i was feeling harsh today, I'd say the answer to your question is impossible to obtain due to the fact that photons do not emit radiation, photons ARE the radiation emitted. Though for the sake of it, here is the method...

The simple method:

E=hf

therefore f=e/h

f=(3.611x10^-15) / 6.63x10^-34)

Answer: 5.45x10^18

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When you calculate the SLOPE of a line segment, what does the SLOPE represent? (Choose all that apply) the Distance traveled the Displacement the Velocity the Acceleration None of the above

Answers

Answer:

Please find the answer in the explanation

Explanation:

When you calculate the SLOPE of a line segment, what does the SLOPE represent? (Choose all that apply) the Distance traveled the Displacement the Velocity the Acceleration None of the above

The slope of any time graph can not give you distance or displacement except for position - time graph.

When you plot either distance or displacement against time, that is, distance time graph or displacement time graph, you can get speed or velocity as the slope of the line segment.

You can only acceleration as a slope in a line of best fit if velocity is plotted against time. That is, in a velocity time graph.

A stone is dropped from a height of 7.70 m how fast is it going when it is 5.25 m above the ground

Answers

The velocity of the stone when it is 5.25 m above the ground is determined as 6.93 m/s.

Velocity of the stone

The velocity of the stone at the given displacement is calculated as follows;

K.E = ΔP.E

¹/₂mv² = mgh

v = √2gΔh

v = √[2(9.8)(7.7 - 5.25)]

v = 6.93 m/s

Thus, the velocity of the stone when it is 5.25 m above the ground is determined as 6.93 m/s.

Learn more about velocity here: brainly.com/question/4931057

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Eric traveled east for 150 miles in 2 hours. Then he went west for 40 miles in 1 hour. What is the average velocity?

Answers

Answer:

190 is the average velocity.

Explanation:

Just add them together

Which of the following variables do you need to know in order to calculate the partial pressure of a gas? (We are going to ignore water vapor here.) Check all that apply.
a. the volume of the container that the gas is in
b. the percentage of the gas
c. the percentage of the other gases that comprise the atmosphere
d. the total pressure in the atmosphere

Answers

Answer:

C.)

Explanation:

i said c because. idk i guessed sry

d, the total pressure in the atmosphere

The peak of the trajectory occurs at time t1. This is the point where the ball reaches its maximum height ymax. At the peak the ball switches from moving up to moving down, even as it continues to travel horizontally at a constant rate.. . Part C. . What are the values of the velocity vector components v1,x and v1,y (both in m/s) as well as the acceleration vector components a1,x and a1,y (both in m/s2)? Here the subscript 1 means that these are all at time t1.. . A) 0, 0, 0, 0. B) 0, 0, 0, -9.80. C) 15.0, 0, 0, 0. D) 15.0, 0, 0, -9.80. E) 0, 26.0, 0, 0. F) 0, 26.0, 0, -9.80. G) 15.0, 26.0, 0, 0. H) 15.0, 26.0, 0, -9.80

Answers

Final answer:

At the peak of its trajectory, the ball's vertical velocity (v1,y) is zero, whereas its horizontal velocity (v1,x) maintains its consistency. The accelerations a1,x and a1,y are 0 and -9.8 m/s² respectively.

Explanation:

The physical concept analyzed here is projectile motion. Considering the trajectory of a ball, we can separate its motion into horizontal and vertical components. At the peak of its trajectory (time t1), the ball's vertical velocity (v1,y) is zero, because it temporarily stops moving upwards before it begins to fall again. However, since there is no acceleration in the horizontal direction (a1,x), the ball keeps moving horizontally with constant velocity (v1,x).

The acceleration in the vertical direction (a1,y) is still the acceleration due to gravity (-9.8 m/s²). This is because even at the peak of the trajectory, the ball is still accelerating downwards. Therefore, the correct answer should include v1,y = 0 m/s, v1,x = consistent value, a1,x = 0 m/s², and a1,y = -9.8 m/s². So the most probable answer is D) 15.0, 0, 0, -9.80, assuming the ball's horizontal velocity is 15 m/s. Please check the exact value of horizontal velocity (v1,x) in the settings of your problem.

Learn more about Projectile motion here:

brainly.com/question/29545516

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How does the muscular system help humans maintain posture?

Answers

The muscular system is an organ system composed of skeletal, smooth and cardiac muscles. This system allows movement of the body, maintains posture, and circulates blood throughout the body.

>Muscles continually align themselves vertically to help maintain posture.

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