How many solutions does the equation have?a+5=1/5(15+5a)

A. one solution B. infinite solutions C. no solution

Answers

Answer 1
Answer: The first thing we need to do is distribute on the right side. 1/5 * 15 is 3, and 1/5* 5a is 1a, so now the equation is a+5 = 3+a
Subract 3 from each side and you have a+2=a
There are no solutions because any number +2 will never equal itself. This is incorrect, because the two sides are not equal to each other, so there are no solutions(:
I hope that helped(:

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How resolve x+1-2- (-x+3)=6-1(1-1)

Answers

x-1+x-3=6-1(0)

2x-4=6

2x=10

x=5

x+1-2-(-x+3)=6-1(1-1)\n\nx+(1-2)-(-x)-(+3)=6-1(0)\n\nx+(-1)+x-3=6-0\n\nx-1+x-3=6\ \ \ \ |\text{use commutative and associative property}\n\n(x+x)+(-1-3)=6\n\n2x-4=6\ \ \ \ |\text{add 4 to both sides}\n\n2x=10\ \ \ \ \ |\text{divide both sides by 2}\n\n\boxed{x=5}

in a first aid kit the ratio of large bandages to small bandages is 5 to 2. Based on this ratio, how many large bandages are in the kit if there are total of 60 bandages?

Answers

The best way to answer this question is to set up the first sentence as a ratio of large bandages to total bandages. You would write 5 large bandages to 7 total bandages to 7 total bandages.  Then you would make this equivalent to x number of large bandages to 60 total.  It would look like this 5:7 = x:60.  You could use cross products to multiply 60 by 5 to get 300.  7 times x also should equal 300.  Unfortunately, this example will not leave us with a whole number of bandages, but 300/7 is a repeating decimal or a mixed number (42 6/7 large bandages). 

Train A arrives at central station on the hour and every 12 minutes. Train B arrives on the hour and every 15 minutes. When do both trains arrive at thesame time?

A) On the hour and 30 minutes past the hour
B) On the hour and 15 minutes to the hour
C) On the hour and 27 minutes past the hour
D) On the hour

Please explain why you chose the answer and how you achieved it

Answers

2________24___________30
3________36___________45
4________48___________60
5________60, found common minute count. 

60 minutes.__________A____________B
__________0____________0
1________12___________15

Brian had 42 class fair tickets to sell. He sold 5/6 of the tickets . How many tickets did Brian sell?

Answers

Answer:  Brian sold 35 tickets.

Step-by-step explanation:  Given that Brian had 42 class fair tickets to sell and he sold (5)/(6) of the tickets.

We are to find the number of tickets that Brian sold.

We have

Total number of tickets that Brian had = 42.

Since he sold five-sixth of the total tickets that he had, so the number of tickets that Brian sold is given by

N_s=(5)/(6)* \textup{total number of tickets}=(5)/(6)*42=5*7=35.

Thus, Brian sold 35 tickets.

35 becauses 7 times 5 = 35

Please show work, will mark brainliest

Answers

Answer:

The radius of the can, rounded to the nearest hundredth, is 530.66.

Step-by-step explanation:

We want to do the reverse of the formula for V, which is pi(r)^2(h).

to isolate r.

Let's start by writing an equivalent equation to V = \pir^(2)h by solving for r

\sqrt[]{(V * \pi )/(h) } = r

Now, substitute and solve for r

1014 * 3.14 / 6 = 530.66

15 is more than a number x

Answers

Given that 15 is more than a number x, we can represent it by the following inequality:

x < 15

Hope that helped =)