MATHEMATICS COLLEGE

A survey of 1000 young adults nationwide found that among adults aged 18-29, 35% of women and 30% of men had tattoos. Suppose that these percentages are based on random samples of 500 women and 500 men. Using a 2.5% level of significance, can you conclude that among adults aged 18-29, the proportion of all women who have tattoos exceeds the proportion of all men who have tattoos?

Answers

Answer 1

Answer:

Answer:

95% confidence interval for adults in age group 18-29 is (-0.007, 0.107)

Step-by-step explanation:

Given

N1 = n2 = 500

% of males = 0.30

% of females = 0.35

95% confidence interval

(p2-p1) + z(0.025) sqrt (p1q1/n1 + p2q2/n2) and (p2-p1) - z(0.025) sqrt (p1q1/n1 + p2q2/n2)

Substituting the given values, we get –

(0.35-0.30) + 1.96 sqrt (0.3*0.7/500 + 0.35*0.65/500) and (0.35-0.30) - 1.96 sqrt (0.3*0.7/500 + 0.35*0.65/500)

0.05 + (1.96 *0.029) and 0.05 - (1.96 *0.029)

0.05 + 0.057 and 0.05 – 0.057

(-0.007, 0.107)

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Answers

Answer:

y = 3x + 3

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer: 9000

This is because the given value is closer to 9,000 than it is to 10,000.

The digit in the thousands place is 9. The digit to the right of this is 0, which is not 5 or greater. So we round down to the nearest thousand. So basically everything after the 9 is replaced with 0.

9000 would be the correct answer because it is closer to 9000 than it is 10,000

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Answers

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Answers

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