A bouncy ball is dropped such that the height of its first bounce is 2.75 feet and eachsuccessive bounce is 69% of the previous bounce's height. Write a recursive formula
to represent the height of the nth bounce of the ball.
A bouncy ball is dropped such that the height of - 1

Answers

Answer 1
Answer:

The value 2.75 goes in the first box, since it's the first term.

The expression 0.69*a_(n-1) goes in the second box. The second line says "to get the nth term, we multiply the previous term by 0.69"


Related Questions

Solve 2cos2x + cosx − 1 = 0 for x over the interval [0, 2pi ).
What is the distance between the points (3,7) and (15,16)?
About 7/10 of the human body is water. If a person weighs 130 pounds about how many pounds are water?
The sum of the first 10 terms of an arithmetic sequence is 235 and thesum of the second 10 terms is 735. Find the first term and the commondifference.
Janet invested $10,000, part at 2% and part at 12%. if the total interest at the end of the year is $600, how much did she invested at 2%

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

Answers

f(x) = 4 - x²    g(x) = 6x

(g - f)(x) = g(x) - f(x)

(g - f)(3) = g(3) - f(3)

g(x) = 6x

g(3) = 6*3 = 18

f(x) = 4 - x²

f(3) = 4 - 3² = 4 - 9 = -5

(g - f)(3) = g(3) - f(3) = 18 - (-5) = 18 + 5 = 23

 (g - f)(3) = 23

Yvette is trying to calculate the distance between point C(1, 2) and point D(7, 10). Which of the following expressions will she use?

Answers

For the answer to the question above, this can be solve using the distance formula: D = sqrt [ (x2 – x1)^2 + (y2 – y1)^2] So the expression she should use is: D = sqrt [ (7 – 1)^2 + (10 – 2)^2] Then the answer would be: D = sqrt [ (6)^2 + (8)^2] D = 10 I hope my answer helped you.

What expressions are equivalent to 3(4x+3)?

Answers

Answer: B, D, E

Step-by-step explanation: Its very easy to check, For B, you notice that it is the same, only the numbers are swapped. In multiplication, this is perfectly fine. For D, I just knew that the answer was 12x+9. And in D, there are 3 4x and 3 threes', so that one was correct. And for E, all you have to do is to multiply accordingly to the distributive property

Which numbers are factors of 40? select all that apply. 4 10 7 80 submit?

Answers

The factors of 40 from that list are 4, 8. and 80. A factor needs to be able to be divided by 40.

Joline is solving the equation 0 = x2 – 5x – 4 using the quadratic formula. Which value is the negative real number solution to her quadratic equation? Round to the nearest tenth if necessary.

Answers

To solve a quadratic equation, we use the quadratic formula which is expressed as:

x1 = [-b + √(b²-4ac)] / 2a]
x2 = [-b - √(b²-4ac)] / 2a]

These formulas are used to solve for the values of the roots of the equation given. From the equation,

a = 1
b = -5
c = -4

Substituting the values, we have:

x1 = 5.70
x2 = -0.70

Therefore, the negative real number is -0.70.

The value -0.07 is the negative real number in the quadratic equation 0 = x² – 5x – 4

What is a quadratic equation ?

Any equation of the form \rm ax^2+bx+c=0  where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

\rm x = (-b \pm√(b^2-4ac))/(2a)

We have a quadratic equation;

0 = x² – 5x – 4   or

x² – 5x – 4 = 0

Here a = 1, b = -5, and c = -4

\rm x = (-(-5) \pm√(-5^2-4(1)(-4)))/(2(1))

\rm x = (5 \pm√(41))/(2)

After simplification:

x = 5.70  or x = -0.70

The value x = -0.70 is the negative real number.

Thus, the value -0.07 is the negative real number in the quadratic equation 0 = x² – 5x – 4

Learn more about quadratic equations here:

brainly.com/question/2263981

#SPJ5

Nicole deposited $2,000 at 6% simple interest. How long will it be before she has $2,600 in her account?

Answers

\bf \qquad \textit{Simple Interest Earned Amount}\n\nA=P(1+rt)\qquad \begin{cases}A=\textit{accumulated amount}\to &2,600\nP=\textit{original amount deposited}\to& \$2,000\nr=rate\to 6\%\to (6)/(100)\to &0.06\nt=years\end{cases}

solve for "t"