A system is best described as: a. a form of energy that is transferred between two substances at different temperatures. b. mass that assumes a physical shape and occupies space. c. any set of ordered, interrelated components working as a unified whole. d. the capacity to change the motion of, or to do work on, matter. e. the point at which characteristics can no longer be maintained and a new state is adopted.

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Answer 1
Answer: I think d sorry if it doesn’t help

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Which of the following is a scalar quantity?​

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Answer:

C. 100 ft/min

Explanation:

A scalar quantity has no direction.

A scalar with direction is called a vector.

Answer:

C. 100ft/min

Explanation:

A scalar quantity is a quantity that has a magnitude but no direction, a vector quantity is a quantity that has both a magnitude and a direction. The other three answers are vectors quantities while C. is a scalar.

A container holding 1.2 kg of water at 20.0 °C is placed in a freezer that is kept at –20.0 °C. The water freezes and comes into thermal equilibrium with the interior of the freezer. a) How much heat is extracted from the water in thisprocess?
b) What is the minimum amount of electrical energy required bythe refrigerator to carry out this process if it operates betweenreservoirs at temperatures of 20.0 °C and -20.0 °C?

Answers

Answer:

(a) Q=556464\ J

(b) 556464 joule

Explanation:

Given:

  • mass of water, m_w=1.2\ kg
  • initial temperature of water, T_i=20^(\circ)C
  • final temperature of frozen water, T_f=-20{}^(\circ)C

The conversion of water of 20.0 °C to the ice of –20.0 °C will comprise of three steps:

  1. cooling of water to 0 °C Q_w
  2. formation of ice at 0 °C from the water of 0 °C Q_L
  3. further cooling of ice of 0 °C to -20 °C Q_i

We have,

  • Latent heat of fusion of ice, L=3.4* 10^5\ J.kg^(-1)
  • specific heat of water, c_w=4186\ J.kg^(-1).^(\circ)C^(-1)
  • specific heat of ice, c_i=2000\ J.kg^(-1).^(\circ)C^(-1)

(a)

Now, total heat lost in the process:

Q=Q_w+Q_L+Q_i

Q=m_w(c_w. \Delta T_w+L+c_i.\Delta T_i)

where:

\Delta T_i\ \&\ \Delta T_w = change in temperature of ice and water respectively.

\Rightarrow Q=1.2(4186* 20+3.4* 10^5+2000* 20)

Q=556464\ J is the total heat extracted during the process.

(b)

So, 556464 joule is the minimum electrical energy (by the law of energy conservation under no loss condition) required by refrigerator to carry out this process if it operates between the reservoirs at temperatures of 20.0 °C and -20.0 °C, because for a refrigerator to work in a continuous cycle it is impossible to transfer heat from a low temperature reservoir to a high temperature reservoir without consuming energy in the form of work. Here 556464 joule is the heat of the system to be eliminated.

Final answer:

The amount of heat extracted from the water involves the sum of heat lost as it cools and then freezes. The minimum energy needed by the refrigerator to do this is given by the formula for Carnot efficiency.

Explanation:

To answer these questions, we'll need to understand some fundamental principles of thermodynamics.

a) The heat Q taken from the water will be the sum of the heat released during cooling of the water until 0.0°C, and the heat released during freezing at 0.0°C. The heat loss as the water cools can be calculated using Q = mcΔt where m=mass of water, c=specific heat of water, and Δt=change in temperature. The heat loss as water freezes can be calculated using Q = mlf where lf is the latent heat of fusion. Adding these two quantities gives the total heat extracted.

b) The minimum energy needed by the refrigerator, W, is given by the Carnot efficiency formula, W = Q*(T_hot - T_cold)/T_hot, where T is in Kelvin. This would tell you how much energy the refrigerator needs to remove the heat from the water and cool it down to the freezer temperature.

Learn more about Thermodynamics here:

brainly.com/question/35546325

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A nerve impulse travel along a myelinated neuron at 75.9 m/s

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