Mauritius island is 2 km due south of its closest point along a straight coastline. Gibril is staying at a private room on the shore that is 6 km east of that point. Gibril is planning to go from the room to the island. Suppose Gibril runs at a rate of 8 kmph and swims at a rate of 3 kmph. How far should Gibril run before swimming to minimize the time it takes to reach the island?

Answers

Answer 1
Answer:

Answer:

5.19 Km

Step-by-step explanation:

According To the Question,

Suppose he Runs Xkm before swimming to minimize the time it takes to reach the island .

So, he should swim \sqrt{2^(2)+(6-X)^(2)  } Km .

Now The Total Time is t = (X)/(8) + \frac{\sqrt{2^(2)+(6-X)^(2)  } }{3} .

t = (X)/(8) + \frac{\sqrt{X^(2)-12X+40  } }{3}

(dt)/(dX)=1/8 + 1/3 * 1/2 * \frac{2X-12}{\sqrt{X^(2)-12X+40 } }

(dt)/(dX)=1/8 + (1)/(3)  * \frac{X-6}{\sqrt{X^(2)-12X+40 } }

Now Put (dt)/(dX) = 0 , we get

1/8 + (1)/(3)  * \frac{X-6}{\sqrt{X^(2)-12X+40 } } = 0

(1)/(3)  * \frac{X-6}{\sqrt{X^(2)-12X+40 } } = - (1)/(8)

8(X-6)= -3 × {\sqrt{X^(2)-12X+40 }

square on both side,We get

64(X²-12X+36) = 9X² - 108X +360

55X² -660X + 1944 = 0

Apply Shri Dharacharya formula, To Find The Value of 'X'

X =[ - (-660) ±\sqrt{(-660)^(2)-4*55*1944 }  ] ÷ 2×55

X = (660±√7920) / 110

X= (660 - 89 ) / 110  ⇒ (Neglect '+' because it give 749/110 = 6.8 km Which is not possible )

X=571/110 ⇔ 5.19km he Should Run before swimming to minimize the time .

(For Diagram,Please Find In Attachment)


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Answers

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Answers

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Answer:

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Step-by-step explanation:

i got it right on the test but I don't know the steps of solving it sorry

Which phrase best defines a square? A.
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Answers

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Answers

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Answers

Answer:

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Step-by-step explanation:

Answer:

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-XxanimexX

What is the value of this expression?

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(its a fraction)

Answers

Hey there!

Answer: \boxed{40}

Explanation:

Simplify to solve.

\boxed{40}\text{ is your answer.}

Hope this helps!

\text{-TestedHyperr}

Answer:

40

Step-by-step explanation:

(9^2 +79) /2^2

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40