MATHEMATICS COLLEGE

Please help me ASAP ASAP ASAP

Answers

Answer 1

Answer:

Answer:

d = 4√5

Step-by-step explanation:

d² = 8² + 4²

d² = 64 + 16

d² = 80

d =√80

d = √(16 * 5)

d = 4√5

Answer 2

Answer:

Answer:

Step-by-step explanation:

hard to see graph ....

Related Questions

Complete the standard form of the equation of a hyperbola that has vertices at (-10, -15) and (70, -15) and one of its foci at (-11, -15).
Approximately how many times greater is 6 x 10^-6 than 2 x 10^-8
Jim borrows $14,000 for a period of 4 years at 6 % simple interest. Determine the interest due on the loan. [4 marks
How do you do these two questions?
Hello can you please help me posted picture of question

NEED THIS QUESTION ASAP!

Answers

Answer:

1. The last one

2. The third one

Write and solve an equation to find the value of x. PLS HELP!!

Answers

Answer:

23.59 - 14.89 = x

x = 8.7

Step-by-step explanation:

To find x, you need to add all of the other sides and subtract it from the perimeter. 5.62 + 5.62 + 3.65 = 14.89.

23.59 - 14.89 = x, so x = 8.7

Answer:

8.7

Step-by-step explanation:

Add all the numbers together (5.62, 5.62, and 3.65) then take away from the result (23.59) to get answer.

Determine the maximized area of a rectangle that has a perimeter equal to 56m by creating and solving a quadratic equation. What is the length and width?

Answers

Answer:

Area of rectangle = $196\,m^2$

Length of rectangle = 14 m

Width of rectangle = 14 m

Step-by-step explanation:

Given:

Perimeter of rectangle is 56 m

To find: the maximized area of a rectangle and the length and width

Solution:

A function $y=f(x)$ has a point of maxima at $x=x_0$ if $f''(x_0)<0$

Let x, y denotes length and width of the rectangle.

Perimeter of rectangle = 2( length + width )

$=2(x+y)$

Also, perimeter of rectangle is equal to 56 m.

So,

$56=2(x+y)\nx+y=28\ny=28-x$

Let A denotes area of rectangle.

A = length × width

$A=xy\n=x(28-x)\n=28x-x^2$

Differentiate with respect to x

$(dA)/(dx)=28-2x$

Put $(dA)/(dx)=0$

$28-2x=0\n2x=28\nx=14$

Also,

$(d^2A)/(dx^2)=-2<0$

At x = 14, $(d^2A)/(dx^2)=-2<0$

So, x = 14 is a point of maxima

So,

$y=28-x=28-14=14$

Area of rectangle:

$A=xy=14(14)=196\,m^2$

Length of rectangle = 14 m

Width of rectangle = 14 m

A reservation service employs six information operators who receive requests for information independently of one another, each according to a Poisson process with rate ???? = 2 per minute. a. What is the probability that during a given 1 min period, the first operator receives no requests? (Round your answer to three decimal places.) b. What is the probability that during a given 1 min period, exactly three of the six operators receive no requests? (Round your answer to five decimal places.)

Answers

Answer:

a) 0.135 = 13.5% probability that during a given 1 min period, the first operator receives no requests.

b) 0.03185 = 3.185% probability that during a given 1 min period, exactly three of the six operators receive no requests

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)$

In which $C_(n,x)$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_(n,x) = (n!)/(x!(n-x)!)$

And p is the probability of X happening.

Poisson process with rate 2 per minute

This means that $\mu = 2$

a. What is the probability that during a given 1 min period, the first operator receives no requests?

Single operator, so we use the Poisson distribution.

This is P(X = 0).

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

$P(X = 0) = (e^(-2)*2^(0))/((0)!) = 0.135$

0.135 = 13.5% probability that during a given 1 min period, the first operator receives no requests.

b. What is the probability that during a given 1 min period, exactly three of the six operators receive no requests?

6 operators, so we use the binomial distribution with $n = 6$

Each operator has a 13.5% probability of receiving no requests during a minute, so $p = 0.135$

This is P(X = 3).

$P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)$

$P(X = 3) = C_(6,3).(0.135)^(3).(0.865)^(3) = 0.03185$

0.03185 = 3.185% probability that during a given 1 min period, exactly three of the six operators receive no requests

Determine whether the value is from a discrete or continuous data set. Area of a park is 9.5 acres Is the value from a discrete or continuous data set? Discrete Continuous O

Answers

Answer: The value is from discrete data set.

Step-by-step explanation:

Since we have given that

Discrete data set is the data set which can be measured in numbers.

Continuous data set is the data set which can take any value within an interval.

As we have mention that

Area of a park = 9.5 acres

So, it is the exact number so, it can be measured in numbers.

so, it is discrete data set.

Hence, the value is from discrete data set.

Nine yards of ribbon are cut into 8 equal pieces what is the length of each piece of ribbon. Write a division expression to represent the problem and solve