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How many molecules are there in 4.27 mol of tungsten(VI) oxide, WO3

Answers

Answer 1

Answer:

25.71 × 10²³ molecules are there in 4.27 mol of tungsten (VI) oxide, $WO_3$ .

How to find the number of molecules ?

To find the Number of molecules of substance multiply the number of moles of given substance by Avogadro number

Number of molecules = Number of moles × Avogadro's Number

Avogadro's Number

Avogadro's number $(N_(A))$ is the number of particles in one mole of substance. 6.023 × 10²³ is known as Avogadro's constant / Avogadro's number.

Avogadro's number = 6.023 × 10²³ $mol^(-)$

Now,

Number of molecules in 4.27 moles of $WO_(3)$

= Number of moles of $WO_(3)$ × Avogadro's Number

= 4.27 × 6.023 × 10²³

= 25.71 × 10²³ molecules

Thus, we can say that 25.71 × 10²³ molecules are there in 4.27 moles of tungsten (VI) oxide, $WO_3$ .

Learn more about the Avogadro's Number here: brainly.com/question/859564

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Answer 2

Answer:

Answer:

Molar mass of WO3 = 231.8382 g/mol

Convert grams Tungsten(VI) Oxide to moles or moles Tungsten(VI) Oxide to grams

Molecular weight calculation:

183.84 + 15.9994*3

Explanation:

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The _______ are found on the left side of the arrow in a chemical reaction. A. coefficients B. reactants C. products D. subscripts

Answers

B reactants then C is on the right side! If you take h2O and air (the reactants) then the product would be a snowflake. happy holidays!!

Answer:

Reactants

Explanation:

Write a balanced chemical equation for the standard formation reaction of gaseous dinitrogen tetroxide

Answers

Answer:

$N_2(g)+2O_2(g)\rightarrow N_2O_4(g)$

Explanation:

Hello,

In this case, considering the required product which is dinitrogen tetroxide whose molecular formula is N₂O₄, by considering its formation reaction which is starting by both gaseous nitrogen and oxygen as shown below:

$N_2(g)+O_2(g)\rightarrow N_2O_4(g)$

Nevertheless, it should be balance since four oxygen atoms are present at the right side, thus, we obtain:

$N_2(g)+2O_2(g)\rightarrow N_2O_4(g)$

Best regards.

Four different methods are described for validating the results of a particular analysis. Indicate for each whether the method primarily checks the accuracy of the analysis or the precision of the analysis.a. Five aliquots of the same sample are injected for gas chromatographic analysis by one person on the same day.
i. Accuracy
ii. Precision
b. A known amount of analyte is added to an aliquot of the sample and analyzed with sample.
i. Accuracy
ii. Precision
c. Aliquots from a blood sample are sent to three separate laboratories for analysis using the same method.
i. Accuracy
ii. Precision
d. Identical standard are analyzed by two different methods.
i. Accuracy
ii. Precision

Answers

Answer:

a) Precision

b) Accuracy

c) Accuracy and precision

d) Accuracy

Explanation:

When an experiment is done more than once to determine if the results are statistically ok, two forms of the validations are possible the accuracy and precision. When the values of the various experiments are close to the known value, then they are accurate. When the values are close to each other they are precise. So, sometimes the results are precise but are not accurate, and vice-versa.

a) Here, the person wants to find if the 5 aliquots will have close results, so, he or she is looking for precision.

b) Here the amount of analyte is already known, and the person wants to identify if the value will be the same when analyzed together with another sample, thus he or she is looking for accuracy.

c) Here the three results will be compared with each other (precision) and with the standard value of the method (accuracy).

d) The methods will be tested, and the values will be compared with the standard known value, so the person is looking for accuracy.

Which of the following statements is true about exothermic reactions?

Answers

Answer:

An Exothermic Reaction , gives off more heat, and a little energy to its surroundings.

this can helps us figure out that the answer is , C, More heat is given off into its products.

Explanation:

the ionization constant for dichloroacetic acid HC2HO2Cl2 is 5.0 x 10^-2 . What is the pH of a 0.15 molar solution of this acid?

Answers

Answer: pH = 1.19

Explanation:

The formula for Ka is: Ka = [H+][A-]/[HA]

where: [H+] = concentration of H+ ions

[A-] = concentration of conjugate base ions

[HA] = concentration of undissociated acid molecules

Equation of reaction: Cl₂CHCOOH ---> H+ + Cl₂CHCOO-

From the equation above, dichloroacetic acid dissociates one H+ ion for every Cl₂CHCOO- ion,

so [H+] = [Cl₂CHCOO-].

Let x represent the concentration of H+ that dissociates from HA, then [HA] = C - x where C is the initial concentration.

Substituting these values into the Ka equation:

Ka = x · x / (C -x)

Ka = x²/(C - x)

(C - x)Ka = x²

x² = CKa - Kax

x² + Kax - CKa = 0

Solve for x using the quadratic formula:

x = [-b ± √(b² - 4ac)]/2a

Note: There are two solutions for x. However only the positive value of x is used since x represents a concentration of ions in solution, and so cannot be negative.

x = [-Ka + √(Ka² + 4CKa)]/2

Substitute the values for Ka and C in the equation above:

Ka = 5.0 x 10^-2

C = 0.15 M

x = {-5.0 x 10^-2 + √[(5.0. x 10^-2)² + 4(0.15)(5.0 x 10^-2)]}/2

x = (-5.0 x 10^-2 + 1.80 x 10^-1)/2

x = 0.13/2

x = 6.50 x 10^-2

To find pH, we use the formula;

pH = -log[H+]

pH = -log(x)

pH = -log(6.50 x 10^-2)