El perro de Antonia debe comer 0,48 kg de alimento cada día. ¿Cuánto alimento necesita para 30 días?

Answers

Answer 1
Answer:

Answer:

Amount of food need for 30 days = 14.4 kilogram

Step-by-step explanation:

Given information:

Amount of food dog eat each day = 0.48 kilogram

Find:

Amount of food need for 30 days

Computation:

⇔ Amount of food need for 30 days = Amount of food dog eat each day x number of days

⇔ Amount of food need for 30 days = 0.48 x 30

Amount of food need for 30 days = 14.4 kilogram

14.4 kilogram is right answer.


Related Questions

This holiday season, Ms. Bastarache organized to give each 9th grader a $10 Dunkin Donuts gift card. Because she bought a lot of cards, Ms. Bastarache tipped the Dunkin Donuts employee $20.This function represents the relationship between the number of gift cards, c, and T(c), the total cost of the cards.T(c) = 10c + 20Be sure to answer BOTH questions below.1. Determine the total cost, in dollars, for Ms. Bastarache to give out 93 gift cards.2. Last year, Ms. Bastarache spent $820, how many cards did she purchase?need help asap plzzzzzz
When hired at a new job selling jewelry, you are given two pay options:Option A: Base salary of $16,000 a year, with a commission of 7% of your sales Option B: Base salary of $25,000 a year, with a commission of 2% of your sales In order for option A to produce a larger income, you would need sell at least $_______ of jewelry each year
Henry needs a 16 ft. table for his family dinner. He is going to put two tables together. He has an 8ft table. How long does the other need to be?
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Correlation is a measure of the direction and strength of the linear (straight-line) association between two quantitative variables. The analysis of data from a study found that the scatter plot between two variables, x and y, appeared to show a straight-line relationship and the correlation (r) was calculated to be -0.84. This tells us that a. there is little reason to believe that the two variables have a linear association relationship b. all of the data values for the two variables lie on a straight line. c. there is a strong linear relationship between the two variables with larger values of x tending to be associated with larger values of the y variable. d. there is a strong linear relationship between x and y with smaller x values tending to be associated with larger values of the y variable. e. there is a weak linear relationship between x and y with smaller x values tending to be associated with smaller values of the y variable

Find the time needed for
a $500 to gain an interest of $150 at 7.5% rate. ​

Answers

Answer:

4 years

Step-by-step explanation:

This is a problem in simple interest:  i = prt, where:

p is the principal (intial amount), i is the interest, r is the annual interest rate and t is the time in years.

                                                    i

Solving i = prt for t, we get t = ------

                                                   pr

             

                                            $150

which comes out to t = ---------------------  =   4 years

                                       ($500)(0.075)

The table shows the price for different numbers of notebooks:Number of Notebooks Price (in dollars)
2 12
3 18
4
5 30

Answers

If you are looking for what it is multiplied by it is 6. But for the number 4 it is 24 because 6 times 4 is 24

Answer:

The answer would be 24$

Step-by-step explanation:

If the relationship is proportional then it would be equal so if were adding 12 plus a number (which is 6) adds up which is 12 plus 6 = 18 plus 6 is our answer 24 then plus 6 is 30 as you can see we were adding by six proportionally and so the answer was 24

a.Find a linear approximation of 4√14 . b. Justify visually whether your approximation is an over- or underestimate.

Answers

Answer:

15

Step-by-step explanation:

Let f(x) be the function

\bf f(x)=√(x)

A linear approximation of f is the Taylor polynomial of degree one:

\bf f(x)\approx f(a)+f'(a)(x-a)

Taking a = 16, and given that

\bf f'(x)=\displaystyle(1)/(2√(x))

we get

\bf f(x)\approx f(16)+f'(16)(x-16)=√(16)+\displaystyle(1)/(2√(16))(x-16)=4+\displaystyle(x-16)/(8)

so

\bf √(14)=f(14)\approx 4+\displaystyle(14-16)/(8)=3.75\Rightarrow\n\n\Rightarrow 4√(14)\approx 4(3.75)=15

Since 16 > 14, we can deduce that this is an overestimate.

What are the domain and range of the real-valued function f(x)=2/3x?A. The domain is all real number except 0. The range is all real numbers except 0.
B. The domain and the range are all real numbers.
C. The domain is x>0. The range is f(x)>0.
D. The domain is all real numbers except 0. The range is all real numbers

Answers

If your function is (as written) ...

... f(x) = (2/3)x

Then B is the correct answer.

_____

If your function is ...

... f(x) = 2/(3x)

Then A is the correct answer.

1. An equation is shown below.3 (x-2) + 7x= 1/2(6x-2)
How many solutions, if any, does the equation have?

Answers

Answer:

x=5/7

Step-by-step explanation:

3(x-2)+7×=1/2×(6×-2)

3x-6+7×=1/2×2(3×-1)

3×-6+7×=3×-1

-6+7×=-1

7×=-1+6

7×=5

Need help with this question all parts (Use the image on cypto to help solve the question)

Answers

Explanation

Part a

We first need to find the encoding and decoding functions used by Boris and Natasha. We know that these two must be linear functions with 1 as the coefficient of x. Then the encoding function must have the form:

f(x)=x+b

Where x is the number associated with the letter and b is a constant that we don't know. The decoding function is its inverse:

f^(-1)(x)=x-b

Now let's take a look at the table that associates the letters with numbers. The minimum number is 1 associated with A and the maximum is 27 associated with Blank. Now let's write the encoded version of these two:

\begin{gathered} f(1)=1+b \n f(27)=27+b \end{gathered}

And let's find the difference between their encoded values:

f(27)-f(1)=(27+b)-(1+b)=27-1+b-b=27-1=26

So the difference between their encoded values is the same as the difference between their decoded values. Since 1 and 27 are the minimum and maximum decoded values their difference is the greatest of all the difference between two decoded values. Then there's no other pair of decoded values with a difference equal to 26 and since the difference between two encoded values is the same as the difference between two decoded values we can assure that 26 is the maximum difference between two encoded values and it corresponds to the pair A - Blank.

This implies that if the difference between the minimum and maximum value in the message sent by Boris and Natasha is 26 we can assure that this pair of values is the one corresponding to A and Blank.

Part b

The minimum and maximum values in the message are 15 and 41 and their difference is 41 - 15 = 26. This means that 15 is the encoded value of A and 41 is that of Blank. Then we can construct two equations using the encoding function:

\begin{gathered} f(1)=1+b=15 \n f(27)=27+b=41 \end{gathered}

By substracting 1 from both sides of the first equation and 27 from both sides of the second equation we obtain b:

\begin{gathered} 1+b-1=15-1\Rightarrow b=14 \n 27+b-27=41-27\Rightarrow b=14 \end{gathered}

So b=14 and the encoding function is f(x)=x+14.

Then the decoding function is f⁻¹(x) = x - 14.

Part c

Now we need to decode the message. We simply need to evaluate the decoding function at all the numbers in the encoded message:

\begin{gathered} f^(-1)(25)=25-14=11 \n f^(-1)\left(19\right)=19-14=5 \n f^(-1)(30)=30-14=16 \n f^(-1)(41)=41-14=27 \n f^(-1)(17)=17-14=3 \n f^(-1)(15)=15-14=1 \n f^(-1)(26)=26-14=12 \n f^(-1)(27)=27-14=13 \n f^(-1)(28)=28-14=14 \n f^(-1)(18)=18-14=4 \n f^(-1)(29)=29-14=15 \n f^(-1)(34)=34-14=20 \n f^(-1)(22)=22-14=8 \end{gathered}

Then we replace each encoded value by its respective decoded value so the message in numbers is:

11 5 5 16 27 3 1 12 13 27 1 14 4 27 4 15 27 20 8 5 27 13 1 20 8

Using the table associating numbers and letters we obtain the final message:

KEEP CALM AND DO THE MATH