The following two right triangles are similar.If side PQ = 42, side LM = 28, and side QR = 24, what is the length of side MN?a. 16
b. 10
c. 13
d. 14

Let's start with sectioning off the little squares on the left that are jutting out of the top and bottom. Both of the squares are C*E, so multiply C*E twice to get the area of those little squares. That comes out to 12 feet.

Next is the main quadrilateral, the big one. You have to cut it off at the point the triangle starts to slope, so the end fo B.

But you also have to get the left part, so you have to add the length of C to the length of B to get the length of the quadrilateral. A encompasses the entire height, but not the part we want, because we already isolated those little squares. To get the height, just subtract the two E parts. The height is 6. The length is 8 feet. Multiply and get 48.

Add that to the previous 12 feet calculated to get 60.

Next, the triangle. The height is A, but only with one E. So subract the other E to get a height of 9. The length is D, but you have to subract B because that is part of the earlier quadrilateral. That makes it 9.

The formula for a triangle is height * length / 2. So, plug in the numbers-- 9 * 9 / 2

81/2

40.5.

Add to the previous 60 we got and that makes 100.5 square feet.

Hope this helped!

Answer: A) Yes, his solution is incorrect.

B) The given equation has 1 solution.

Step-by-step explanation:

A) Here, the given expression is,

Thus, the steps of solving the given expression are as follow,

Step 1:

Ste 2 :

Step 3 :

Hence, by the above explanation,

It is clear that the given steps of the solution are incorrect.

B) Since, x has only one value which is 6,

Hence, the given expression has only one solution.

The distance between two points (x₁, y₁) and (x₂, y₂) is given by:

With this, we will found that the distance between A and B is: 4 units.

The first thing we need to do is find A and B.

We know that the points are the intersection between the two parabolas.

y = -x^2 + 9

y = 2*x^2 - 3

The intersection is given by the zeros of the difference:

(2*x^2 - 3) - (-x^2 + 9) = 0

3*x^2 -12 = 0

3*x^2 = 12

x^2 = 12/3 = 4

x = √4 = ±2

To find the points, we need to evaluate one of the parabolas in these two x-values.

Let's use the first one:

y = -(2)^2 + 9 = 5

So we have the point (2, 5)

For the other point:

y = -(-2)^2 + 9 = 5

So we have the point (-2, 5)

Then we can define:

A =  (2, 5)

B = (-2, 5)

Using the distance equation we get:

The distance between A and B is 4.

If you want to learn more, you can read:

brainly.com/question/12082741

Answer:

Answer:

AB=4

Step-by-step explanation:

Answer:

AB=4

Step-by-step explanation:

1. Since you are finding the intersection points of two parabolas:

a. y=-x²+9

b. y=2x²-3

2. You have to set them equal to each other:

2x²-3= - x²+9

2x²+x=9+3

3x²=12

x²=4

This is the crucial part; the absolute value of x is equal to plus minus the square root of 4, since either -2 squared with parentheses or 2 squared is equal to 4.

√x²=±√4

x=±2

or

x=2; x=-2

3. Then you substitute them into each equation. For this step, any sign 2 will work.

a. y=-(2)²+9

y=-4+9

y=5

b. y=2(2)²-3

y=8-3

y=5

4. So our coordinates will be (2,5) and (-2,5). These are the points of intersection.

5. Now we use the distance formula:

The subscripts didn't work for this but I mean the square root of x 2 - x 1 in parentheses plus y 2 -y 1.

=

√16=

4

The absolute value rule that I mentioned above doesn't work for this because its a distance and you can't have a negative distance.

So AB=4

Answer:

The matrix that is the coordinate matrix of the given quadrilateral is:

Step-by-step explanation:

We  know that the vertices of a quadrilateral are expressed in form of a matrix by placing the vertices along the column of a matrix.

i.e. the vertex A(-5,0) form the first column of a  matrix and similarly the vertex B form the second column of the matrix ; C from the third column of the matrix and D form the third column of the matrix.

          Hence, the answer is:

                      Matrix A