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HELP PLEASE 20points!!!At a high school, 9th and 10th graders were asked whether they would prefer
robotics or art as an elective. The results are shown in the relative frequency
table.
HELP PLEASE 20points!!! At a high school, 9th and 10th - 1

Answers

Answer 1
Answer:

Answer:

61%

Step-by-step explanation:

We can see that out of all the people that were surveyed, 54% were 10th graders. Since 33% out of all the ones surveyed were 10th graders that chose robotics, the fraction would be 33/54 which is 0.611.

This is 61% approx.
Answer 2
Answer:

Answer:

61%

Step-by-step explanation:

A P E X

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Question part points submissions used two cars start moving from the same point. one travels south at 32 mi/h and the other travels west at 24 mi/h. at what rate is the distance between the cars increasing three hours later? mi/h

Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of μ=22.5 in. and a standard deviation of σ=1.1 in. These data are often used in the design of different​ seats, including aircraft​ seats, train​ seats, theater​ seats, and classroom seats. Instead of using 0.05 for identifying significant​ values, use the criteria that a value x is significantly high if​ P(x or ​greater) ≤0.01 and a value is significantly low if​ P(x or ​less) ≤0.01.Find the​ back-to-knee lengths separating significant values from those that are not significant.

Answers

Answer:

Measures equal or lower than 19.94 inches are significantly low.

Measures equal or higher than 25.06 inches are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 22.5, \sigma = 1.1

Find the​ back-to-knee lengths separating significant values from those that are not significant.

Significantly low

In this exercise, a value is going to be to significantly low if it has a pvalue of 0.01 or less. So we have to find X when Z has a pvalue of 0.01. This is between Z = -2.32 and Z = -2.33, so we use Z = -2.325

Z = (X - \mu)/(\sigma)

-2.325 = (X - 22.5)/(1.1)

X - 22.5 = -2.325*1.1

X = 19.94

Measures equal or lower than 19.94 inches are significantly low.

Significantly high

In this exercise, a value is going to be to significantly high if it has a pvalue of 0.99 or more. So we have to find X when Z has a pvalue of 0.99. This is Z = 2.325. So:

Z = (X - \mu)/(\sigma)

2.325 = (X - 22.5)/(1.1)

X - 22.5 = 2.325*1.1

X = 25.06

Measures equal or higher than 25.06 inches are significantly high.

Final answer:

To find the separating back-to-knee lengths, we calculate the corresponding z-scores for the given probabilities. Using the standard normal distribution table, we find that the separating values are 24.78 inches for significantly high lengths and 20.22 inches for significantly low lengths.

Explanation:

To find the back-to-knee lengths separating significant values from those that are not significant, we need to calculate the z-scores corresponding to the given probabilities. For a value to be significantly high, we look for a z-score such that the area to its right is 0.01. Using the standard normal distribution table, we find that z = 2.33. Similarly, for a value to be significantly low, we look for a z-score such that the area to its left is 0.01. Again using the table, we find that z = -2.33. Converting these z-scores back to actual back-to-knee lengths, we can calculate the separating values as: 22.5 + (2.33 * 1.1) = 24.78 inches for significantly high lengths, and 22.5 - (2.33 * 1.1) = 20.22 inches for significantly low lengths.

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If h(x) = -2x+5/4, find h(x) = 3/4

Answers

Answer:

x=(1)/(4)

Step-by-step explanation:

So we have the function:

h(x)=-2x+(5)/(4)

And we want to find h(x)=3/4.

So, we want to find the value of x such that h(x) equates to 3/4.

So, substitute 3/4 for h(x):

(3)/(4)=-2x+(5)/(4)

First, subtract both sides by 5/4. The right will cancel.

(3)/(4)-(5)/(4)=-2x+(5)/(4)-(5)/(4)

Subtract on the left:

-(2)/(4)=-2x

Reduce on the left:

-(1)/(2)=-2x

Now, multiply both sides by -1/2. The right will again cancel:

-(1)/(2)(-(1)/(2))=-(1)/(2)(-2x)

Multiply on the left:

x=(1)/(4)

So, for h(x) to be 3/4, the value of x is 1/4.

And we're done!

Answer:

x = 1/4

Step-by-step explanation:

We are given the function as h(x) = - 2x + 5/4. If we have to determine h(x) = 3/4 given this function, let's substitute this value into our function and solve for 'x.' This will be our solution -

3/4 = - 2x + 5/4,

If we subtract 5/4 from either side : - 2x = - 1/2

Now divide either side by - 2 : x = 1/4

Therefore our solution is x = 1/4

At the start of 2014 Mike's car was worth £12000.The value of the car decreased by 30% every year.
Work out the value of his car at the start of 2017.

Answers

The value of Mike's car at the start of 2017 is £4116.

What is percentage ?

Percentage is a ratio in the form of fraction of 100.

Percentage is defined by the "%" symbol.

What is the required value of the car ?

At the start of the year 2014, Mike's car was worth £12000.

The value of the car decreased by 30% every year.

So, The value of the car at the start of 2015 = £12000×(1-(30)/(100))

                                                                         = £ 12000×(7)/(10)

                                                                         = £ 8400

Again, The value of the car at the start of 2016 = £8400×(1-(30)/(100))

                                                                              = £8400×(7)/(10)

                                                                              = £5880

∴ The value of the car at the start of 2017 = £5880×(1-(30)/(100))

                                                                     = £5880×(7)/(10)

                                                                     = £4116

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Parallel lines r and s are cut by two transversals, parallel lines t and u. Lines r and s are crossed by lines t and u to form 16 angles. Clockwise from top left, at the intersection of r and t, the angles are 1, 2, 3, 4; at the intersection of s and t, 5, 6, 7, 8; at the intersection of u and s, 9, 10, 11, 12; at the intersection of u and r, 13, 14, 15, 16. Which angles are alternate interior angles with angle 3? Angle5 and Angle13 Angle7 and Angle15 Angle6 and Angle16 Angle8 and Angle14 Mark this an

Answers

Answer:

5 and 13

Step-by-step explanation:

I got it right on edge

Answer:

5 and 13, got in right in edge 2020

Step-by-step explanation:

Round the decimal to the nearest tenth 0.709

Answers

Given:-

0.709

To find the nearest tenth.

Since the tenths term is greater than five the nearest tenths is,

1.000

So the required is 1.00

Could you help me solve y = x^2+6x+7?

Answers

Answer:

x ≈ -1.585786438 or x ≈ -4.414213562

y = 7

Step-by-step explanation:

This should be a parabola function.

Let y = 0 so we can find the two x-intercepts. (x1,0) and (x2,0)

x^2+6x+7 = 0

Using the quadratic equation, we get:

x ≈ -1.585786438 or x ≈ -4.414213562

Now we can find y by setting x = 0, so that we get a y-intercept. (0,y)

y = 0^2+6(0)+7

y = 7
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