CHEMISTRY HIGH SCHOOL

What determines the strength of a dipole dipole force?

Answers

Answer 1
Answer:

Answer:

The more polar the molecules, the stronger the force. The more hydrogen in the molecule, the stronger the force.

Explanation:

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Predict which of the following compounds will be insoluble in water.A. NaCl
B. HCl
C. CF4
D. CuSO4

Answers

\boxed{{\text{C}}{\text{. C}}{{\text{F}}_4}}will be insoluble in water.

Further Explanation:

The bond formed due to electrostatic forces is an ionic bond. The compounds formed by the ions of the respective species are called ionic compounds. One of the species loses electrons and gets converted into cation while the other one accepts electrons and forms anion.

Covalent compound:

The bond that is formed by the mutual sharing of electrons between the bonded atoms is called a covalent bond. It is also known as a molecular bond. Covalent compounds or molecular compounds are those compounds which are formed by the electron sharing between two or more non-metals.

Solubility is the property of any substance that makes it soluble in other substances. It is governed by the principle “like dissolves like”.

A. NaCl is an ionic compound so it dissociates into its constituent ions on dissolving in water. Water is a polar molecule and therefore NaCl is soluble in water.

B. HCl is a polar covalent compound and water is also a polar compound so HCl is soluble in water in accordance with the principle “like dissolves like”.

C.{\text{C}}{{\text{F}}_{\text{4}}} is a non-polar compound while water is a polar compound. So {\text{C}}{{\text{F}}_{\text{4}}} is insoluble in water because of different nature of both substances.

D. {\text{CuS}}{{\text{O}}_{\text{4}}} is an ionic compound so it dissociates into {\text{C}}{{\text{u}}^(2 + )} and {\text{SO}}_4^(2 - ) ions on dissolving in water. Water is a polar molecule and therefore {\text{CuS}}{{\text{O}}_{\text{4}}} is soluble in water.

Learn more:

1. Identification of ionic bonding: brainly.com/question/1603987

2. What type of bond exists between phosphorus and chlorine? brainly.com/question/81715

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ionic and covalent compounds

Keywords: ionic compound, covalent compound, solubility, NaCl, HCl, CuSO4, CF4, soluble, insoluble, water, like dissolves like.

Final answer:

Among the compounds NaCl, HCl, CuSO4, and CF4, the latter, CF4, is predicted to be insoluble in water due to its nonpolar nature.

Explanation:

The insolubility of a compound in water depends on its polarity. Nonpolar compounds do not dissolve in water, a polar solvent. The compounds NaCl, HCl, and CuSO4 are all polar ionic compounds and, therefore, soluble in water, since 'like dissolves like'. However, the compound CF4 is a nonpolar molecule and hence predicted to be insoluble in water.

Learn more about Solubility here:

brainly.com/question/31493083

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A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products have cooled to 20.0 °C at 1 bar, there are 4.41 L of CO2 and 3.26 mL of H2O . The density of water at 20.0 °C is 0.998 g/mL.

Answers

Explanation:

First, calculate the moles of CO_(2) using ideal gas equation as follows.

                PV = nRT

or,          n = (PV)/(RT)

                = (1 atm * 4.41 ml)/(0.0821 Latm/mol K * 293 K)      (as 1 bar = 1 atm (approx))

                = 0.183 mol

As,   Density = (mass)/(volume)

Hence, mass of water will be as follows.

                Density = (mass)/(volume)

             0.998 g/ml = (mass)/(3.26 ml)    

                 mass = 3.25 g

Similarly, calculate the moles of water as follows.

        No. of moles = \frac{mass}{\text{molar mass}}

                              =  (3.25 g)/(18.02 g/mol)            

                              = 0.180 mol

Moles of hydrogen = 0.180 * 2 = 0.36 mol

Now, mass of carbon will be as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

          0.183 mol =  (mass)/(12 g/mol)            

                              = 2.19 g

Therefore, mass of oxygen will be as follows.

              Mass of O = mass of sample - (mass of C + mass of H)

                                = 3.50 g - (2.19 g + 0.36 g)

                                = 0.95 g

Therefore, moles of oxygen will be as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                               =  (0.95 g)/(16 g/mol)            

                              = 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

                         C              H           O

No. of moles:  0.183        0.36       0.059

On dividing:      3.1           6.1            1

Therefore, empirical formula of the given compound is C_(3)H_(6)O.

Thus, we can conclude that empirical formula of the given compound is C_(3)H_(6)O.            

While camping up at Haloooo Mountain (5,500 feet above sea level), it generally takes Sandy about the same amount of time to boil water for her soup as it takes to make a sandwich. This week, Sandy is camping at a trail that is only about 200 feet above sea level. Sandy is very hungry and wants something to eat immediately. Should she make the soup or sandwich? Which would be ready more quickly and why?

Answers

She should make soup. When you are way above sea level, the atmospheric pressure decreases. Boiling starts when the vapor pressure of the liquid is the same with the atmospheric pressure. This would mean that water boils at a much lower temperature than the usual 100deg C. So it would take longer for the components in the soup to cook compared to when it is cooked on the foot of the mountain. 

After decaying for 48 hours, l/16 of the original mass of a radioisotope sample remains unchanged. What is the half-life of this radioisotope?

Answers


After the first half-life, 1/2 is unchanged. After the 2nd one, 1/4 remains. After the 4th one, 1/16 remains. So you have 4 half-lives in 48 hours, the half-life is thus 12 hours.

Which formula is MgI2

Answers

Answer:

Magnesium iodide (MgI2)

Why should you cover the container during chromatography?

Answers

Typically the solvent used for the chromatography is rather volatile. So, its likely that the entire solvent will evaporate prior to the completion of the chromatography if the container isn't covered.
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