What is the name of the compound Al2(SO3)3?

Answers

Answer 1
Answer:

Answer:

Name: Aluminum Sulfite

Explanation:

Systematic nomenclature: dialuminium tris [trioxosulfate (IV)]

Oxoanions: anions derived from removing H + from an oxo acid with a vulgar name:

(SO3)3^-2 (sulfite)

Metal cation according to valence number:

Al (III) or Al+3 (as a cation) (Aluminum)

There are different types of salts, in this case we have a simple salt and the nomenclature for binary substances is used when only one class of cation and one class of anion are present

So:

Al2(SO3)3: Aluminum Sulfite

Answer 2
Answer:

Ions are charged particles that form when an atom (or group of atoms) receives or loses an electron, and ionic compounds are composed of these charged particles. An anion is a negatively charged ion, whereas a cation is a positively charged ion. Here Al₂(SO₃)₃ is aluminium sulfite.

Ionic compounds are defined as substances that are joined by ionic bonds. In order to reach their closest arrangement as a noble gas, elements can either gain or lose electrons. For the completion of the octet, ions are formed (either by gaining or losing electrons), which aids in their stabilization.

The name of the compound Al₂(SO₃)₃ is aluminium sulfite.

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How many significant figures are in 340500

Answers

Answer:

Five significant figures

Explanation:

You have to change the number to standard form

340500 = 3.405×10**5

** means raise to power

10**5

Where five represents the number of significant figures.

Answer:

4!

Explanation:

How many significant digits are in the volume measurement 0.100 L? (a) 1 (b) 2 (C) 3 (d) 4 (e) none of the above

Answers

C is the answer. The 1 and the two zeros behind the one are significant digits.

Final answer:

The volume measurement 0.100 L consists of 3 significant digits, counting the non-zero digit and the zero after the decimal point.

Explanation:

In the volume measurement 0.100 L, there are 3 significant figures. Significant figures represent the precision of a measured value. In this case, the zeroes after the decimal point are 'leading zeroes' which are not counted as significant. The '1' is a non-zero digit, which is always significant. And the zero after '1' is a 'trailing zero' that comes after a decimal point, so it is also counted as significant. Therefore, the number of significant figures in 0.100 L is 3.

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How many total atoms are in 3(SO)4

Answers

Answer:

17 atoms are in 3(SO)4

Explanation:

Final answer:

There are 15 total atoms in 3(SO)4.

Explanation:

To find the total number of atoms in a chemical formula like 3(SO)4, you need to multiply the subscripts (the numbers outside the parentheses) by the number of atoms represented by each element within the parentheses and then multiply that by the coefficient (the number outside the formula).

In this case, you have:

3(SO)4.

Now, let's break it down:

The subscript for sulfur (S) is 1.

The subscript for oxygen (O) is 4.

So, for each (SO4) unit, you have 1 sulfur atom and 4 oxygen atoms.

Now, multiply this by the coefficient of 3:

3(SO)4. = 3 * (1 sulfur atom + 4 oxygen atoms)

= 3 sulfur atoms + 12 oxygen atoms

So, in 3(SO)4., there are a total of 3 sulfur atoms and 12 oxygen atoms, for a combined total of 15 atoms.

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What do you mean by metallic bond?

Answers

Answer:

_________________________________________________

METALLIC BOND:

Metallic Bond is basically a electrostatic force of attraction between the metal ions which are arranged in a lattice(Lattice is a regular repeating pattern) and the free electrons floating around the metal ions.

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PROPERTIES OF METALLIC BOND:

1- Metals are good conductors of heat and electricity

2- Metals are ductile

3- Metals are malleable

4- Metals are solid at room temperature

5- Metals Possess Metallic luster

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Consider four elements from Group 7A: fluorine in the second period, chlorine in the third period, bromine in the fourth period, and iodine in the fifth period. Which element has the largest first ionization energy?

Answers

Out of the possible answers for this question, fluorine in the second period is correct. Of the four elements fluorine, chlorine, bromine and iodine, fluorine has the largest first ionization energy, with a Enthalpy number of 1681.0. Of all the elements, helium has the highest first ionization energy figure.

According to the quantum-mechanical model for the hydrogen atom, which electron transitions produces light with the longer wavelength: 2p→1s or 3p→1s?

Answers

Answer:2p→1s

Explanation:

Frequency is inversely proportional to wavelength. The higher the frequency, the shorter that wavelength. The smaller the frequency the longer the wavelength. The frequency of light associated with 2p→1s is less than the frequency of light associated with 3p→1s since the latter represents transition from a much higher energy level. It follows that the wavelength associated with the former will be longer since its frequency is lesser. This deduction follows from our argument about the inverse relationship between frequency and wavelength.